<div id="pf1" class="pf w0 h0" data-page-no="1"><div class="pc pc1 w0 h0"><img class="bi x0 y0 w1 h1" alt="" src="https://files.passeidireto.com/1d953e05-2f10-49f7-9e84-23aa1b4bf702/bg1.png"><div class="t m0 x1 h2 y1 ff1 fs0 fc0 sc0 ls0 ws1">Hidr<span class="blank _0"></span>a<span class="blank _1"></span>\ue7b4<span class="blank _2"> </span>ulica e Hidrometria (17451) </div><div class="t m0 x1 h2 y2 ff1 fs0 fc0 sc0 ls0 ws1">GABARITO | Avaliação<span class="blank _3"> </span> Final (Discursiva) - Indivi<span class="blank _3"> </span>dual </div><div class="t m0 x1 h3 y3 ff1 fs1 fc1 sc0 ls0 ws1">Peso da Avaliação4,00 </div><div class="t m0 x1 h3 y4 ff1 fs1 fc1 sc0 ls0 ws1">Prova </div><div class="t m0 x1 h3 y5 ff1 fs1 fc1 sc0 ls0 ws1">Qtd. de Questões2 </div><div class="t m0 x1 h3 y6 ff1 fs1 fc1 sc0 ls0 ws1">Nota8,00 </div><div class="t m0 x1 h3 y7 ff2 fs1 fc1 sc0 ls0 ws0">1<span class="ff1 ws1"> </span></div><div class="t m0 x1 h3 y8 ff1 fs1 fc1 sc0 ls0 ws1">Existem dife<span class="blank _3"> </span>rentes tipos de regime de escoamento de <span class="blank _3"> </span>fluidos. O tipo de regime de escoamento<span class="blank _3"> </span> define as </div><div class="t m0 x1 h3 y9 ff1 fs1 fc1 sc0 ls0 ws1">condições do esc<span class="blank _3"> </span>oamento, pois o tipo de regime tem efeito sobre a distribuição de <span class="blank _3"> </span>pressão e de velocidade </div><div class="t m0 x1 h3 ya ff1 fs1 fc1 sc0 ls0 ws1">no meio de condução do fluido. Isso afeta<span class="blank _3"> </span> muito, dentre outras coisas, a potên<span class="blank _3"> </span>cia requerida para </div><div class="t m0 x1 h3 yb ff1 fs1 fc1 sc0 ls0 ws1">bombeamento desse fluido.<span class="ff3"> </span></div><div class="t m0 x1 h3 yc ff1 fs1 fc1 sc0 ls0 ws1">Considerando os tipo<span class="blank _3"> </span>s de regime de escoamento, a partir da figura a seguir, indique o<span class="blank _3"> </span>s tipos de regime de </div><div class="t m0 x1 h3 yd ff1 fs1 fc1 sc0 ls0 ws1">escoamento e as características d<span class="blank _3"> </span>e cada um. </div><div class="t m0 x1 h3 ye ff1 fs1 fc1 sc0 ls0 ws1"> </div><div class="t m0 x2 h3 yf ff1 fs1 fc1 sc0 ls0 ws1"> </div><div class="t m0 x1 h3 y10 ff2 fs1 fc1 sc0 ls0 ws1">Resposta esperada<span class="ff1"> </span></div><div class="t m0 x1 h3 y11 ff1 fs1 fc1 sc0 ls0 ws1">O <span class="blank _3"> </span>primeiro <span class="blank _3"> </span>caso <span class="blank _4"> </span>é <span class="blank _3"> </span>de <span class="blank _4"> </span>escoamento <span class="blank _3"> </span>em <span class="blank _3"> </span>regime <span class="blank _3"> </span>do <span class="blank _3"> </span>ti<span class="blank _3"> </span>po <span class="blank _3"> </span>laminar. <span class="blank _4"> </span>Nesse <span class="blank _3"> </span>tipo <span class="blank _3"> </span>de <span class="blank _4"> </span>regime, <span class="blank _3"> </span>o <span class="blank _3"> </span>escoamento <span class="blank _4"> </span>se <span class="blank _3"> </span>dá d<span class="blank _3"> </span>e </div><div class="t m0 x1 h3 y12 ff1 fs1 fc1 sc0 ls0 ws1">forma s<span class="blank _3"> </span>uave <span class="blank _3"> </span>e <span class="blank _4"> </span>ordenada.<span class="blank _3"> </span> <span class="blank _3"> </span>As <span class="blank _3"> </span>pa<span class="blank _3"> </span>rtículas <span class="blank _3"> </span>do <span class="blank _3"> </span>fluido <span class="blank _4"> </span>se <span class="blank _3"> </span>movem <span class="blank _4"> </span>de <span class="blank _3"> </span>forma <span class="blank _3"> </span>o<span class="blank _3"> </span>rdenad<span class="blank _3"> </span>a, <span class="blank _3"> </span>como <span class="blank _3"> </span>se <span class="blank _4"> </span>fossem <span class="blank _3"> </span>agrupadas </div><div class="t m0 x1 h3 y13 ff1 fs1 fc1 sc0 ls0 ws1">em <span class="blank"> </span>\u201clâminas <span class="blank"> </span>cilíndricas\u201d <span class="blank"> </span>deslizando <span class="blank"> </span>suaveme<span class="blank _0"></span>nte <span class="blank"> </span>sobre <span class="blank _5"> </span>a <span class="blank"> </span>outra. <span class="blank"> </span>Ess<span class="blank _0"></span>e <span class="blank"> </span>tipo <span class="blank"> </span>de <span class="blank _5"> </span>escoamento <span class="blank _5"> </span>acontece <span class="blank"> </span>em </div><div class="t m0 x1 h3 y14 ff1 fs1 fc1 sc0 ls0 ws1">velocidades muito<span class="blank _3"> </span> baixas, não sendo tão facilmente encontrado quanto o do último caso. </div><div class="t m0 x1 h3 y15 ff1 fs1 fc1 sc0 ls0 ws1"> </div><div class="t m0 x1 h3 y16 ff1 fs1 fc1 sc0 ls0 ws1"> </div><div class="t m0 x1 h3 y17 ff1 fs1 fc1 sc0 ls0 ws1">O caso do conduto mais abaixo é d<span class="blank _3"> </span>e regime do tipo turbulento. Nesse tipo de regime, as pa<span class="blank _3"> </span>rtículas do fluido </div><div class="t m0 x1 h3 y18 ff1 fs1 fc1 sc0 ls0 ws1">se movem de maneira desordenada e errática. Qu<span class="blank _0"></span>anto maior o grau de turbulência, maior a taxa de mistura </div><div class="t m0 x1 h3 y19 ff1 fs1 fc1 sc0 ls0 ws1">no <span class="blank _3"> </span>fluido e <span class="blank _4"> </span>menor a <span class="blank _3"> </span>es<span class="blank _3"> </span>tabilidade <span class="blank _3"> </span>do <span class="blank _3"> </span>escoamento. <span class="blank _3"> </span>Esse <span class="blank _3"> </span>tipo <span class="blank _3"> </span>de <span class="blank _3"> </span>regime <span class="blank _3"> </span>de <span class="blank _3"> </span>escoamento <span class="blank _3"> </span>é <span class="blank _3"> </span>comum <span class="blank _3"> </span>para <span class="blank _3"> </span>fluidos </div><div class="t m0 x1 h3 y1a ff1 fs1 fc1 sc0 ls0 ws1">de baix<span class="blank _3"> </span>a viscosidade, como o ar, por exemplo. </div><div class="t m0 x1 h3 y1b ff1 fs1 fc1 sc0 ls0 ws1"> </div><div class="t m0 x1 h3 y1c ff1 fs1 fc1 sc0 ls0 ws1"> </div><div class="t m0 x1 h3 y1d ff1 fs1 fc1 sc0 ls0 ws1">Em <span class="blank _4"> </span>si<span class="blank _3"> </span>tuação <span class="blank _6"> </span>intermediária, <span class="blank _6"> </span>es<span class="blank _3"> </span>tá <span class="blank _4"> </span>o <span class="blank _6"> </span>caso <span class="blank _6"> </span>d<span class="blank _3"> </span>o <span class="blank _4"> </span>cond<span class="blank _3"> </span>uto <span class="blank _6"> </span>do <span class="blank _6"> </span>meio <span class="blank _6"> </span>em <span class="blank _6"> </span>que <span class="blank _6"> </span>o <span class="blank _4"> </span>esco<span class="blank _3"> </span>amento <span class="blank _4"> </span>é <span class="blank _7"> </span>dito <span class="blank _6"> </span>transitório. <span class="blank _6"> </span>Esse </div><div class="t m0 x1 h3 y1e ff1 fs1 fc1 sc0 ls0 ws1">tipo <span class="blank _3"> </span>d<span class="blank _3"> </span>e <span class="blank _3"> </span>regime <span class="blank _3"> </span>é <span class="blank _4"> </span>de <span class="blank _3"> </span>transição <span class="blank _3"> </span>en<span class="blank _3"> </span>tre <span class="blank _3"> </span>o <span class="blank _3"> </span>laminar<span class="blank _3"> </span> <span class="blank _3"> </span>e <span class="blank _3"> </span>o <span class="blank _3"> </span>turbulento<span class="blank _3"> </span>, <span class="blank _3"> </span>sendo <span class="blank _4"> </span>a <span class="blank _3"> </span>principal <span class="blank _3"> </span>caracter<span class="blank _3"> </span>ística <span class="blank _3"> </span>o <span class="blank _3"> </span>regime <span class="blank _4"> </span>não </div><div class="t m0 x1 h3 y1f ff1 fs1 fc1 sc0 ls0 ws1">ser estável. Esse <span class="blank _0"></span>tipo de <span class="blank _0"></span>regime deve ser <span class="blank _0"></span>evitado, pois <span class="blank _0"></span>é mais <span class="blank _0"></span>difícil de se <span class="blank _0"></span>saber ou control<span class="blank _0"></span>ar as condições <span class="blank _0"></span>do </div><div class="t m0 x1 h3 y20 ff1 fs1 fc1 sc0 ls0 ws1">escoamento, como, por exemplo, <span class="blank _3"> </span>as condições de pressão do escoamento. </div></div><div class="pi" data-data="{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}"></div></div> <div id="pf2" class="pf w0 h0" data-page-no="2"><div class="pc pc2 w0 h0"><img class="bi x0 y21 w1 h4" alt="" src="https://files.passeidireto.com/1d953e05-2f10-49f7-9e84-23aa1b4bf702/bg2.png"><div class="t m0 x1 h3 y22 ff1 fs1 fc1 sc0 ls0 ws1"> </div><div class="t m0 x1 h3 y23 ff2 fs1 fc1 sc0 ls0 ws1">Minha resposta<span class="ff1"> </span></div><div class="t m0 x1 h3 y3 ff1 fs1 fc1 sc0 ls0 ws1">Os três principai<span class="blank _3"> </span>s regimes de <span class="blank _3"> </span>escoamento de fluidos:<span class="blank _3"> </span> 1. LAMINAR: O fluido <span class="blank _3"> </span>se move de maneira ordenad<span class="blank _3"> </span>a e </div><div class="t m0 x1 h3 y4 ff1 fs1 fc1 sc0 ls0 ws1">suave, <span class="blank _8"> </span>com <span class="blank _8"> </span>partículas <span class="blank _8"> </span>fluindo <span class="blank _8"> </span>em <span class="blank _8"> </span>camadas <span class="blank _8"> </span>paralelas; <span class="blank _8"> </span>Velocidade <span class="blank _8"> </span>constante <span class="blank _8"> </span>em <span class="blank _8"> </span>cada <span class="blank _8"> </span>ponto <span class="blank _8"> </span>do <span class="blank _8"> </span>flux<span class="blank _0"></span>o; </div><div class="t m0 x1 h3 y24 ff1 fs1 fc1 sc0 ls0 ws1">Distribuição <span class="blank _4"> </span>de <span class="blank _4"> </span>pressão <span class="blank _4"> </span>uniforme <span class="blank _4"> </span>e <span class="blank _4"> </span>previsível; <span class="blank _4"> </span>Baixo <span class="blank _4"> </span>número <span class="blank _4"> </span>de <span class="blank _4"> </span>Reynolds <span class="blank _4"> </span>(geralmente <span class="blank _4"> </span>abaixo <span class="blank _4"> </span>de <span class="blank _4"> </span>2000); <span class="blank _3"> </span>e </div><div class="t m0 x1 h3 y25 ff1 fs1 fc1 sc0 ls0 ws1">requer <span class="blank _2"> </span>menos<span class="blank _3"> </span> <span class="blank _2"> </span>ener<span class="blank _3"> </span>gia <span class="blank _2"> </span>para <span class="blank _5"> </span>o <span class="blank _2"> </span>bo<span class="blank _3"> </span>mbeamento <span class="blank _2"> </span>e <span class="blank _5"> </span>é <span class="blank _2"> </span>facilmente <span class="blank"> </span>controlado. <span class="blank _2"> </span>2. <span class="blank _5"> </span>TRANSITÓRIO: <span class="blank _2"> </span>Uma <span class="blank _5"> </span>fase <span class="blank _2"> </span>d<span class="blank _3"> </span>e </div><div class="t m0 x1 h3 y26 ff1 fs1 fc1 sc0 ls0 ws1">transição <span class="blank _9"> </span>entre <span class="blank _9"> </span>laminar <span class="blank _7"> </span>e <span class="blank _9"> </span>tu<span class="blank _3"> </span>rbulenta; <span class="blank _7"> </span>P<span class="blank _3"> </span>adrões <span class="blank _9"> </span>de <span class="blank _9"> </span>fluxo <span class="blank _7"> </span>in<span class="blank _3"> </span>stáveis <span class="blank _9"> </span>à <span class="blank _9"> </span>medida <span class="blank _9"> </span>que <span class="blank _9"> </span>a <span class="blank _9"> </span>velocidade <span class="blank _9"> </span>aumenta; <span class="blank _9"> </span>O </div><div class="t m0 x1 h3 y27 ff1 fs1 fc1 sc0 ls0 ws1">fluido <span class="blank _0"></span>pode a<span class="blank _0"></span>presentar <span class="blank _0"></span>turbilhões <span class="blank _0"></span>temporários; <span class="blank _0"></span>e <span class="blank _0"></span>Núme<span class="blank _0"></span>ro <span class="blank _0"></span>de <span class="blank _0"></span>Reynolds <span class="blank _0"></span>na <span class="blank _0"></span>faixa <span class="blank _a"></span>interativa (gera<span class="blank _0"></span>lmente <span class="blank _a"></span>entr<span class="blank _3"> </span>e </div><div class="t m0 x1 h3 y28 ff1 fs1 fc1 sc0 ls0 ws1">2000 <span class="blank _3"> </span>e <span class="blank _4"> </span>4000) <span class="blank _3"> </span>quand<span class="blank _3"> </span>o <span class="blank _3"> </span>em <span class="blank _4"> </span>transição. <span class="blank _3"> </span>3. <span class="blank _4"> </span>TURBULENTO: <span class="blank _3"> </span>O <span class="blank _4"> </span>fluido <span class="blank _3"> </span>s<span class="blank _3"> </span>e <span class="blank _4"> </span>move <span class="blank _3"> </span>de <span class="blank _3"> </span>forma <span class="blank _3"> </span>c<span class="blank _3"> </span>aótica, <span class="blank _4"> </span>com <span class="blank _3"> </span>turbilhões <span class="blank _3"> </span>e </div><div class="t m0 x1 h3 y29 ff1 fs1 fc1 sc0 ls0 ws1">vórtices; <span class="blank _b"> </span>Partículas <span class="blank _b"> </span>do <span class="blank _b"> </span>fluid<span class="blank _3"> </span>o <span class="blank _b"> </span>se <span class="blank _b"> </span>misturam <span class="blank _b"> </span>inten<span class="blank _3"> </span>samente <span class="blank _b"> </span>em <span class="blank _b"> </span>todas <span class="blank _b"> </span>as <span class="blank _b"> </span>direções; <span class="blank _c"> </span>A <span class="blank _b"> </span>velocidade <span class="blank _b"> </span>varia </div><div class="t m0 x1 h3 y2a ff1 fs1 fc1 sc0 ls0 ws1">significativamente <span class="blank _b"> </span>em <span class="blank _b"> </span>dif<span class="blank _3"> </span>erentes <span class="blank _b"> </span>pontos <span class="blank _b"> </span>e <span class="blank _b"> </span>ao <span class="blank _b"> </span>longo <span class="blank _b"> </span>do <span class="blank _b"> </span>tempo; <span class="blank _b"> </span>Distribuição <span class="blank _b"> </span>de <span class="blank _b"> </span>pressão <span class="blank _b"> </span>irregular <span class="blank _b"> </span>e </div><div class="t m0 x1 h3 y2b ff1 fs1 fc1 sc0 ls0 ws1">imprevisível; <span class="blank _b"> </span>Alto <span class="blank _b"> </span>número <span class="blank _b"> </span>de <span class="blank _b"> </span>Reynold<span class="blank _3"> </span>s <span class="blank _b"> </span>(geralmente <span class="blank _b"> </span>acima <span class="blank _b"> </span>de <span class="blank _b"> </span>4000); <span class="blank _b"> </span>e <span class="blank _b"> </span>exige <span class="blank _b"> </span>mais <span class="blank _b"> </span>energia <span class="blank _b"> </span>para <span class="blank _b"> </span>o </div><div class="t m0 x1 h3 y2c ff1 fs1 fc1 sc0 ls0 ws1">bombeamento <span class="blank"> </span>causando <span class="blank"> </span>mais <span class="blank"> </span>desgaste <span class="blank _5"> </span>em <span class="blank"> </span>tubulações <span class="blank _5"> </span>e <span class="blank"> </span>equipamentos. <span class="blank"> </span>A <span class="blank _5"> </span>determinação <span class="blank"> </span>do <span class="blank"> </span>regime <span class="blank _5"> </span>de </div><div class="t m0 x1 h3 y2d ff1 fs1 fc1 sc0 ls0 ws1">escoamento é essencial para <span class="blank _a"></span>compreen<span class="blank _3"> </span>der como <span class="blank _a"></span>os fluidos se comportam em <span class="blank _a"></span>sis<span class="blank _3"> </span>temas de t<span class="blank _0"></span>ransporte e par<span class="blank _0"></span>a </div><div class="t m0 x1 h3 y2e ff1 fs1 fc1 sc0 ls0 ws1">garantir <span class="blank _4"> </span>a <span class="blank _6"> </span>eficiência <span class="blank _4"> </span>e <span class="blank _6"> </span>a <span class="blank _4"> </span>confiabilidade <span class="blank _4"> </span>d<span class="blank _3"> </span>esses <span class="blank _4"> </span>sistemas.<span class="blank _3"> </span> <span class="blank _4"> </span>O <span class="blank _4"> </span>número <span class="blank _4"> </span>de <span class="blank _4"> </span>Reyn<span class="blank _3"> </span>olds <span class="blank _4"> </span>(R <span class="blank _4"> </span>e)<span class="blank _3"> </span> <span class="blank _4"> </span>é <span class="blank _4"> </span>uma <span class="blank _4"> </span>medid<span class="blank _3"> </span>a-chave </div><div class="t m0 x1 h3 y2f ff1 fs1 fc1 sc0 ls0 ws1">para <span class="blank _2"> </span>prever <span class="blank _2"> </span>o <span class="blank _2"> </span>tipo <span class="blank _9"> </span>d<span class="blank _3"> </span>e <span class="blank _9"> </span>regime <span class="blank _2"> </span>de <span class="blank _2"> </span>escoamento <span class="blank _2"> </span>e, <span class="blank _2"> </span>consequentemente, <span class="blank _2"> </span>para <span class="blank _2"> </span>projetar <span class="blank _2"> </span>e <span class="blank _9"> </span>ope<span class="blank _3"> </span>rar <span class="blank _2"> </span>sistemas <span class="blank _9"> </span>de </div><div class="t m0 x1 h3 y30 ff1 fs1 fc1 sc0 ls0 ws1">maneira <span class="blank _a"></span>adequada. <span class="blank _a"></span>Com <span class="blank _a"></span>valores <span class="blank _a"></span>baixos <span class="blank _a"></span>diminuem <span class="blank _a"></span>fluxo <span class="blank _a"></span>laminar, <span class="blank _a"></span>valores <span class="blank _a"></span>intermediários <span class="blank _a"></span>diminuem <span class="blank _a"></span>transição </div><div class="t m0 x1 h3 y31 ff1 fs1 fc1 sc0 ls0 ws1">e valores altos diminuem o fluxo turbulento. </div><div class="t m0 x1 h3 y32 ff1 fs1 fc1 sc0 ls0 ws1"> </div><div class="t m0 x1 h3 y33 ff2 fs1 fc1 sc0 ls0 ws1">Retorno da correção<span class="ff1"> </span></div><div class="t m0 x1 h3 y34 ff1 fs1 fc1 sc0 ls0 ws1">Parabéns, <span class="blank _b"> </span>acadêmico, <span class="blank _d"> </span>sua <span class="blank _d"> </span>respo<span class="blank _3"> </span>sta <span class="blank _d"> </span>at<span class="blank _3"> </span>ingiu <span class="blank _d"> </span>os <span class="blank _b"> </span>objetivos <span class="blank _d"> </span>da <span class="blank _b"> </span>questão <span class="blank _d"> </span>e <span class="blank _b"> </span>você <span class="blank _d"> </span>contemplou <span class="blank _b"> </span>o <span class="blank _d"> </span>espe<span class="blank _3"> </span>rado, </div><div class="t m0 x1 h3 y35 ff1 fs1 fc1 sc0 ls0 ws1">demonstrando <span class="blank _e"> </span>a <span class="blank _e"> </span>competência <span class="blank _f"> </span>da <span class="blank _e"> </span>análise <span class="blank _f"> </span>e <span class="blank _f"> </span>sín<span class="blank _3"> </span>tese <span class="blank _f"> </span>d<span class="blank _3"> </span>o <span class="blank _f"> </span>assunto <span class="blank _e"> </span>abordado, <span class="blank _f"> </span>apr<span class="blank _3"> </span>esentando <span class="blank _f"> </span>excelentes </div><div class="t m0 x1 h3 y36 ff1 fs1 fc1 sc0 ls0 ws1">argumentos próprios, com base nos mate<span class="blank _3"> </span>riais disponibilizados. </div><div class="t m0 x1 h3 y37 ff1 fs1 fc1 sc0 ls0 ws1"> </div><div class="t m0 x1 h5 y38 ff2 fs1 fc1 sc0 ls0 ws0">2<span class="ff3 ws1"> </span></div><div class="t m0 x1 h3 y39 ff1 fs1 fc1 sc0 ls0 ws1">Estações elevató<span class="blank _3"> </span>rias são unidades responsáveis por adicion<span class="blank _3"> </span>ar energia (ou \u201ccarga\u201d) ao escoamento, a fim de </div><div class="t m0 x1 h3 y3a ff1 fs1 fc1 sc0 ls0 ws1">que o fluido chegue ao pont<span class="blank _3"> </span>o de destino em condições de pr<span class="blank _3"> </span>essão e vazão pretendidas. Em sistemas de </div><div class="t m0 x1 h3 y3b ff1 fs1 fc1 sc0 ls0 ws1">abastecimento de <span class="blank _3"> </span>água, isso significa chegar à torneira do consumidor fina<span class="blank _3"> </span>l em condições de pressão e </div><div class="t m0 x1 h3 y3c ff1 fs1 fc1 sc0 ls0 ws1">vazão adequadas, bem<span class="blank _3"> </span> como com qualidade para uso. No planejamento de est<span class="blank _3"> </span>ações elevatórias, o poço de </div><div class="t m0 x1 h3 y3d ff1 fs1 fc1 sc0 ls0 ws1">sucção é uma das partes que requer d<span class="blank _3"> </span>imensionamento e para o qu<span class="blank _3"> </span>al se deve considerar a altura </div><div class="t m0 x1 h3 y3e ff1 fs1 fc1 sc0 ls0 ws1">manométrica máxima de sucção d<span class="blank _3"> </span>a bomba. Nesse sentido, a NPSH (em inglês, <span class="ff4">Net Positi<span class="blank _3"> </span>ve Suction Head</span>) </div><div class="t m0 x1 h3 y3f ff1 fs1 fc1 sc0 ls0 ws1">disponível <span class="blank _3"> </span>é uma característica das instalações de sucção, sendo a ener<span class="blank _3"> </span>gia disponível para que o líquido </div><div class="t m0 x1 h3 y40 ff1 fs1 fc1 sc0 ls0 ws1">consiga alcançar as pá<span class="blank _3"> </span>s do rotor da bomba. Em uma situação em que se deseja bombear<span class="blank _3"> </span> uma vazão de 30 </div><div class="t m0 x1 h3 y41 ff1 fs1 fc1 sc0 ls0 ws1">m³/h, send<span class="blank _3"> </span>o o NPSH requerido da bomba de 2,50 m, a pressão atmosférica é <span class="blank _3"> </span>igual à 9,42 mH<span class="fs2 ls1 v1">2</span>O, a pressão </div><div class="t m0 x1 h3 y42 ff1 fs1 fc1 sc0 ls0 ws1">de vapor é igual à 0,34 mH<span class="fs2 ls2 v1">2</span>O e as cotas d<span class="blank _3"> </span>e eixo da bomba e do nível do<span class="blank _3"> </span> reservatório de sucção são iguais à </div><div class="t m0 x1 h3 y43 ff1 fs1 fc1 sc0 ls0 ws1">834,50 m e 833,10 m, respecti<span class="blank _3"> </span>vamente.<span class="ff3"> </span></div><div class="t m0 x1 h3 y44 ff1 fs1 fc1 sc0 ls0 ws1">Considerando que, na tubulação de sucção, <span class="blank _3"> </span>existe um joelho de 90° e uma válvula de pé com crivo (perd<span class="blank _3"> </span>a </div><div class="t m0 x1 h3 y45 ff1 fs1 fc1 sc0 ls0 ws1">de carga localizada tot<span class="blank _3"> </span>al igual à 1,48 m), bem como que a perda de carga distr<span class="blank _3"> </span>ibuída é de apenas 0,4 m, </div><div class="t m0 x1 h3 y46 ff1 fs1 fc1 sc0 ls0 ws1">calcule o NPSH disponível para sucção e verif<span class="blank _3"> </span>ique se a bomba <span class="blank _3"> </span>realizará a sucção. </div><div class="t m0 x1 h3 y47 ff2 fs1 fc1 sc0 ls0 ws1">Resposta esperada<span class="ff1"> </span></div><div class="t m0 x1 h3 y48 ff1 fs1 fc1 sc0 ls0 ws0">h<span class="fs2 ws2 v1">f</span><span class="ws1">=1,48+0,40=1,88 m </span></div><div class="t m0 x1 h3 y49 ff1 fs1 fc1 sc0 ls0 ws0">NPSH<span class="fs2 ws3 v1">disponível</span>=H+(p<span class="fs2 ws2 v1">a</span>-p<span class="fs2 ws2 v1">v</span>)/\u03b3×10-h<span class="fs2 ls3 v1">f</span><span class="ws1"> </span></div><div class="t m0 x1 h3 y4a ff1 fs1 fc1 sc0 ls0 ws0">NPSH<span class="fs2 ws3 v1">disponível</span><span class="ws1">=834,50 - 833,10 + 9,42 - 0,34*10-1,88<span class="blank _3"> </span> </span></div><div class="t m0 x1 h3 y4b ff1 fs1 fc1 sc0 ls0 ws0">NPSH<span class="fs2 ws3 v1">disponível</span><span class="ws1">=1,4 + 9,42 - 3,4 - 1,88 </span></div><div class="t m0 x1 h3 y4c ff1 fs1 fc1 sc0 ls0 ws0">NPSH<span class="fs2 ws3 v1">disponível</span><span class="ws1">=5,54 m </span></div><div class="t m0 x1 h3 y4d ff1 fs1 fc1 sc0 ls0 ws1"> </div><div class="t m0 x1 h3 y4e ff1 fs1 fc1 sc0 ls0 ws1">Verificando se a bomba realizará a sucção, te<span class="blank _3"> </span>mos: </div></div><div class="pi" data-data="{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}"></div></div> <div id="pf3" class="pf w0 h0" data-page-no="3"><div class="pc pc3 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x0 y4f w1 h6" alt="" src="https://files.passeidireto.com/1d953e05-2f10-49f7-9e84-23aa1b4bf702/bg3.png"><div class="t m0 x1 h3 y22 ff1 fs1 fc1 sc0 ls0 ws1"> </div><div class="t m0 x1 h3 y23 ff1 fs1 fc1 sc0 ls0 ws0">NPSH<span class="fs2 ws1 v1">disponível </span><span class="ws1">\u2265 NPSH<span class="fs2 ws2 v1">r<span class="blank _3"> </span>equerido</span> </span></div><div class="t m0 x1 h3 y3 ff1 fs1 fc1 sc0 ls0 ws1">5,54 \u2265 2,50 m </div><div class="t m0 x1 h3 y24 ff1 fs1 fc1 sc0 ls0 ws1">A bomba terá energia suficien<span class="blank _3"> </span>te para realizar a sucção. </div><div class="t m0 x1 h3 y50 ff2 fs1 fc1 sc0 ls0 ws1">Minha resposta<span class="ff1"> </span></div><div class="t m0 x1 h3 y51 ff1 fs1 fc1 sc0 ls0 ws1">Para se <span class="blank _3"> </span>obter o <span class="blank _3"> </span>NPSH disponível (NPSHd), <span class="blank _3"> </span>será necessário <span class="blank _3"> </span>considerar alguns parâmet<span class="blank _3"> </span>ros e <span class="blank _3"> </span>perdas de car<span class="blank _3"> </span>ga<span class="blank _a"></span> </div><div class="t m0 x1 h3 y52 ff1 fs1 fc1 sc0 ls0 ws1">ao longo <span class="blank _a"></span>da tubulação <span class="blank _0"></span>de <span class="blank _a"></span>suc<span class="blank _3"> </span>ção. O <span class="blank _a"></span>NPSH disponível <span class="blank _0"></span>deve ser <span class="blank _a"></span>maior do <span class="blank _a"></span>q<span class="blank _3"> </span>ue o <span class="blank _a"></span>NPSH exigido <span class="blank _a"></span>pe<span class="blank _3"> </span>la <span class="blank _0"></span>bomba para<span class="blank _0"></span> </div><div class="t m0 x1 h3 y53 ff1 fs1 fc1 sc0 ls0 ws1">evitar <span class="blank _6"> </span>a <span class="blank _4"> </span>cav<span class="blank _3"> </span>itação. <span class="blank _6"> </span>A <span class="blank _6"> </span>fórmula <span class="blank _4"> </span>geral <span class="blank _4"> </span>pa<span class="blank _3"> </span>ra <span class="blank _4"> </span>o <span class="blank _6"> </span>cálculo <span class="blank _6"> </span>do <span class="blank _6"> </span>NPSH <span class="blank _6"> </span>disponível <span class="blank _6"> </span>é: <span class="blank _6"> </span>NPS <span class="blank _6"> </span>Hdisponível <span class="blank _6"> </span>= <span class="blank _4"> </span>ht <span class="blank _6"> </span>(total<span class="blank _3"> </span>) <span class="blank _4"> </span>- <span class="blank _6"> </span>hv </div><div class="t m0 x1 h3 y54 ff1 fs1 fc1 sc0 ls0 ws1">(vapor) <span class="blank _6"> </span>- <span class="blank _6"> </span>hp <span class="blank _6"> </span>(pe<span class="blank _3"> </span>rda) <span class="blank _6"> </span>Ond<span class="blank _3"> </span>e: <span class="blank _6"> </span>htotal <span class="blank _6"> </span>- <span class="blank _7"> </span>é <span class="blank _6"> </span>a <span class="blank _6"> </span>altura <span class="blank _6"> </span>man<span class="blank _3"> </span>ométrica <span class="blank _6"> </span>total <span class="blank _7"> </span>na <span class="blank _6"> </span>sucção; <span class="blank _6"> </span>hvapor <span class="blank _7"> </span>- <span class="blank _6"> </span>é <span class="blank _6"> </span>a <span class="blank _6"> </span>pr<span class="blank _3"> </span>essão <span class="blank _6"> </span>d<span class="blank _3"> </span>e <span class="blank _6"> </span>vpor </div><div class="t m0 x1 h3 y55 ff1 fs1 fc1 sc0 ls0 ws1">convertida em altura<span class="blank _0"></span> manométrica, hperda - <span class="blank _a"></span>é a soma <span class="blank _0"></span>das perdas <span class="blank _a"></span>d<span class="blank _3"> </span>e ca<span class="blank _a"></span>rga localizadas e distribuídas. Vamo<span class="blank _a"></span>s </div><div class="t m0 x1 h3 y56 ff1 fs1 fc1 sc0 ls0 ws1">calcular <span class="blank _4"> </span>cada <span class="blank _6"> </span>um <span class="blank _4"> </span>desses <span class="blank _4"> </span>ter<span class="blank _3"> </span>mos: <span class="blank _4"> </span>1. <span class="blank _4"> </span>ALTURA <span class="blank _6"> </span>MANOMÉTRICA <span class="blank _4"> </span>TOTAL <span class="blank _4"> </span>(<span class="blank _3"> </span>htotal): <span class="blank _4"> </span>- <span class="blank _6"> </span>A <span class="blank _4"> </span>altura <span class="blank _4"> </span>do<span class="blank _3"> </span> <span class="blank _4"> </span>eixo <span class="blank _4"> </span>da <span class="blank _6"> </span>bomba<span class="blank _0"></span> </div><div class="t m0 x1 h3 y57 ff1 fs1 fc1 sc0 ls0 ws1">até o nível do reservatório é de <span class="blank _3"> </span>834,50 m - 833,10 m = 1,<span class="blank _0"></span>40 m. - A pressão atmosférica é ig<span class="blank _3"> </span>ual a 9,42 mH2O.<span class="blank _0"></span> </div><div class="t m0 x1 h3 y58 ff1 fs1 fc1 sc0 ls0 ws1">Portanto, <span class="blank _3"> </span>htotal <span class="blank _3"> </span>= <span class="blank _3"> </span>1,40 m <span class="blank _3"> </span>+ <span class="blank _3"> </span>9,42 <span class="blank _3"> </span>mH2O <span class="blank _3"> </span>= <span class="blank _3"> </span>10,82 <span class="blank _3"> </span>m. <span class="blank _3"> </span>2. <span class="blank _3"> </span>PRESSÃO <span class="blank _3"> </span>DE VAP<span class="blank _3"> </span>OR (hvapor):<span class="blank _3"> </span> - <span class="blank _3"> </span>A <span class="blank _3"> </span>pressã<span class="blank _3"> </span>o d<span class="blank _3"> </span>o <span class="blank _3"> </span>vapor é </div><div class="t m0 x1 h3 y59 ff1 fs1 fc1 sc0 ls0 ws1">igual <span class="blank _a"></span>a 0,34 <span class="blank _a"></span>mH2O. 3. <span class="blank _a"></span>PERD<span class="blank _3"> </span>AS <span class="blank _a"></span>DE CA<span class="blank _a"></span>RG<span class="blank _3"> </span>A: - <span class="blank _a"></span>Temos <span class="blank _a"></span>um<span class="blank _3"> </span> <span class="blank _a"></span>joe<span class="blank _3"> </span>lho <span class="blank _a"></span>de 90º, <span class="blank _a"></span>qu<span class="blank _3"> </span>e <span class="blank _a"></span>adi<span class="blank _3"> </span>ciona perda <span class="blank _a"></span>de ca<span class="blank _a"></span>rga localizada. </div><div class="t m0 x1 h3 y5a ff1 fs1 fc1 sc0 ls0 ws1">- Tempos uma<span class="blank _a"></span> válvula de pé com crivo<span class="blank _a"></span>, que<span class="blank _3"> </span> também co<span class="blank _a"></span>nt<span class="blank _3"> </span>ribui para a <span class="blank _a"></span>perda de carga localizada. <span class="blank _a"></span>- A perda de </div><div class="t m0 x1 h3 y5b ff1 fs1 fc1 sc0 ls0 ws1">carga dis<span class="blank _3"> </span>tribuída <span class="blank _3"> </span>é <span class="blank _3"> </span>de <span class="blank _3"> </span>0,4<span class="blank _3"> </span> m. <span class="blank _3"> </span>Po<span class="blank _3"> </span>rtanto, hpe<span class="blank _3"> </span>rda <span class="blank _3"> </span>= <span class="blank _3"> </span>1,48 <span class="blank _3"> </span>m <span class="blank _3"> </span>+ <span class="blank _3"> </span>0,4 <span class="blank _3"> </span>m <span class="blank _3"> </span>= <span class="blank _3"> </span>1,88<span class="blank _3"> </span> <span class="blank _3"> </span>m. Ago<span class="blank _3"> </span>ra, <span class="blank _3"> </span>podemos <span class="blank _3"> </span>calcular <span class="blank _3"> </span>o <span class="blank _3"> </span>NPSH </div><div class="t m0 x1 h3 y5c ff1 fs1 fc1 sc0 ls0 ws1">disponível (NPSHd): NPSHd<span class="blank _3"> </span> = <span class="blank _a"></span>10,82 m - 0,34 mH2O - 1,88 m =<span class="blank _a"></span> 8,6<span class="blank _3"> </span>0 <span class="blank _0"></span>m O NPSH disponível<span class="blank _3"> </span> é <span class="blank _0"></span>de 8,60 m, <span class="blank _a"></span>o<span class="blank _3"> </span> que </div><div class="t m0 x1 h3 y5d ff1 fs1 fc1 sc0 ls0 ws1">é <span class="blank _a"></span>maior <span class="blank _a"></span>do <span class="blank _0"></span>que <span class="blank _a"></span>o <span class="blank _a"></span>NPSH <span class="blank _a"></span>exigido <span class="blank _a"></span>da <span class="blank _0"></span>bomba, <span class="blank _a"></span>que <span class="blank _a"></span>é <span class="blank _a"></span>de <span class="blank _a"></span>2,5<span class="blank _3"> </span>0 <span class="blank _a"></span>m. <span class="blank _a"></span>Portanto, <span class="blank _a"></span>uma <span class="blank _a"></span>bomba <span class="blank _a"></span>co<span class="blank _3"> </span>nsiguirá <span class="blank _a"></span>realizar <span class="blank _a"></span>a <span class="blank _a"></span>sucção </div><div class="t m0 x1 h3 y5e ff1 fs1 fc1 sc0 ls0 ws1">sem problemas, d<span class="blank _3"> </span>evido o NPSH disponível ser suficiente para evitar a cavitação<span class="blank _3"> </span>. </div><div class="t m0 x1 h3 y5f ff1 fs1 fc1 sc0 ls0 ws1"> </div><div class="t m0 x3 h3 y60 ff1 fs1 fc1 sc0 ls0 ws1"> </div><div class="t m0 x1 h3 y61 ff1 fs3 fc1 sc0 ls0 ws4">resposta_questnuo_2_discursiva.pdf<span class="fs4 ws1">Clique para baix<span class="blank _3"> </span>ar sua resposta<span class="blank _3"> </span><span class="fs1"> </span></span></div><div class="t m0 x1 h3 y62 ff1 fs1 fc1 sc0 ls0 ws1"> </div><div class="t m0 x1 h3 y63 ff2 fs1 fc1 sc0 ls0 ws1">Retorno da correção<span class="ff1"> </span></div><div class="t m0 x1 h3 y64 ff1 fs1 fc1 sc0 ls0 ws1">Prezado acadêmico, sua <span class="blank _a"></span>respo<span class="blank _3"> </span>sta foi parcial. Fal<span class="blank _a"></span>to<span class="blank _3"> </span>u argum<span class="blank _a"></span>en<span class="blank _3"> </span>tação suficiente para contemplar a<span class="blank _a"></span>s discussõ<span class="blank _3"> </span>es </div><div class="t m0 x1 h3 y65 ff1 fs1 fc1 sc0 ls0 ws1">do conteúdo da questã<span class="blank _3"> </span>o. Aprofunde mais seus estudos e explore os materiais in<span class="blank _3"> </span>dicados da trilha. </div><div class="t m0 x1 h3 y66 ff1 fs1 fc1 sc0 ls0 ws1"> </div></div><div class="pi" data-data="{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}"></div></div>
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