URGENTE, preciso que me auxiliem com essas duas questões de física,?

1)

V0 = 6000 cm³

t = 10 °C

a = 8,0 x 10-6 °C-1

T = 110 °C

g = 3 a

g = 3 * 8,0 x 10-6 °C-1

g = 24,0 x 10-6 °C-1

V = V0 (1 + g (T - t)

V = 6000 [1 + 24,0 x 10-6 (110 - 10)]

v = 6000 ( 1 + 24,0 x 10-6 * 100)

V = 6000 (1 + 24,0 X 10-6 * 102)

V = 6000 (1 + 24,0 x 10-4)

V = 6000 (1 + 0,0024)

V = 6000 * 1,0024

V = 6014,4 cm³

2)

V0 = 2000 cm³

ΔT = 100 °C

ΔVap = 14 cm³

y = ?

ΔVap = V0 YΔT

14 = 2000 * y * 100

14 = 2 x105 y

2 x 105 y = 14

y = 14 / 2 x 105

y = 7 x 10-5 °C-1