Determine f(0), f(1), f(2), f(3), f(4), e f(-1) das seguintes funções :A) f (x) = 2x+4B) f (x) = 3x+1C) f (x) = -2x+2C) f (x) = x-4E) f (x) = 3x-5

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1. \(\)\(\eqalign{ & f(x) = 2x + 4 \cr & f(0) = 2(0) + 4 = 4 \cr & f(1) = 2(1) + 4 = 6 \cr & f(2) = 2(2) + 4 = 8 \cr & f(3) = 2(3) + 4 = 10 \cr & f(4) = 2(4) + 4 = 12 \cr & f( - 1) = 2( - 1) + 4 = 2 \cr}\)
2. \(\)\(\eqalign{ & f(x) = 3x + 1 \cr & f(0) = 3(0) + 1 = 1 \cr & f(1) = 3(1) + 1 = 4 \cr & f(2) = 3(2) + 1 = 7 \cr & f(3) = 3(3) + 1 = 10 \cr & f(4) = 3(4) + 1 = 13 \cr & f( - 1) = 3( - 1) + 1 = - 2 \cr}\)
3. \(\)\(\eqalign{ & f(x) = - 2x + 2 \cr & f(0) = - 2(0) + 2 = 2 \cr & f(1) = - 2(1) + 2 = 0 \cr & f(2) = - 2(2) + 2 = - 2 \cr & f(3) = - 2(3) + 2 = - 4 \cr & f(4) = - 2(4) + 2 = - 6 \cr & f( - 1) = - 2( - 1) + 2 = 4 \cr}\)
4. \(\)\(\eqalign{ & f(x) = x - 4 \cr & f(0) = 0 - 4 = - 4 \cr & f(1) = 1 - 4 = - 3 \cr & f(2) = 2 - 4 = - 2 \cr & f(3) = 3 - 4 = - 1 \cr & f(4) = 4 - 4 = 0 \cr & f( - 1) = - 1 - 4 = - 5 \cr}\)
5. \(\)\(\eqalign{ & f(x) = 3x - 5 \cr & f(0) = 3(0) - 5 = - 5 \cr & f(1) = 3(1) - 5 = - 2 \cr & f(2) = 3(2) - 5 = 1 \cr & f(3) = 3(3) - 5 = 4 \cr & f(4) = 3(4) - 5 = 7 \cr & f( - 1) = 3( - 1) - 5 = - 8 \cr}\)

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Portanto, basta substituir os valores dados pelo x de cada equação.