<div id="pf1" class="pf w0 h0" data-page-no="1"><div class="pc pc1 w0 h0"><img class="bi x0 y0 w1 h1" alt="" src="https://files.passeidireto.com/6ccd0e70-466b-42b0-aeb8-73a512191ddb/bg1.png"><div class="c x0 y1 w2 h2"><div class="t m0 x1 h3 y2 ff1 fs0 fc0 sc0 ls0 ws1">V<span class="blank _0"></span>ocê <span class="blank _1"> </span>pro<span class="blank _2"></span>va<span class="blank _2"></span>velment<span class="blank _2"></span>e <span class="blank _1"> </span>deve <span class="blank _1"> </span>ouvir <span class="blank _1"> </span>essa <span class="blank _1"> </span>palavra <span class="blank _1"> </span>quase <span class="blank _1"> </span>todo <span class="blank _1"> </span>dia: <span class="blank _1"> </span>porcentagem. <span class="blank _1"> </span>Ela</div><div class="t m0 x1 h3 y3 ff1 fs0 fc0 sc0 ls0 ws1">origina-se do <span class="blank _3"> </span>latim <span class="ff2">per centum</span>, <span class="blank _3"> </span>que <span class="blank _3"> </span>signi\ue67dca por <span class="blank _3"> </span>cem ou <span class="blank _3"> </span>\u201c<span class="blank _3"> </span>por cento\u201d<span class="blank _2"></span>, <span class="blank _3"> </span>ou seja, <span class="blank _3"> </span>é <span class="blank _3"> </span>uma</div><div class="t m0 x1 h3 y4 ff1 fs0 fc0 sc0 ls0 ws1">razão <span class="blank _3"> </span>cujo <span class="blank _3"> </span>denominador <span class="blank _4"> </span>é <span class="blank _3"> </span>100. <span class="blank _3"> </span>Usamos <span class="blank _4"> </span>o <span class="blank _3"> </span>símbolo <span class="blank _3"> </span>% <span class="blank _4"> </span>para <span class="blank _3"> </span>repr<span class="blank _2"></span>esentar <span class="blank _3"> </span>porcentagem,</div><div class="t m0 x1 h3 y5 ff1 fs0 fc0 sc0 ls0 ws1">assim <span class="blank _5"> </span>quando <span class="blank _5"> </span>dizemos <span class="blank _5"> </span>x% <span class="blank _5"> </span>estamos <span class="blank _5"> </span>indicando <span class="blank _5"> </span>a <span class="blank _5"> </span>f<span class="blank _4"> </span>ração <span class="blank _6"> </span>. <span class="blank _5"> </span>Isso <span class="blank _1"> </span>signi\ue67dca <span class="blank _5"> </span>que</div><div class="t m0 x1 h3 y6 ff1 fs0 fc0 sc0 ls0 ws1">dividimos algo em 100 partes e t<span class="blank _2"></span>omamos x dessas partes.</div><div class="t m0 x1 h3 y7 ff1 fs0 fc0 sc0 ls0 ws1">Par<span class="blank _2"></span>a <span class="blank _7"> </span>repr<span class="blank _2"></span>esentarmos <span class="blank _7"> </span>porc<span class="blank _2"></span>entagem <span class="blank _7"> </span>podemos <span class="blank _7"> </span>usar <span class="blank _7"> </span>uma <span class="blank _7"> </span>f<span class="blank _4"> </span>ração <span class="blank _7"> </span>cent<span class="blank _0"></span>esimal</div><div class="t m0 x1 h3 y8 ff1 fs0 fc0 sc0 ls0 ws1">(denominador <span class="blank _8"> </span>igual <span class="blank _8"> </span>a <span class="blank _8"> </span>cem) <span class="blank _5"> </span>ou <span class="blank _8"> </span>um <span class="blank _8"> </span>número <span class="blank _8"> </span>decimal. <span class="blank _8"> </span>A <span class="blank _8"> </span>seguir <span class="blank _8"> </span>estão <span class="blank _8"> </span>algumas</div><div class="t m0 x1 h3 y9 ff1 fs0 fc0 sc0 ls0 ws1">repr<span class="blank _2"></span>esentações que são equivalent<span class="blank _0"></span>es.</div><div class="t m0 x1 h3 ya ff1 fs0 fc0 sc0 ls0 ws1">A <span class="blank _4"> </span>porc<span class="blank _2"></span>entagem <span class="blank _4"> </span>é <span class="blank _4"> </span>vastament<span class="blank _0"></span>e <span class="blank _4"> </span>utilizada <span class="blank _4"> </span>no <span class="blank _4"> </span>mercado <span class="blank _4"> </span>\ue67dnanceiro<span class="blank _2"></span>, <span class="blank _4"> </span>sendo <span class="blank _4"> </span>aplicada <span class="blank _4"> </span>para</div><div class="t m0 x1 h3 yb ff1 fs0 fc0 sc0 ls0 ws1">capitalizar <span class="blank _9"> </span>empréstimos <span class="blank _9"> </span>e <span class="blank _9"> </span>aplicações, <span class="blank _9"> </span>e<span class="blank _2"></span>xpressar <span class="blank _9"> </span>índic<span class="blank _2"></span>es <span class="blank _9"> </span>in\ue67eacionários <span class="blank _9"> </span>e</div><div class="t m0 x1 h3 yc ff1 fs0 fc0 sc0 ls0 ws1">de\ue67eacionários, descont<span class="blank _0"></span>os, aum<span class="blank _3"> </span>ent<span class="blank _2"></span>os, taxas de jur<span class="blank _2"></span>os, entre outr<span class="blank _2"></span>os.</div><div class="t m0 x1 h4 yd ff3 fs0 fc0 sc0 ls0 ws1">Ex<span class="blank _2"></span>emplos resolvidos.</div><div class="t m0 x1 h3 ye ff1 fs0 fc0 sc0 ls0 ws1">1) <span class="blank _8"> </span>Uma <span class="blank _5"> </span>loja <span class="blank _8"> </span>fez <span class="blank _5"> </span>um <span class="blank _8"> </span>anúncio <span class="blank _8"> </span>de <span class="blank _5"> </span>uma <span class="blank _8"> </span>promoção<span class="blank _2"></span>, <span class="blank _8"> </span>indicando <span class="blank _5"> </span>que <span class="blank _8"> </span>estav<span class="blank _2"></span>a <span class="blank _8"> </span>dando</div><div class="t m0 x1 h3 yf ff1 fs0 fc0 sc0 ls0 ws1">descont<span class="blank _2"></span>os <span class="blank _3"> </span>de <span class="blank _3"> </span>até <span class="blank _3"> </span>60%<span class="blank _3"> </span>. <span class="blank _3"> </span>Uma <span class="blank _3"> </span>pessoa <span class="blank _3"> </span>que <span class="blank _3"> </span>nela <span class="blank _4"> </span>fosse <span class="blank _3"> </span>compr<span class="blank _2"></span>ar <span class="blank _3"> </span>uma <span class="blank _3"> </span>calça <span class="blank _3"> </span>que <span class="blank _4"> </span>ant<span class="blank _2"></span>es <span class="blank _3"> </span>da</div><div class="t m0 x1 h3 y10 ff1 fs0 fc0 sc0 ls0 ws1">promoção <span class="blank _3"> </span>custav<span class="blank _2"></span>a <span class="blank _3"> </span>R$ <span class="blank _3"> </span>90,00, <span class="blank _3"> </span>e <span class="blank _3"> </span>na <span class="blank _3"> </span>liquidação <span class="blank _3"> </span>estava <span class="blank _3"> </span>com <span class="blank _3"> </span>descont<span class="blank _2"></span>o <span class="blank _3"> </span>máximo, <span class="blank _3"> </span>lev<span class="blank _2"></span>aria <span class="blank _3"> </span>a</div><div class="t m0 x1 h3 y11 ff1 fs0 fc0 sc0 ls0 ws1">calça por qual valor?</div><div class="t m0 x1 h4 y12 ff3 fs0 fc0 sc0 ls0 ws0">Resolução:</div><div class="t m0 x1 h3 y13 ff1 fs0 fc0 sc0 ls0 ws1">Dev<span class="blank _2"></span>emos <span class="blank _a"> </span>calcular <span class="blank _a"> </span>o <span class="blank _a"> </span>descont<span class="blank _0"></span>o <span class="blank _a"> </span>que <span class="blank _a"> </span>essa <span class="blank _a"> </span>calça <span class="blank _a"> </span>t<span class="blank _2"></span>em. <span class="blank _a"> </span>Par<span class="blank _2"></span>a <span class="blank _a"> </span>se <span class="blank _a"> </span>obt<span class="blank _2"></span>er <span class="blank _a"> </span>60% <span class="blank _a"> </span>de <span class="blank _a"> </span>R$ <span class="blank _a"> </span>90<span class="blank _2"></span>,00</div><div class="t m0 x1 h3 y14 ff3 fs0 fc0 sc0 ls0 ws1">uma <span class="blank _3"> </span>forma <span class="ff1">é <span class="blank _3"> </span>dividir <span class="blank _3"> </span>o <span class="blank _3"> </span>valor em <span class="blank _3"> </span>reais por <span class="blank _3"> </span>100 <span class="blank _3"> </span>e <span class="blank _3"> </span>multiplicar <span class="blank _3"> </span>por <span class="blank _3"> </span>60<span class="blank _2"></span>. <span class="blank _3"> </span>Assim <span class="blank _3"> </span>R$90<span class="blank _2"></span>,00:100</span></div><div class="t m0 x1 h3 y15 ff1 fs0 fc0 sc0 ls0 ws1">= <span class="blank _a"> </span>0,9<span class="blank _2"></span>.60 <span class="blank _a"> </span>= <span class="blank _b"> </span>R$54,00. <span class="blank _b"> </span>Logo <span class="blank _a"> </span>o <span class="blank _b"> </span>desconto <span class="blank _b"> </span>será <span class="blank _b"> </span>de <span class="blank _a"> </span>R$ <span class="blank _a"> </span>54<span class="blank _3"> </span>,<span class="blank _2"></span>00 <span class="blank _b"> </span>e <span class="blank _a"> </span>ela <span class="blank _a"> </span>pagará <span class="blank _b"> </span>R$ <span class="blank _a"> </span>90,00 <span class="blank _b"> </span>\u2013 <span class="blank _a"> </span>R$</div><div class="t m0 x1 h3 y16 ff1 fs0 fc0 sc0 ls0 ws1">54,00 = R$ 36,00.</div><div class="t m0 x1 h3 y17 ff1 fs0 fc0 sc0 ls0 ws1">2) Descont<span class="blank _2"></span>os sucessiv<span class="blank _2"></span>os de 12% e 20%<span class="blank _3"> </span>, corr<span class="blank _2"></span>espondem a descont<span class="blank _2"></span>o único de quant<span class="blank _2"></span>o<span class="blank _0"></span>?</div><div class="t m0 x1 h4 y18 ff3 fs0 fc0 sc0 ls0 ws0">Resolução:</div><div class="t m0 x1 h3 y19 ff1 fs0 fc0 sc0 ls0 ws1">Se <span class="blank _4"> </span>um <span class="blank _4"> </span>artigo <span class="blank _4"> </span>tem <span class="blank _4"> </span>descont<span class="blank _2"></span>o <span class="blank _4"> </span>de <span class="blank _4"> </span>12% <span class="blank _4"> </span>então <span class="blank _4"> </span>estaremos <span class="blank _4"> </span>pagando <span class="blank _4"> </span>100% <span class="blank _4"> </span>\u2013 <span class="blank _4"> </span>12<span class="blank _3"> </span>% <span class="blank _4"> </span>= <span class="blank _4"> </span>88%, <span class="blank _4"> </span>de</div><div class="t m0 x1 h3 y1a ff1 fs0 fc0 sc0 ls0 ws1">mesma <span class="blank _4"> </span>forma, <span class="blank _3"> </span>se <span class="blank _4"> </span>houver <span class="blank _4"> </span>um <span class="blank _4"> </span>descont<span class="blank _0"></span>o <span class="blank _4"> </span>de <span class="blank _4"> </span>20% <span class="blank _4"> </span>então <span class="blank _4"> </span>a <span class="blank _4"> </span>f<span class="blank _4"> </span>ração <span class="blank _4"> </span>corr<span class="blank _2"></span>espondente <span class="blank _3"> </span>a <span class="blank _4"> </span>ser</div><div class="t m0 x1 h3 y1b ff1 fs0 fc0 sc0 ls0 ws1">paga <span class="blank _c"> </span>é <span class="blank _c"> </span>100% <span class="blank _c"> </span>\u2013 <span class="blank _c"> </span>20% <span class="blank _c"> </span>= <span class="blank _c"> </span>80%<span class="blank _3"> </span>. <span class="blank _c"> </span><span class="ff3">Uma <span class="blank _d"> </span>forma</span> <span class="blank _d"> </span>de <span class="blank"> </span>se <span class="blank _d"> </span>calcular <span class="blank"> </span>os <span class="blank _d"> </span>descontos <span class="blank _d"> </span>sucessivos <span class="blank _c"> </span>é</div><div class="t m0 x1 h3 y1c ff1 fs0 fc0 sc0 ls0 ws1">multiplicar esses valor<span class="blank _2"></span>es.</div><div class="t m0 x2 h5 y1d ff4 fs1 fc0 sc0 ls0"><span class="fc1 sc0">x</span></div><div class="t m0 x3 h5 y1e ff4 fs1 fc0 sc0 ls0 ws1"><span class="fc1 sc0">1</span><span class="fc1 sc0">0</span><span class="fc1 sc0">0</span></div><div class="t m0 x4 h6 y1f ff4 fs2 fc0 sc0 ls0 ws2"><span class="fc1 sc0">x</span><span class="fc1 sc0">%</span><span class="blank"> </span><span class="fc1 sc0">=</span><span class="blank _e"> </span><span class="v1"><span class="fc1 sc0">x</span></span></div><div class="t m0 x5 h7 y20 ff4 fs2 fc0 sc0 ls0 ws1"><span class="fc1 sc0">1</span><span class="fc1 sc0">0</span><span class="fc1 sc0">0</span></div><div class="t m0 x6 h7 y21 ff4 fs2 fc0 sc0 ls0 ws3"><span class="fc1 sc0">8</span><span class="fc1 sc0">%</span><span class="blank _1"> </span><span class="fc1 sc0">=</span><span class="blank _f"> </span><span class="fc1 sc0">=</span><span class="blank _1"> </span><span class="fc1 sc0">0</span><span class="fc1 sc0">,</span><span class="blank"> </span><span class="fc1 sc0">0</span><span class="fc1 sc0">8</span></div><div class="t m0 x7 h7 y22 ff4 fs2 fc0 sc0 ls0"><span class="fc1 sc0">8</span></div><div class="t m0 x8 h7 y23 ff4 fs2 fc0 sc0 ls0 ws1"><span class="fc1 sc0">1</span><span class="fc1 sc0">0</span><span class="fc1 sc0">0</span></div><div class="t m0 x9 h7 y24 ff4 fs2 fc0 sc0 ls0 ws4"><span class="fc1 sc0">5</span><span class="fc1 sc0">7</span><span class="fc1 sc0">%</span><span class="blank _1"> </span><span class="fc1 sc0">=</span><span class="blank _f"> </span><span class="fc1 sc0">=</span><span class="blank _1"> </span><span class="fc1 sc0">0</span><span class="fc1 sc0">,</span><span class="blank"> </span><span class="fc1 sc0">5</span><span class="fc1 sc0">7</span></div><div class="t m0 x7 h7 y25 ff4 fs2 fc0 sc0 ls0 ws1"><span class="fc1 sc0">5</span><span class="fc1 sc0">7</span></div><div class="t m0 xa h7 y26 ff4 fs2 fc0 sc0 ls0 ws1"><span class="fc1 sc0">1</span><span class="fc1 sc0">0</span><span class="fc1 sc0">0</span></div><div class="t m0 xb h7 y27 ff4 fs2 fc0 sc0 ls0 ws3"><span class="fc1 sc0">1</span><span class="fc1 sc0">3</span><span class="fc1 sc0">2</span><span class="fc1 sc0">%</span><span class="blank _1"> </span><span class="fc1 sc0">=</span><span class="blank _f"> </span><span class="fc1 sc0">=</span><span class="blank _1"> </span><span class="fc1 sc0">1</span><span class="fc1 sc0">,</span><span class="blank"> </span><span class="fc1 sc0">3</span><span class="fc1 sc0">2</span></div><div class="t m0 x7 h7 y28 ff4 fs2 fc0 sc0 ls0 ws1"><span class="fc1 sc0">1</span><span class="fc1 sc0">3</span><span class="fc1 sc0">2</span></div><div class="t m0 x7 h7 y29 ff4 fs2 fc0 sc0 ls0 ws1"><span class="fc1 sc0">1</span><span class="fc1 sc0">0</span><span class="fc1 sc0">0</span></div></div></div><div class="pi" data-data="{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}"></div></div> <div id="pf2" class="pf w0 h0" data-page-no="2"><div class="pc pc2 w0 h0"><img class="bi x0 y2a w1 h8" alt="" src="https://files.passeidireto.com/6ccd0e70-466b-42b0-aeb8-73a512191ddb/bg2.png"><div class="c x0 y2b w2 h9"><div class="t m0 x1 h3 y2c ff1 fs0 fc0 sc0 ls0 ws1">Logo<span class="blank _2"></span>, <span class="blank _4"> </span>esses <span class="blank _4"> </span>dois <span class="blank _4"> </span>descont<span class="blank _2"></span>os <span class="blank _4"> </span>sucessiv<span class="blank _2"></span>os <span class="blank _4"> </span>cor<span class="blank _2"></span>respondem <span class="blank _4"> </span>a <span class="blank _3"> </span>um <span class="blank _4"> </span>desconto <span class="blank _3"> </span>único <span class="blank _4"> </span>de <span class="blank _4"> </span>100%</div><div class="t m0 x1 h3 y2d ff1 fs0 fc0 sc0 ls0 ws1">\u2013 70<span class="blank _2"></span>,4<span class="blank _0"></span>% = 29,6<span class="blank _2"></span>%</div><div class="t m0 xc h7 y2e ff4 fs2 fc0 sc0 ls0 ws3"><span class="fc1 sc0">.</span><span class="blank _10"> </span><span class="fc1 sc0">=</span><span class="blank _11"> </span><span class="fc1 sc0">=</span><span class="blank _12"> </span><span class="fc1 sc0">=</span><span class="blank _1"> </span><span class="fc1 sc0">7</span><span class="fc1 sc0">0</span><span class="fc1 sc0">,</span><span class="blank"> </span><span class="fc1 sc0">4</span><span class="fc1 sc0">%</span></div><div class="t m0 xd h7 y2f ff4 fs2 fc0 sc0 ls0 ws1"><span class="fc1 sc0">8</span><span class="fc1 sc0">8</span></div><div class="t m0 xe h7 y30 ff4 fs2 fc0 sc0 ls0 ws1"><span class="fc1 sc0">1</span><span class="fc1 sc0">0</span><span class="fc1 sc0">0</span></div><div class="t m0 xf h7 y2f ff4 fs2 fc0 sc0 ls0 ws1"><span class="fc1 sc0">8</span><span class="fc1 sc0">0</span></div><div class="t m0 x10 h7 y30 ff4 fs2 fc0 sc0 ls0 ws1"><span class="fc1 sc0">1</span><span class="fc1 sc0">0</span><span class="fc1 sc0">0</span></div><div class="t m0 x11 h7 y2f ff4 fs2 fc0 sc0 ls0 ws1"><span class="fc1 sc0">7</span><span class="fc1 sc0">0</span><span class="fc1 sc0">4</span><span class="fc1 sc0">0</span></div><div class="t m0 x4 h7 y30 ff4 fs2 fc0 sc0 ls0 ws1"><span class="fc1 sc0">1</span><span class="fc1 sc0">0</span><span class="fc1 sc0">0</span><span class="fc1 sc0">0</span><span class="fc1 sc0">0</span></div><div class="t m0 x12 h7 y2f ff4 fs2 fc0 sc0 ls0 ws3"><span class="fc1 sc0">7</span><span class="fc1 sc0">0</span><span class="fc1 sc0">,</span><span class="blank"> </span><span class="fc1 sc0">4</span></div><div class="t m0 x13 h7 y30 ff4 fs2 fc0 sc0 ls0 ws1"><span class="fc1 sc0">1</span><span class="fc1 sc0">0</span><span class="fc1 sc0">0</span></div></div></div><div class="pi" data-data="{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}"></div></div> <div id="pf3" class="pf w0 h0" data-page-no="3"><div class="pc pc3 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x0 y0 w3 h1" alt="" src="https://files.passeidireto.com/6ccd0e70-466b-42b0-aeb8-73a512191ddb/bg3.png"><div class="c x0 y1 w2 h2"><div class="t m0 x14 ha y31 ff5 fs3 fc2 sc0 ls0 ws1"><span class="fc1 sc0">E</span><span class="blank _2"></span><span class="fc1 sc0">quaç</span><span class="fc1 sc0">ão</span></div><div class="t m0 x15 hb y32 ff6 fs4 fc2 sc0 ls0 ws5">AU<span class="blank _2"></span>TORIA</div><div class="t m0 x15 hc y33 ff7 fs5 fc2 sc0 ls0 ws1">Luciano Xa<span class="blank _2"></span>vier de Azev<span class="blank _0"></span>edo</div></div><a class="l" data-dest-detail="[3,"XYZ",56,799.92,null]"><div class="d m1" style="border-style:none;position:absolute;left:101.000008px;bottom:700.169980px;width:393.000022px;height:43.500000px;background-color:rgba(255,255,255,0.000001);"></div></a></div><div class="pi" data-data="{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}"></div></div> <div id="pf4" class="pf w0 h0" data-page-no="4"><div class="pc pc4 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x0 y0 w1 h1" alt="" src="https://files.passeidireto.com/6ccd0e70-466b-42b0-aeb8-73a512191ddb/bg4.png"><div class="c x0 y1 w2 h2"><div class="t m0 x1 hd y2 ff6 fs0 fc0 sc0 ls0 ws1">Dizemos <span class="blank _d"> </span>que <span class="blank _c"> </span>uma <span class="blank _c"> </span>igualdade <span class="blank _d"> </span>entre <span class="blank _c"> </span>duas <span class="blank _d"> </span>expressões <span class="blank _d"> </span>matemáticas <span class="blank _d"> </span>que <span class="blank _c"> </span>se <span class="blank _d"> </span>veri\ue67dca</div><div class="t m0 x1 h4 y3 ff6 fs0 fc0 sc0 ls0 ws1">para <span class="blank _13"> </span>deter<span class="blank _2"></span>minados <span class="blank _13"> </span>valores <span class="blank"> </span>das <span class="blank _1"> </span>v<span class="blank _2"></span>ariáv<span class="blank _2"></span>eis <span class="blank _13"> </span>é <span class="blank _13"> </span>chamada <span class="blank _1"> </span>de <span class="blank"> </span><span class="ff7 ws0">equa<span class="blank _3"> </span>ção</span>. <span class="blank _1"> </span>Resolver <span class="blank _1"> </span>uma</div><div class="t m0 x1 hd y4 ff6 fs0 fc0 sc0 ls0 ws1">equação <span class="blank _14"> </span>é <span class="blank _14"> </span>det<span class="blank _2"></span>erminar <span class="blank _14"> </span>quais <span class="blank _14"> </span>os <span class="blank _14"> </span>v<span class="blank _2"></span>alores <span class="blank _14"> </span>satisf<span class="blank _2"></span>azem <span class="blank _14"> </span>det<span class="blank _0"></span>erminadas <span class="blank _14"> </span>condições</div><div class="t m0 x1 hd y5 ff6 fs0 fc0 sc0 ls0 ws1">indicadas <span class="blank _8"> </span>na <span class="blank _8"> </span>equação. <span class="blank _8"> </span>E<span class="blank _2"></span>sses <span class="blank _8"> </span>valor<span class="blank _2"></span>es <span class="blank _8"> </span>são <span class="blank _8"> </span>chamados <span class="blank _8"> </span>de <span class="blank _5"> </span>raízes <span class="blank _8"> </span>da <span class="blank _8"> </span>equação. <span class="blank _5"> </span>Ao</div><div class="t m0 x1 h4 y34 ff6 fs0 fc0 sc0 ls0 ws1">conjunt<span class="blank _2"></span>o de todas as soluç<span class="blank _2"></span>ões de uma equação é chamado de <span class="ff7">conjunt<span class="blank _2"></span>o solução<span class="ff6">.</span></span></div><div class="t m0 x1 hd y35 ff6 fs0 fc0 sc0 ls0 ws1">Por <span class="blank _c"> </span>ex<span class="blank _2"></span>emplo, <span class="blank _c"> </span>o <span class="blank _c"> </span>número <span class="blank _15"> </span>3 <span class="blank _c"> </span>é <span class="blank"> </span>solução <span class="blank _c"> </span>da <span class="blank _15"> </span>equação <span class="blank _c"> </span>4x <span class="blank"> </span>\u2013 <span class="blank _d"> </span>3 <span class="blank"> </span>= <span class="blank _c"> </span>3x, <span class="blank _c"> </span>pois <span class="blank"> </span>a <span class="blank _d"> </span>igualda<span class="blank _3"> </span>de <span class="blank _c"> </span>é</div><div class="t m0 x1 hd y20 ff6 fs0 fc0 sc0 ls0 ws1">ver<span class="blank _2"></span>i\ue67dcada quando se substitui x por 3, note 4.<span class="blank _3"> </span>3 \u2013 3 = 3.3.</div><div class="t m0 x1 he y36 ff8 fs6 fc3 sc0 ls0 ws1"><span class="fc1 sc0">E</span><span class="fc1 sc0">quaç</span><span class="fc1 sc0">õ</span><span class="fc1 sc0">e</span><span class="fc1 sc0">s </span><span class="fc1 sc0">d</span><span class="fc1 sc0">o </span><span class="fc1 sc0">1º </span><span class="fc1 sc0">Gr</span><span class="blank _2"></span><span class="fc1 sc0">a</span><span class="blank _0"></span><span class="fc1 sc0">u</span></div><div class="t m0 x1 hd y37 ff6 fs0 fc0 sc0 ls0 ws1">Caro(a) <span class="blank _4"> </span>aluno(a), <span class="blank _4"> </span>neste <span class="blank _4"> </span>tópico <span class="blank _4"> </span>iremos <span class="blank _4"> </span>discutir <span class="blank _16"> </span>conceit<span class="blank _0"></span>os <span class="blank _16"> </span>envolvidos <span class="blank _4"> </span>em <span class="blank _4"> </span>equações <span class="blank _16"> </span>do</div><div class="t m0 x1 hd y38 ff6 fs0 fc0 sc0 ls0 ws1">1º <span class="blank _4"> </span>grau, <span class="blank _4"> </span>em <span class="blank _16"> </span>especial <span class="blank _16"> </span>a <span class="blank _4"> </span>sua <span class="blank _16"> </span>resolução<span class="blank _2"></span>. <span class="blank _4"> </span>Mas, <span class="blank _16"> </span>a\ue67dnal, <span class="blank _16"> </span>o <span class="blank _4"> </span>que <span class="blank _16"> </span>é <span class="blank _4"> </span>uma <span class="blank _16"> </span>equação <span class="blank _16"> </span>do <span class="blank _4"> </span>primeiro</div><div class="t m0 x1 hd y39 ff6 fs0 fc0 sc0 ls0 ws6">grau?</div><div class="t m0 x1 hd y3a ff6 fs0 fc0 sc0 ls0 ws1">Uma equação <span class="blank _3"> </span>do primeir<span class="blank _2"></span>o grau é <span class="blank _3"> </span>t<span class="blank _2"></span>oda igualdade do <span class="blank _3"> </span>tipo ax + b <span class="blank _3"> </span>= 0, com a e b <span class="blank _3"> </span><span class="ff9 ws7">\u2208<span class="blank _0"></span><span class="ff6 ws1"> R <span class="blank _3"> </span>e a</span></span></div><div class="t m0 x1 hd y3b ffa fs0 fc0 sc0 ls0 ws7">\u2260<span class="ffb ws1"> <span class="ff6">0, sendo </span>x <span class="ff6">um número r<span class="blank _0"></span>eal a ser determinado<span class="blank _0"></span>, chamado de incógnita.</span></span></div><div class="t m0 x1 hd y3c ff6 fs0 fc0 sc0 ls0 ws1">O <span class="blank"> </span>pr<span class="blank _0"></span>oblema <span class="blank"> </span>fundamental <span class="blank"> </span>das <span class="blank _c"> </span>equações <span class="blank"> </span>é <span class="blank _c"> </span>a <span class="blank"> </span>det<span class="blank _2"></span>erminação <span class="blank _c"> </span>de <span class="blank"> </span>suas <span class="blank _15"> </span>raízes, <span class="blank _c"> </span>isto <span class="blank _c"> </span>é,</div><div class="t m0 x1 hd y3d ff6 fs0 fc0 sc0 ls0 ws1">deter<span class="blank _2"></span>minar <span class="blank _4"> </span>a <span class="blank _4"> </span>soluçã<span class="blank _3"> </span>o <span class="blank _4"> </span>da <span class="blank _4"> </span>equação. <span class="blank _4"> </span>Assim, <span class="blank _4"> </span>poderíamos <span class="blank _4"> </span>nos <span class="blank _16"> </span>perguntar: <span class="blank _4"> </span>uma <span class="blank _4"> </span>equação</div><div class="t m0 x1 hd y3e ff6 fs0 fc0 sc0 ls0 ws1">tem solução, isto é, tem raízes<span class="blank _2"></span>? Quantas <span class="blank _3"> </span>são as <span class="blank _3"> </span>raíz<span class="blank _2"></span>es? C<span class="blank _2"></span>omo determinar essas raízes</div><div class="t m0 x1 hd y3f ff6 fs0 fc0 sc0 ls0 ws1">da equaçã<span class="blank _3"> </span>o<span class="blank _0"></span>? Para obter as <span class="blank _3"> </span>raíz<span class="blank _2"></span>es <span class="blank _3"> </span>de uma <span class="blank _3"> </span>equação do <span class="blank _3"> </span>tipo ax <span class="blank _3"> </span>+ b <span class="blank _3"> </span>= 0, <span class="blank _3"> </span>com <span class="ffb">a </span>e b <span class="blank _3"> </span><span class="ff9 ws7">\u2208<span class="blank _2"></span><span class="ff6 ws1"> R <span class="blank _3"> </span>e</span></span></div><div class="t m0 x1 hd y40 ff6 fs0 fc0 sc0 ls0 ws8">a<span class="ffb ws1"> <span class="ffa ws7">\u2260</span> <span class="ff6">0, e<span class="blank _2"></span>xistem v<span class="blank _0"></span>ários métodos.</span></span></div><div class="t m0 x1 h4 y41 ff7 fs0 fc0 sc0 ls0 ws0">Propr<span class="blank _2"></span>iedades:</div><div class="t m0 x1 h4 y42 ff7 fs0 fc0 sc0 ls0 ws0">Aditiv<span class="blank _2"></span>a:<span class="ff6 ws1"> <span class="blank _8"> </span>somar <span class="blank _8"> </span>ou <span class="blank _8"> </span>subtrair <span class="blank _8"> </span>um <span class="blank _8"> </span>número <span class="blank _8"> </span>nos <span class="blank _8"> </span>dois <span class="blank _8"> </span>membros <span class="blank _8"> </span>de <span class="blank _8"> </span>uma <span class="blank _8"> </span>equação,</span></div><div class="t m0 x1 hd y43 ff6 fs0 fc0 sc0 ls0 ws1">encontrando outr<span class="blank _2"></span>a equivalent<span class="blank _2"></span>e.</div><div class="t m0 x1 h4 y44 ff7 fs0 fc0 sc0 ls0 ws9">Mul<span class="blank"> </span>tiplicativa:<span class="ff6 ws1"> multiplicar <span class="blank _3"> </span>ou dividir <span class="blank _3"> </span>por um <span class="blank _3"> </span>número não <span class="blank _3"> </span>nulo <span class="blank _3"> </span>nos dois <span class="blank _3"> </span>membros de</span></div><div class="t m0 x1 hd y45 ff6 fs0 fc0 sc0 ls0 ws1">uma equação, encontr<span class="blank _2"></span>ando outra equiv<span class="blank _2"></span>alente.</div><div class="t m0 x1 h4 y46 ff7 fs0 fc0 sc0 ls0 ws1">Ex<span class="blank _2"></span>emplo resolvido</div><div class="t m0 x1 hd y47 ff6 fs0 fc0 sc0 ls0 ws1">Resolver cada uma das equações:</div><div class="t m0 x1 hd y48 ff6 fs0 fc0 sc0 ls0 ws1">a) 5x \u2013 12 = 8 </div><div class="t m0 x1 hd y49 ff6 fs0 fc0 sc0 ls0 ws1">b) 3x \u2013 10 = 2x + 8</div><div class="t m0 x1 h4 y4a ff7 fs0 fc0 sc0 ls0 ws0">Resolução:</div><div class="t m0 x1 hd y4b ff6 fs0 fc0 sc0 ls0 ws1">a) <span class="blank _d"> </span>As <span class="blank _d"> </span>operações <span class="blank _d"> </span>aditiva <span class="blank _d"> </span>e <span class="blank _d"> </span>multiplicativa <span class="blank _d"> </span>podem <span class="blank _c"> </span>ser <span class="blank _d"> </span>substituídas <span class="blank _d"> </span>pelo <span class="blank _c"> </span>processo <span class="blank _d"> </span>de</div><div class="t m0 x1 hd y4c ff6 fs0 fc0 sc0 ls0 ws1">isolar o valor de x, observe:</div><div class="t m0 x1 hd y4d ff6 fs0 fc0 sc0 ls0 ws1">Podemos \u201clev<span class="blank _0"></span>ar<span class="blank _3"> </span>\u201d o \u2013 12 para o segundo membro inv<span class="blank _2"></span>ertendo a operação<span class="blank _2"></span>, daí:</div></div></div><div class="pi" data-data="{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}"></div></div> <div id="pf5" class="pf w0 h0" data-page-no="5"><div class="pc pc5 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x0 y0 w1 h1" alt="" src="https://files.passeidireto.com/6ccd0e70-466b-42b0-aeb8-73a512191ddb/bg5.png"><div class="c x0 y2b w2 h9"><div class="t m0 x1 hd y4e ff6 fs0 fc0 sc0 ls0 ws1">5x = 8 + 12 </div><div class="t m0 x1 hd y30 ff6 fs0 fc0 sc0 ls0 ws1">5x = 20</div><div class="t m0 x1 hd y4f ff6 fs0 fc0 sc0 ls0 ws1">Agora, como <span class="blank _3"> </span>o valor <span class="blank _3"> </span>5 está <span class="blank _3"> </span>multiplicando <span class="blank _3"> </span>o valor <span class="blank _3"> </span>de x <span class="blank _3"> </span>então <span class="blank _3"> </span>\u201ctransferimos\u201d o <span class="blank _3"> </span>5 <span class="blank _3"> </span>para o</div><div class="t m0 x1 hd y50 ff6 fs0 fc0 sc0 ls0 ws1">outro membr<span class="blank _2"></span>o invert<span class="blank _2"></span>endo a operação:</div><div class="t m0 x1 hd y51 ff6 fs0 fc0 sc0 ls0 ws1">Logo: <span class="blank _17"> </span>.</div><div class="t m0 x1 hd y52 ff6 fs0 fc0 sc0 ls0 ws1">b) <span class="blank"> </span>P<span class="blank _2"></span>ode-se <span class="blank"> </span>usar <span class="blank _c"> </span>o <span class="blank"> </span>método <span class="blank _c"> </span>aplicado <span class="blank"> </span>em <span class="blank _c"> </span>a), <span class="blank"> </span>mas <span class="blank"> </span>f<span class="blank _2"></span>aremos <span class="blank _c"> </span>pelo <span class="blank"> </span>proc<span class="blank _2"></span>esso <span class="blank"> </span>aditiv<span class="blank _2"></span>o <span class="blank _15"> </span>e</div><div class="t m0 x1 hd y53 ff6 fs0 fc0 sc0 ls0 ws8">multiplicativo<span class="blank _2"></span>.</div><div class="t m0 x1 hd y54 ff6 fs0 fc0 sc0 ls0 ws1">Par<span class="blank _2"></span>a <span class="blank"> </span>obt<span class="blank _0"></span>ermos <span class="blank"> </span>a <span class="blank _c"> </span>solução <span class="blank"> </span>dessa <span class="blank _c"> </span>equação <span class="blank"> </span>dev<span class="blank _0"></span>emos <span class="blank"> </span>somar <span class="blank _c"> </span>10 <span class="blank"> </span>a <span class="blank _c"> </span>cada <span class="blank"> </span>um <span class="blank _c"> </span>de <span class="blank"> </span>seus</div><div class="t m0 x1 hd y55 ff6 fs0 fc0 sc0 ls0 ws8">membros:</div><div class="t m0 x1 hd y56 ff6 fs0 fc0 sc0 ls0 ws1">3x \u2013 10 + 10 = 2x + 8 + 10 </div><div class="t m0 x1 hd y57 ff6 fs0 fc0 sc0 ls0 ws1">3x = 2x + 18</div><div class="t m0 x1 hd y58 ff6 fs0 fc0 sc0 ls0 ws1">Ainda podemos somar \u20132x em ambos os membros:</div><div class="t m0 x1 hd y59 ff6 fs0 fc0 sc0 ls0 ws1">3x + (\u20132x) = 2<span class="blank _2"></span>x + (\u20132x) + 18 </div><div class="t m0 x1 hd y5a ff6 fs0 fc0 sc0 ls0 ws1">x = 18</div><div class="t m0 x1 hd y5b ff6 fs0 fc0 sc0 ls0 ws1">Logo<span class="blank _2"></span>, x \ue6d0= 18. Podemos então indicar o conjunto solução S = {18}.</div><div class="t m0 x1 he y5c ff8 fs6 fc3 sc0 ls0 ws1"><span class="fc1 sc0">E</span><span class="fc1 sc0">quaç</span><span class="fc1 sc0">õ</span><span class="fc1 sc0">e</span><span class="fc1 sc0">s </span><span class="fc1 sc0">d</span><span class="fc1 sc0">o </span><span class="fc1 sc0">2º </span><span class="fc1 sc0">Gr</span><span class="blank _2"></span><span class="fc1 sc0">a</span><span class="blank _0"></span><span class="fc1 sc0">u</span></div><div class="t m0 x1 hd y5d ff6 fs0 fc0 sc0 ls0 ws1">Caro(a) <span class="blank _d"> </span>aluno(a), <span class="blank _c"> </span>agora <span class="blank _d"> </span>você <span class="blank _d"> </span>terá <span class="blank _d"> </span>contat<span class="blank _2"></span>o <span class="blank _c"> </span>com <span class="blank _d"> </span>um <span class="blank _c"> </span>tipo <span class="blank _c"> </span>de <span class="blank _c"> </span>equação <span class="blank _c"> </span>par<span class="blank _3"> </span>ticular, <span class="blank _d"> </span>as</div><div class="t m0 x1 hd y5e ff6 fs0 fc0 sc0 ls0 ws1">equações <span class="blank _18"> </span>chamadas <span class="blank _18"> </span>de <span class="blank _18"> </span>equações <span class="blank _18"> </span>polinomiais <span class="blank _18"> </span>do <span class="blank _19"> </span>segundo <span class="blank _18"> </span>grau <span class="blank _18"> </span>ou <span class="blank _18"> </span>equação</div><div class="t m0 x1 hd y5f ff6 fs0 fc0 sc0 ls0 ws1">quadrática. Nós iremos apresentar a <span class="blank _3"> </span>v<span class="blank _2"></span>ocê um m<span class="blank _3"> </span>ét<span class="blank _2"></span>odo de resolução conhecido <span class="blank _3"> </span>como</div><div class="t m0 x1 hd y60 ff6 fs0 fc0 sc0 ls0 ws1">Bhaskara. <span class="blank _18"> </span>Ant<span class="blank _0"></span>es <span class="blank _18"> </span>desse <span class="blank _18"> </span>método, <span class="blank _18"> </span>ir<span class="blank _2"></span>emos <span class="blank _18"> </span>indicar <span class="blank _18"> </span>as <span class="blank _18"> </span>equações <span class="blank _18"> </span>incompletas <span class="blank _18"> </span>que</div><div class="t m0 x1 hd y61 ff6 fs0 fc0 sc0 ls0 ws1">também <span class="blank _3"> </span>podem <span class="blank _3"> </span>ser <span class="blank _3"> </span>resolvidas como <span class="blank _3"> </span>o <span class="blank _3"> </span>método citado, <span class="blank _3"> </span>mas <span class="blank _3"> </span>exist<span class="blank _0"></span>e <span class="blank _3"> </span>a <span class="blank _3"> </span>possibilidade <span class="blank _3"> </span>de</div><div class="t m0 x1 hd y62 ff6 fs0 fc0 sc0 ls0 ws1">diminuir esfor<span class="blank _2"></span>ços e t<span class="blank _2"></span>empo na resolução. V<span class="blank _0"></span>amos então par<span class="blank _2"></span>a a de\ue67dnição:</div><div class="t m0 x1 hd y63 ff6 fs0 fc0 sc0 ls0 ws1">Uma equação <span class="blank _3"> </span>de segundo <span class="blank _3"> </span>grau ou quadrática com <span class="blank _3"> </span>coe\ue67dcient<span class="blank _0"></span>es <span class="blank _3"> </span><span class="ffb">a, b </span>e <span class="ffb">c </span>é <span class="blank _4"> </span>a <span class="blank _3"> </span>equa<span class="blank _3"> </span>ção</div><div class="t m0 x1 hd y64 ff6 fs0 fc0 sc0 ls0 ws1">na forma c<span class="blank _2"></span>ompleta repr<span class="blank _2"></span>esentada por:</div><div class="t m0 x1 hd y65 ff6 fs0 fc0 sc0 ls0 ws1">ax² + bx + c = 0<span class="ffb"> </span></div><div class="t m0 x1 hd y66 ffb fs0 fc0 sc0 ls0 ws1">a, b <span class="ff6">e c <span class="ffc ws7">\u2208<span class="blank _2"></span><span class="ff6 ws1"> R e <span class="ffb ws8">a</span> <span class="ffd ws7">\u2260</span> 0 e <span class="ffb ws8">x</span> a incógnita a ser det<span class="blank _2"></span>erminada.</span></span></span></div><div class="t m0 x1 hd y67 ff6 fs0 fc0 sc0 ls0 ws1">Observe que <span class="ffb">a </span>é o coe\ue67dcient<span class="blank _2"></span>e que acompanha o <span class="ffb ws8">x²</span>, o coe\ue67dcient<span class="blank _0"></span>e <span class="ffb">b </span>acompanha o <span class="ffb">x <span class="blank _4"> </span></span>e</div><div class="t m0 x1 hd y68 ff6 fs0 fc0 sc0 ls0 ws1">o <span class="ffb">c </span>é <span class="blank _4"> </span>o <span class="blank _4"> </span>t<span class="blank _2"></span>ermo <span class="blank _4"> </span>independent<span class="blank _2"></span>e <span class="blank _4"> </span>da <span class="blank _4"> </span>equação. <span class="blank _3"> </span>Não <span class="blank _4"> </span>se <span class="blank _4"> </span>esqueça <span class="blank _4"> </span>de <span class="blank _4"> </span>atentar <span class="blank _3"> </span>a <span class="blank _4"> </span>esses <span class="blank _4"> </span>fator<span class="blank _2"></span>es,</div><div class="t m0 x1 hd y69 ff6 fs0 fc0 sc0 ls0 ws1">pois são essenciais para resolv<span class="blank _0"></span>er uma equaçã<span class="blank _3"> </span>o do 2º grau.</div><div class="t m0 x1 hd y6a ff6 fs0 fc0 sc0 ls0 ws1">Observe as equações a seguir:</div><div class="t m0 x16 h7 y51 ffe fs2 fc0 sc0 ls0 wsa"><span class="fc1 sc0">x</span><span class="blank"> </span><span class="fc1 sc0">=</span><span class="blank _1a"> </span><span class="fc1 sc0">\u21d2</span><span class="blank"> </span><span class="fc1 sc0">x</span><span class="blank"> </span><span class="fc1 sc0">=</span><span class="blank"> </span><span class="fc1 sc0">4</span></div><div class="t m0 x17 h5 y6b ffe fs1 fc0 sc0 ls0 ws1"><span class="fc1 sc0">2</span><span class="fc1 sc0">0</span></div><div class="t m0 x18 h5 y6c ffe fs1 fc0 sc0 ls0"><span class="fc1 sc0">5</span></div></div></div><div class="pi" data-data="{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}"></div></div> <div id="pf6" class="pf w0 h0" data-page-no="6"><div class="pc pc6 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x0 y6d w1 hf" alt="" src="https://files.passeidireto.com/6ccd0e70-466b-42b0-aeb8-73a512191ddb/bg6.png"><div class="c x0 y6e w2 h10"><div class="t m0 x1 hd y6f ff6 fs0 fc0 sc0 ls0 ws1">a) 3x² \u2013 7<span class="blank _0"></span>x + 9 = 0 \ue6d0 é uma equa<span class="blank _3"> </span>ção do 2º grau, c<span class="blank _2"></span>om <span class="ffb ws8">a</span> = 3, \ue6d0<span class="ffb ws8">b</span> = \u20137 \ue6d0e \ue6d0<span class="ffb ws8">c</span> = 9. </div><div class="t m0 x1 hd y70 ff6 fs0 fc0 sc0 ls0 ws1">b) \u20132x² \u2013 x \u2013 1 = 0 \ue6d0 \ue6d0é uma equação do 2º grau, c<span class="blank _2"></span>om <span class="ffb ws8">a</span> = \u20132, \ue6d0<span class="ffb ws8">b</span> = \u20131 \ue6d0e \ue6d0<span class="ffb ws8">c</span> = \u20131. </div><div class="t m0 x1 hd y71 ff6 fs0 fc0 sc0 ls0 ws1">c) 9<span class="blank _2"></span>x² \u2013 12x = 0 \ue6d0 \ue6d0 \ue6d0 \ue6d0é uma equação do 2º grau, c<span class="blank _2"></span>om <span class="ffb ws8">a</span> = 9, \ue6d0<span class="ffb ws8">b</span> = \u201312 \ue6d0e \ue6d0<span class="ffb ws8">c</span> = 0<span class="blank _2"></span>.</div><div class="t m0 x1 hd y72 ff6 fs0 fc0 sc0 ls0 ws1">C<span class="blank _2"></span>onsidere a equaçã<span class="blank _3"> </span>o do segundo <span class="blank _3"> </span>grau ax² + <span class="blank _3"> </span>b<span class="blank _2"></span>x + <span class="blank _3"> </span>c = 0, <span class="blank _3"> </span>com a <span class="ffd ls1">\u2260</span> 0. <span class="blank _3"> </span>P<span class="blank _2"></span>ara obtermos sua</div><div class="t m0 x1 hd y73 ff6 fs0 fc0 sc0 ls0 ws1">solução, um dos pr<span class="blank _2"></span>ocessos que pode ser usado é a fór<span class="blank _2"></span>mula resolutiv<span class="blank _2"></span>a de Bhaskara:</div><div class="t m0 x1 hd y74 ff6 fs0 fc0 sc0 ls0 ws1">Note <span class="blank _b"> </span>que <span class="blank _d"> </span>usamos <span class="blank _1b"> </span>. <span class="blank _d"> </span>Esse <span class="blank _d"> </span>valor <span class="blank _a"> </span>é <span class="blank _d"> </span>chamado <span class="blank _d"> </span>de <span class="blank _c"> </span>delta. <span class="blank _d"> </span>Então, <span class="blank _d"> </span>confor<span class="blank _2"></span>me</div><div class="t m0 x1 hd y75 ff6 fs0 fc0 sc0 ls0 ws1">temos a, b e c esse v<span class="blank _2"></span>alor pode var<span class="blank _2"></span>iar o sinal. Acompanhe:</div></div><div class="c x0 y76 w2 h11"><div class="t m0 x19 hd y77 ff6 fs0 fc0 sc0 ls0 ws1">1<span class="blank _2"></span>. <span class="blank _3"> </span>Se <span class="blank _1c"> </span>, <span class="blank _d"> </span>então <span class="blank _d"> </span>exist<span class="blank _2"></span>em <span class="blank _d"> </span>duas <span class="blank _d"> </span>raízes <span class="blank _d"> </span>re<span class="blank _2"></span>ais <span class="blank _d"> </span>distintas, <span class="blank _d"> </span>pois <span class="blank _1d"> </span> <span class="blank _d"> </span>representa <span class="blank _a"> </span>um</div><div class="t m0 x1a hd y78 ff6 fs0 fc0 sc0 ls0 ws1">número r<span class="blank _2"></span>eal positiv<span class="blank _2"></span>o.</div><div class="t m0 x1b hd y79 ff6 fs0 fc0 sc0 ls0 ws1">2<span class="blank _0"></span>. <span class="blank _4"> </span>Se <span class="blank _1e"> </span> então as duas raízes são iguais, uma v<span class="blank _2"></span>ez que <span class="blank _1a"> </span> é igual a zero.</div><div class="t m0 x1b hd y7a ff6 fs0 fc0 sc0 ls0 ws1">3<span class="blank _0"></span>. <span class="blank _4"> </span>Se <span class="blank _1f"> </span> <span class="blank _4"> </span>então <span class="blank _4"> </span>não <span class="blank _16"> </span>exist<span class="blank _0"></span>em <span class="blank _16"> </span>raízes <span class="blank _3"> </span>reais, <span class="blank _4"> </span>pois <span class="blank _20"> </span> <span class="blank _16"> </span>não <span class="blank _16"> </span>representa <span class="blank _4"> </span>um <span class="blank _16"> </span>número</div><div class="t m0 x1a hd y7b ff6 fs0 fc0 sc0 ls0 ws8">re<span class="blank _2"></span>al.</div></div><div class="c x0 y6e w2 h10"><div class="t m0 x1 h4 y7c ff7 fs0 fc0 sc0 ls0 ws1">Ex<span class="blank _2"></span>emplo resolvido:</div><div class="t m0 x1 hd y7d ff6 fs0 fc0 sc0 ls0 ws1">1) Considere a equaçã<span class="blank _3"> </span>o dada <span class="blank _3"> </span>por x² <span class="blank _3"> </span>\u2013 5x + <span class="blank _3"> </span>6 = <span class="blank _3"> </span>0. Determine, se h<span class="blank _3"> </span>ouv<span class="blank _2"></span>er, as <span class="blank _3"> </span>raíz<span class="blank _2"></span>es dessa</div><div class="t m0 x1 hd y7e ff6 fs0 fc0 sc0 ls0 ws8">equação.</div><div class="t m0 x1 h4 y7f ff7 fs0 fc0 sc0 ls0 ws0">Resolução:</div><div class="t m0 x1 hd y80 ff6 fs0 fc0 sc0 ls0 ws1">C<span class="blank _2"></span>omparando a <span class="blank _3"> </span>sentença da <span class="blank _3"> </span>equação <span class="blank _3"> </span>como ax² <span class="blank _3"> </span>+ bx + <span class="blank _3"> </span>c <span class="blank _3"> </span>= 0 <span class="blank _3"> </span>temos a <span class="blank _3"> </span>= 1, <span class="blank _3"> </span>b <span class="blank _3"> </span>= \u20135 <span class="blank _3"> </span>e <span class="blank _3"> </span>c = <span class="blank _3"> </span>6.</div><div class="t m0 x1 hd y81 ff6 fs0 fc0 sc0 ls0 ws1">Par<span class="blank _2"></span>a obter<span class="blank _2"></span>mos, se houver, r<span class="blank _2"></span>aízes, usaremos o pr<span class="blank _2"></span>ocesso de Bhaskar<span class="blank _2"></span>a, assim:</div><div class="t m0 x1 hd y82 ff6 fs0 fc0 sc0 ls0 ws1">Logo x<span class="fff ws7">\u2081</span> = 2 e x<span class="fff ws7">\u2082</span> = 3.</div><div class="t m0 x1 hd y83 ff6 fs0 fc0 sc0 ls0 ws1">2) <span class="blank _4"> </span>Calcule <span class="blank _3"> </span>o <span class="blank _4"> </span>valor <span class="blank _4"> </span>de <span class="blank _4"> </span><span class="ffb ws8">m</span> <span class="blank _4"> </span>para <span class="blank _4"> </span>que <span class="blank _4"> </span>a <span class="blank _4"> </span>equação <span class="blank _4"> </span>do <span class="blank _4"> </span>segundo <span class="blank _16"> </span>grau <span class="blank _4"> </span>x² <span class="blank _4"> </span>\u2013 <span class="blank _4"> </span>4x <span class="blank _4"> </span>+ <span class="blank _4"> </span>m <span class="blank _4"> </span>= <span class="blank _4"> </span>0 <span class="blank _16"> </span>tenha</div><div class="t m0 x1 hd y84 ff6 fs0 fc0 sc0 ls0 ws1">uma única raiz.</div><div class="t m0 x1 h4 y85 ff7 fs0 fc0 sc0 ls0 ws0">Resolução:</div><div class="t m0 x1 hd y86 ff6 fs0 fc0 sc0 ls0 ws1">Par<span class="blank _2"></span>a <span class="blank _21"> </span>que <span class="blank _21"> </span>a <span class="blank _21"> </span>equação <span class="blank _21"> </span>quadrática <span class="blank _8"> </span>tenha <span class="blank _21"> </span>uma <span class="blank _21"> </span>única <span class="blank _21"> </span>raiz <span class="blank _8"> </span>real <span class="blank _8"> </span>devemos <span class="blank _21"> </span>t<span class="blank _2"></span>er <span class="blank _21"> </span>seu</div><div class="t m0 x1 hd y87 ff6 fs0 fc0 sc0 ls0 ws1">discriminant<span class="blank _2"></span>e, delta, igual a zero<span class="blank _0"></span>. Usan<span class="blank _3"> </span>do <span class="ffb ws8">a</span> = 1, <span class="ffb ws8">b</span> = \u2013 4 e <span class="ffb ws8">c</span> = <span class="ffb ws8">m</span> t<span class="blank _0"></span>emos</div><div class="t m0 xd h7 y88 ffe fs2 fc0 sc0 ls0 wsb"><span class="fc1 sc0">x</span><span class="blank"> </span><span class="fc1 sc0">=</span><span class="blank _22"> </span><span class="fc1 sc0">=</span></div><div class="t m0 x10 h7 y89 ffe fs2 fc0 sc0 ls0 wsc"><span class="fc1 sc0">\u2212</span><span class="fc1 sc0">b</span><span class="blank"> </span><span class="fc1 sc0">±</span></div><div class="t m0 x1c h7 y8a ff10 fs2 fc0 sc0 ls0"><span class="fc1 sc0">\u221a</span></div><div class="t m0 x11 h12 y89 ffe fs2 fc0 sc0 ls2"><span class="fc1 sc0">b</span><span class="fs1 ls3 v2"><span class="fc1 sc0">2</span></span><span class="ls0 wsd"><span class="fc1 sc0">\u2212</span><span class="blank"> </span><span class="fc1 sc0">4</span><span class="fc1 sc0">a</span><span class="fc1 sc0">c</span></span></div><div class="t m0 x1d h7 y8b ffe fs2 fc0 sc0 ls0 ws1"><span class="fc1 sc0">2</span><span class="fc1 sc0">a</span></div><div class="t m0 x1e h13 y89 ffe fs2 fc0 sc0 ls0 wsd"><span class="fc1 sc0">\u2212</span><span class="fc1 sc0">b</span><span class="blank"> </span><span class="fc1 sc0">±</span><span class="blank"> </span><span class="ls4 v3"><span class="fc1 sc0">\u221a</span></span><span class="fc1 sc0">\u0394</span></div><div class="t m0 x1f h7 y8b ffe fs2 fc0 sc0 ls0 ws1"><span class="fc1 sc0">2</span><span class="fc1 sc0">a</span></div><div class="t m0 x20 h7 y8c ff11 fs2 fc0 sc0 ls0"><span class="fc1 sc0">x</span></div><div class="t m0 x4 h14 y8c ffe fs2 fc0 sc0 ls5"><span class="fc1 sc0">=</span><span class="ls0 v4"><span class="fc1 sc0">\u2212</span></span></div><div class="t m0 x21 h7 y8d ff11 fs2 fc0 sc0 ls0"><span class="fc1 sc0">b</span></div><div class="t m0 x22 h15 y8d ffe fs2 fc0 sc0 ls6"><span class="fc1 sc0">±</span><span class="ls4 v5"><span class="fc1 sc0">\u221a</span></span><span class="ls0"><span class="fc1 sc0">\u0394</span></span></div><div class="t m0 x23 h7 y8e ffe fs2 fc0 sc0 ls0"><span class="fc1 sc0">2</span></div><div class="t m0 x24 h7 y8e ff11 fs2 fc0 sc0 ls0"><span class="fc1 sc0">a</span></div><div class="t m0 x25 h7 y74 ffe fs2 fc0 sc0 ls0 wse"><span class="fc1 sc0">\u0394</span><span class="blank"> </span><span class="fc1 sc0">=</span></div><div class="t m0 x26 h7 y74 ff11 fs2 fc0 sc0 ls0"><span class="fc1 sc0">b</span></div><div class="t m0 x27 h5 y8f ffe fs1 fc0 sc0 ls7"><span class="fc1 sc0">2</span><span class="fs2 ls0 wsf v6"><span class="fc1 sc0">\u2212</span><span class="blank"> </span><span class="fc1 sc0">4</span></span></div><div class="t m0 x28 h7 y74 ff11 fs2 fc0 sc0 ls0 ws1"><span class="fc1 sc0">a</span><span class="fc1 sc0">c</span></div></div><div class="c x0 y76 w2 h11"><div class="t m0 x29 h15 y77 ffe fs2 fc0 sc0 ls0 wse"><span class="fc1 sc0">\u0394</span><span class="blank"> </span><span class="fc1 sc0">></span><span class="blank"> </span><span class="fc1 sc0">0</span><span class="blank _23"> </span><span class="ls4 v5"><span class="fc1 sc0">\u221a</span></span><span class="fc1 sc0">\u0394</span></div><div class="t m0 x2a h15 y79 ffe fs2 fc0 sc0 ls0 wse"><span class="fc1 sc0">\u0394</span><span class="blank"> </span><span class="fc1 sc0">=</span><span class="blank"> </span><span class="fc1 sc0">0</span><span class="blank _24"> </span><span class="ls4 v5"><span class="fc1 sc0">\u221a</span></span><span class="fc1 sc0">\u0394</span></div><div class="t m0 x2a h15 y7a ffe fs2 fc0 sc0 ls0 wse"><span class="fc1 sc0">\u0394</span><span class="blank"> </span><span class="fc1 sc0"><</span><span class="blank"> </span><span class="fc1 sc0">0</span><span class="blank _25"> </span><span class="ls4 v5"><span class="fc1 sc0">\u221a</span></span><span class="fc1 sc0">\u0394</span></div></div><div class="c x0 y6e w2 h10"><div class="t m0 x6 h16 y90 ffe fs2 fc0 sc0 ls0 ws2"><span class="fc1 sc0">\u0394</span><span class="blank"> </span><span class="fc1 sc0">=</span><span class="blank"> </span><span class="fc1 sc0">(</span><span class="fc1 sc0">\u2212</span><span class="fc1 sc0">5</span><span class="fc1 sc0">)</span><span class="fs1 ls3 v7"><span class="fc1 sc0">2</span></span><span class="wsd"><span class="fc1 sc0">\u2212</span><span class="blank"> </span><span class="fc1 sc0">4</span><span class="fc1 sc0">.</span><span class="fc1 sc0">1</span><span class="fc1 sc0">.</span><span class="fc1 sc0">6</span></span></div><div class="t m0 x6 h7 y91 ffe fs2 fc0 sc0 ls0 ws10"><span class="fc1 sc0">\u0394</span><span class="blank"> </span><span class="fc1 sc0">=</span><span class="blank"> </span><span class="fc1 sc0">2</span><span class="fc1 sc0">5</span><span class="blank _26"> </span><span class="fc1 sc0">\u2212</span><span class="blank _26"> </span><span class="fc1 sc0">2</span><span class="fc1 sc0">4</span><span class="blank"> </span><span class="fc1 sc0">=</span><span class="blank"> </span><span class="fc1 sc0">1</span></div><div class="t m0 x6 h7 y92 ffe fs2 fc0 sc0 ls0 ws11"><span class="fc1 sc0">x</span><span class="blank"> </span><span class="fc1 sc0">=</span></div><div class="t m0 x6 h7 y93 ffe fs2 fc0 sc0 ls0 ws11"><span class="fc1 sc0">x</span><span class="blank"> </span><span class="fc1 sc0">=</span></div><div class="t m0 x2b h17 y94 ffe fs1 fc0 sc0 ls0 ws1"><span class="fc1 sc0">\u2212</span><span class="fc1 sc0">(</span><span class="fc1 sc0">\u2212</span><span class="fc1 sc0">5</span><span class="fc1 sc0">)</span><span class="fc1 sc0">±</span><span class="ls8 v5"><span class="fc1 sc0">\u221a</span></span><span class="fc1 sc0">1</span></div><div class="t m0 x7 h5 y95 ffe fs1 fc0 sc0 ls0 ws1"><span class="fc1 sc0">2</span><span class="fc1 sc0">.</span><span class="fc1 sc0">1</span></div><div class="t m0 x2b h5 y96 ffe fs1 fc0 sc0 ls0 ws1"><span class="fc1 sc0">5</span><span class="fc1 sc0">±</span><span class="fc1 sc0">1</span></div><div class="t m0 x2c h5 y97 ffe fs1 fc0 sc0 ls0"><span class="fc1 sc0">2</span></div></div></div><div class="pi" data-data="{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}"></div></div> <div id="pf7" class="pf w0 h0" data-page-no="7"><div class="pc pc7 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x0 y6d w1 hf" alt="" src="https://files.passeidireto.com/6ccd0e70-466b-42b0-aeb8-73a512191ddb/bg7.png"><div class="c x0 y6e w2 h10"><div class="t m0 x1 hd y98 ffd fs0 fc0 sc0 ls0 ws7">\u0394<span class="ff6 ws1"> = (\u20134)² \u2013 4.1.m = 0 </span></div><div class="t m0 x1 hd y99 ff6 fs0 fc0 sc0 ls0 ws1">16 \u2013 4m = 0 </div><div class="t m0 x1 hd y9a ff6 fs0 fc0 sc0 ls0 ws1">m = 4</div><div class="t m0 x1 he y9b ff8 fs6 fc3 sc0 ls0 ws1"><span class="fc1 sc0">Sist</span><span class="blank _2"></span><span class="fc1 sc0">emas </span><span class="fc1 sc0">d</span><span class="fc1 sc0">e </span><span class="fc1 sc0">E</span><span class="fc1 sc0">qua</span><span class="fc1 sc0">ç</span><span class="fc1 sc0">õ</span><span class="fc1 sc0">e</span><span class="fc1 sc0">s </span><span class="fc1 sc0">d</span><span class="fc1 sc0">o </span><span class="fc1 sc0">Pr</span><span class="fc1 sc0">im</span><span class="fc1 sc0">eir</span><span class="blank _2"></span><span class="fc1 sc0">o</span><span class="fc1 sc0"> </span><span class="fc1 sc0">Gr</span><span class="fc1 sc0">a</span><span class="blank _0"></span><span class="fc1 sc0">u</span></div><div class="t m0 x1 hd y9c ff6 fs0 fc0 sc0 ls0 ws1">Em <span class="blank _4"> </span>várias <span class="blank _3"> </span>situações <span class="blank _4"> </span>encontradas <span class="blank _4"> </span>nas <span class="blank _4"> </span>descrições <span class="blank _4"> </span>mat<span class="blank _2"></span>emáticas <span class="blank _4"> </span>de <span class="blank _4"> </span>fenômenos <span class="blank _4"> </span>f<span class="blank _16"> </span>ísicos</div><div class="t m0 x1 hd y9d ff6 fs0 fc0 sc0 ls0 ws1">nos <span class="blank _1"> </span>dep<span class="blank _2"></span>aramos <span class="blank _13"> </span>com <span class="blank _1"> </span>a <span class="blank _13"> </span>necessidade <span class="blank _1"> </span>da <span class="blank _13"> </span>solução <span class="blank _1"> </span>simultâne<span class="blank _2"></span>a <span class="blank _1"> </span>de <span class="blank _13"> </span>um <span class="blank _1"> </span>c<span class="blank _2"></span>onjunto <span class="blank _13"> </span>de</div><div class="t m0 x1 hd y9e ff6 fs0 fc0 sc0 ls0 ws1">equações. <span class="blank _5"> </span>Esses <span class="blank _1"> </span>conjuntos <span class="blank _5"> </span>apresentam <span class="blank _1"> </span><span class="ffb ws8">m</span> <span class="blank _8"> </span>equaç<span class="blank _2"></span>ões <span class="blank _5"> </span>com <span class="blank _5"> </span><span class="ffb ws8">n</span> <span class="blank _8"> </span>incógnitas. <span class="blank _8"> </span>A <span class="blank _5"> </span>esse</div><div class="t m0 x1 h4 y9f ff6 fs0 fc0 sc0 ls0 ws1">conjunt<span class="blank _2"></span>o <span class="blank _1"> </span>de <span class="blank _5"> </span>equações <span class="blank _1"> </span>daremos <span class="blank _1"> </span>o <span class="blank _1"> </span>nome <span class="blank _1"> </span>de <span class="blank _5"> </span><span class="ff7 ws0">sistemas</span>. <span class="blank _1"> </span>Ir<span class="blank _2"></span>emos <span class="blank _1"> </span>discutir <span class="blank _1"> </span>sistemas</div><div class="t m0 x1 hd ya0 ff6 fs0 fc0 sc0 ls0 ws1">linear<span class="blank _2"></span>es <span class="blank _3"> </span>de segunda <span class="blank _3"> </span>ordem, que <span class="blank _3"> </span>são <span class="blank _3"> </span>aqueles casos <span class="blank _3"> </span>que <span class="blank _3"> </span>apresentam duas <span class="blank _3"> </span>incógnitas</div><div class="t m0 x1 hd ya1 ff6 fs0 fc0 sc0 ls0 ws1">e <span class="blank _5"> </span>duas <span class="blank _1"> </span>equações. <span class="blank _5"> </span>Se <span class="blank _5"> </span>um <span class="blank _1"> </span>sistema <span class="blank _5"> </span>está <span class="blank _1"> </span>com <span class="blank _5"> </span>as <span class="blank _1"> </span>in<span class="blank _3"> </span>cógnitas <span class="blank _1"> </span>x <span class="blank _5"> </span>e <span class="blank _1"> </span>y, <span class="blank _1"> </span>nesta <span class="blank _5"> </span>ordem,</div><div class="t m0 x1 hd ya2 ff6 fs0 fc0 sc0 ls0 ws1">repr<span class="blank _2"></span>esentamos a solução por S = {(x,<span class="blank _2"></span>y)}.</div><div class="t m0 x1 hd ya3 ff6 fs0 fc0 sc0 ls0 ws1">Exist<span class="blank _0"></span>em <span class="blank _1"> </span>vár<span class="blank _2"></span>ios <span class="blank _1"> </span>mét<span class="blank _0"></span>odos <span class="blank _1"> </span>para <span class="blank _13"> </span>encontrarmos <span class="blank _13"> </span>a <span class="blank _1"> </span>solução <span class="blank _13"> </span>de <span class="blank _1"> </span>um <span class="blank _13"> </span>sistema <span class="blank _13"> </span>linear <span class="blank _13"> </span>de</div><div class="t m0 x1 hd ya4 ff6 fs0 fc0 sc0 ls0 ws1">ordem dois, aqui apresentaremos o mét<span class="blank _2"></span>odo de adição. Caro(a) aluno(a), este mét<span class="blank _2"></span>odo</div><div class="t m0 x1 hd ya5 ff6 fs0 fc0 sc0 ls0 ws1">consist<span class="blank _2"></span>e <span class="blank _15"> </span>em <span class="blank"> </span>somar <span class="blank _c"> </span>as <span class="blank"> </span>equaç<span class="blank _2"></span>ões <span class="blank _15"> </span>do <span class="blank"> </span>sist<span class="blank _0"></span>ema, <span class="blank"> </span>buscando <span class="blank _c"> </span>obter <span class="blank _15"> </span>uma <span class="blank _15"> </span>equação <span class="blank"> </span>c<span class="blank _2"></span>om</div><div class="t m0 x1 hd ya6 ff6 fs0 fc0 sc0 ls0 ws1">apenas <span class="blank _b"> </span>uma <span class="blank _b"> </span>incógnita. <span class="blank _a"> </span>Em <span class="blank _b"> </span>vários <span class="blank _b"> </span>casos <span class="blank _b"> </span>ocorr<span class="blank _2"></span>erá <span class="blank _b"> </span>a <span class="blank _b"> </span>necessidade <span class="blank _b"> </span>de <span class="blank _a"> </span>multiplicarmos</div><div class="t m0 x1 hd ya7 ff6 fs0 fc0 sc0 ls0 ws1">uma <span class="blank _16"> </span>ou <span class="blank _27"> </span>mais <span class="blank _16"> </span>equações <span class="blank _16"> </span>por <span class="blank _27"> </span>um <span class="blank _16"> </span>número <span class="blank _16"> </span>de <span class="blank _27"> </span>forma <span class="blank _16"> </span>conv<span class="blank _2"></span>enient<span class="blank _2"></span>e, <span class="blank _16"> </span>de <span class="blank _27"> </span>modo <span class="blank _16"> </span>que <span class="blank _27"> </span>uma</div><div class="t m0 x1 hd ya8 ff6 fs0 fc0 sc0 ls0 ws1">incógnita t<span class="blank _2"></span>enha coe\ue67dcient<span class="blank _2"></span>es opostos nas duas equaç<span class="blank _2"></span>ões.</div><div class="t m0 x1 h4 ya9 ff7 fs0 fc0 sc0 ls0 ws1">Ex<span class="blank _2"></span>emplo resolvido:</div><div class="t m0 x1 hd yaa ff6 fs0 fc0 sc0 ls0 ws1">Deter<span class="blank _2"></span>mine a solução do sistema <span class="blank _28"> </span>.</div><div class="t m0 x1 h4 yab ff7 fs0 fc0 sc0 ls0 ws0">Resolução:</div><div class="t m0 x1 hd yac ff6 fs0 fc0 sc0 ls0 ws1">Pelo método <span class="blank _3"> </span>de adição <span class="blank _3"> </span>devemos obter <span class="blank _3"> </span>equações equivalent<span class="blank _2"></span>e <span class="blank _3"> </span>à do <span class="blank _3"> </span>sistema de <span class="blank _3"> </span>forma</div><div class="t m0 x1 hd yad ff6 fs0 fc0 sc0 ls0 ws1">que <span class="blank _3"> </span>possamos <span class="blank _3"> </span>somar essas <span class="blank _3"> </span>equações <span class="blank _3"> </span>e, <span class="blank _3"> </span>assim, <span class="blank _3"> </span>obt<span class="blank _2"></span>ermos <span class="blank _3"> </span>uma incógnita. <span class="blank _3"> </span>Neste caso,</div><div class="t m0 x1 hd yae ff6 fs0 fc0 sc0 ls0 ws1">se optarmos em obt<span class="blank _2"></span>er o valor de <span class="ffb ws8">x</span> podemos multiplicar a primeir<span class="blank _2"></span>a equação por 2.</div><div class="t m0 x1 hd yaf ff6 fs0 fc0 sc0 ls0 ws1">Agora, somando essas duas equações t<span class="blank _0"></span>emos que:</div><div class="t m0 x1 hd yb0 ff6 fs0 fc0 sc0 ls0 ws1">Desta forma <span class="blank _3"> </span>t<span class="blank _2"></span>emos <span class="blank _29"> </span>. Logo<span class="blank _2"></span>,<span class="ffb"> x</span> <span class="blank _3"> </span>= 1. <span class="blank _3"> </span>Para obtermos o <span class="blank _3"> </span>valor de <span class="blank _3"> </span><span class="ffb ws8">y</span> <span class="blank _3"> </span>dev<span class="blank _0"></span>emos <span class="blank _3"> </span>escolher</div><div class="t m0 x1 hd yb1 ff6 fs0 fc0 sc0 ls0 ws1">uma <span class="blank _16"> </span>das <span class="blank _27"> </span>equações <span class="blank _16"> </span>e <span class="blank _16"> </span>substituir <span class="blank _27"> </span><span class="ffb">x <span class="blank _4"> </span></span>= <span class="blank _16"> </span>1, <span class="blank _27"> </span>escolheremos <span class="blank _27"> </span>a <span class="blank _27"> </span>segunda, <span class="blank _2a"> </span>. <span class="blank _27"> </span>Desta</div><div class="t m0 x1 hd yb2 ff6 fs0 fc0 sc0 ls0 ws8">forma:</div><div class="t m0 x2d h7 yaa ff12 fs2 fc0 sc0 ls0"><span class="fc1 sc0">{</span></div><div class="t m0 x20 h7 yb3 ffe fs2 fc0 sc0 ls0"><span class="fc1 sc0">3</span></div><div class="t m0 x2e h7 yb3 ff11 fs2 fc0 sc0 ls0"><span class="fc1 sc0">x</span></div><div class="t m0 x2b h7 yb3 ffe fs2 fc0 sc0 ls0 wsd"><span class="fc1 sc0">\u2212</span><span class="blank"> </span><span class="fc1 sc0">2</span></div><div class="t m0 x21 h7 yb3 ff11 fs2 fc0 sc0 ls0"><span class="fc1 sc0">y</span></div><div class="t m0 x22 h7 yb3 ffe fs2 fc0 sc0 ls0 ws10"><span class="fc1 sc0">=</span><span class="blank"> </span><span class="fc1 sc0">\u2212</span><span class="fc1 sc0">3</span></div><div class="t m0 x2f h7 yb4 ffe fs2 fc0 sc0 ls0"><span class="fc1 sc0">5</span></div><div class="t m0 x1d h7 yb4 ff11 fs2 fc0 sc0 ls0"><span class="fc1 sc0">x</span></div><div class="t m0 x30 h7 yb4 ffe fs2 fc0 sc0 ls0 wsd"><span class="fc1 sc0">+</span><span class="blank"> </span><span class="fc1 sc0">4</span></div><div class="t m0 x31 h7 yb4 ff11 fs2 fc0 sc0 ls0"><span class="fc1 sc0">y</span></div><div class="t m0 x5 h7 yb4 ffe fs2 fc0 sc0 ls0 ws10"><span class="fc1 sc0">=</span><span class="blank"> </span><span class="fc1 sc0">1</span><span class="fc1 sc0">7</span></div><div class="t m0 x32 h7 yb5 ff12 fs2 fc0 sc0 ls0"><span class="fc1 sc0">{</span></div><div class="t m0 x2e h7 yb6 ffe fs2 fc0 sc0 ls0"><span class="fc1 sc0">6</span></div><div class="t m0 x11 h7 yb6 ff11 fs2 fc0 sc0 ls0"><span class="fc1 sc0">x</span></div><div class="t m0 x33 h7 yb6 ffe fs2 fc0 sc0 ls0 wsf"><span class="fc1 sc0">\u2212</span><span class="blank"> </span><span class="fc1 sc0">4</span></div><div class="t m0 x34 h7 yb6 ff11 fs2 fc0 sc0 ls0"><span class="fc1 sc0">y</span></div><div class="t m0 x24 h7 yb6 ffe fs2 fc0 sc0 ls0 ws10"><span class="fc1 sc0">=</span><span class="blank"> </span><span class="fc1 sc0">\u2212</span><span class="fc1 sc0">6</span></div><div class="t m0 x1d h7 yb7 ffe fs2 fc0 sc0 ls0"><span class="fc1 sc0">5</span></div><div class="t m0 x35 h7 yb7 ff11 fs2 fc0 sc0 ls0"><span class="fc1 sc0">x</span></div><div class="t m0 x36 h7 yb7 ffe fs2 fc0 sc0 ls0 wsf"><span class="fc1 sc0">+</span><span class="blank"> </span><span class="fc1 sc0">4</span></div><div class="t m0 x22 h7 yb7 ff11 fs2 fc0 sc0 ls0"><span class="fc1 sc0">y</span></div><div class="t m0 x37 h7 yb7 ffe fs2 fc0 sc0 ls0 ws10"><span class="fc1 sc0">=</span><span class="blank"> </span><span class="fc1 sc0">1</span><span class="fc1 sc0">7</span></div><div class="t m0 x32 h7 yb8 ff12 fs2 fc0 sc0 ls0"><span class="fc1 sc0">{</span></div><div class="t m0 x2e h7 yb9 ffe fs2 fc0 sc0 ls0"><span class="fc1 sc0">6</span></div><div class="t m0 x11 h7 yb9 ff11 fs2 fc0 sc0 ls0"><span class="fc1 sc0">x</span></div><div class="t m0 x33 h7 yb9 ffe fs2 fc0 sc0 ls0 wsf"><span class="fc1 sc0">\u2212</span><span class="blank"> </span><span class="fc1 sc0">4</span></div><div class="t m0 x34 h7 yb9 ff11 fs2 fc0 sc0 ls0"><span class="fc1 sc0">y</span></div><div class="t m0 x24 h7 yb9 ffe fs2 fc0 sc0 ls0 ws10"><span class="fc1 sc0">=</span><span class="blank"> </span><span class="fc1 sc0">\u2212</span><span class="fc1 sc0">6</span></div><div class="t m0 x1d h7 yba ffe fs2 fc0 sc0 ls0"><span class="fc1 sc0">5</span></div><div class="t m0 x35 h7 yba ff11 fs2 fc0 sc0 ls0"><span class="fc1 sc0">x</span></div><div class="t m0 x36 h7 yba ffe fs2 fc0 sc0 ls0 wsf"><span class="fc1 sc0">+</span><span class="blank"> </span><span class="fc1 sc0">4</span></div><div class="t m0 x22 h7 yba ff11 fs2 fc0 sc0 ls0"><span class="fc1 sc0">y</span></div><div class="t m0 x37 h7 yba ffe fs2 fc0 sc0 ls0 ws10"><span class="fc1 sc0">=</span><span class="blank"> </span><span class="fc1 sc0">1</span><span class="fc1 sc0">7</span></div><div class="t m0 x32 h7 ybb ffe fs2 fc0 sc0 ls0 ws1"><span class="fc1 sc0">\u2013</span><span class="blank _2b"></span><span class="fc1 sc0">\u2013</span><span class="blank _2b"></span><span class="fc1 sc0">\u2013</span><span class="blank _2c"></span><span class="fc1 sc0">\u2013</span><span class="blank _2c"></span><span class="fc1 sc0">\u2013</span><span class="blank _2b"></span><span class="fc1 sc0">\u2013</span><span class="blank _2c"></span><span class="fc1 sc0">\u2013</span><span class="blank _2b"></span><span class="fc1 sc0">\u2013</span><span class="blank _2c"></span><span class="fc1 sc0">\u2013</span><span class="blank _2b"></span><span class="fc1 sc0">\u2013</span><span class="blank _2c"></span><span class="fc1 sc0">\u2013</span><span class="blank _2b"></span><span class="fc1 sc0">\u2013</span><span class="blank _2c"></span><span class="fc1 sc0">\u2013</span><span class="blank _2b"></span><span class="fc1 sc0">\u2013</span><span class="blank _2c"></span><span class="fc1 sc0">\u2013</span><span class="blank _2b"></span><span class="fc1 sc0">\u2013</span><span class="blank _2c"></span><span class="fc1 sc0">\u2013</span><span class="fc1 sc0">\u2013</span></div><div class="t m0 x32 h7 ybc ffe fs2 fc0 sc0 ls0 ws1"><span class="fc1 sc0">1</span><span class="fc1 sc0">1</span></div><div class="t m0 x1d h7 ybc ff11 fs2 fc0 sc0 ls0"><span class="fc1 sc0">x</span></div><div class="t m0 x30 h7 ybc ffe fs2 fc0 sc0 ls0 ws10"><span class="fc1 sc0">=</span><span class="blank"> </span><span class="fc1 sc0">1</span><span class="fc1 sc0">1</span></div><div class="t m0 x15 h7 yb0 ff11 fs2 fc0 sc0 ls0"><span class="fc1 sc0">x</span></div><div class="t m0 x38 h12 yb0 ffe fs2 fc0 sc0 ls9"><span class="fc1 sc0">=</span><span class="fs1 ls0 ws1 v2"><span class="fc1 sc0">1</span><span class="fc1 sc0">1</span></span></div><div class="t m0 x39 h5 ybd ffe fs1 fc0 sc0 ls0 ws12"><span class="fc1 sc0">1</span><span class="fc1 sc0">1</span><span class="blank"> </span><span class="fs2 v8"><span class="fc1 sc0">5</span></span></div><div class="t m0 x3a h7 yb1 ff11 fs2 fc0 sc0 ls0"><span class="fc1 sc0">x</span></div><div class="t m0 x3b h7 yb1 ffe fs2 fc0 sc0 ls0 wsd"><span class="fc1 sc0">+</span><span class="blank"> </span><span class="fc1 sc0">4</span></div><div class="t m0 x3c h7 yb1 ff11 fs2 fc0 sc0 ls0"><span class="fc1 sc0">y</span></div><div class="t m0 x3d h7 yb1 ffe fs2 fc0 sc0 ls0 ws10"><span class="fc1 sc0">=</span><span class="blank"> </span><span class="fc1 sc0">1</span><span class="fc1 sc0">7</span></div></div></div><div class="pi" data-data="{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}"></div></div> <div id="pf8" class="pf w0 h0" data-page-no="8"><div class="pc pc8 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x0 y0 w1 h1" alt="" src="https://files.passeidireto.com/6ccd0e70-466b-42b0-aeb8-73a512191ddb/bg8.png"><div class="c x0 ybe w2 h18"><div class="t m0 x1 hd ybf ff6 fs0 fc0 sc0 ls0 ws1">C<span class="blank _2"></span>oncluímos que a solução do sistema é S = {(1, 3)}.</div><div class="t m0 x1 ha yc0 ff13 fs3 fc3 sc0 ls0 ws1"><span class="fc1 sc0">In</span><span class="fc1 sc0">e</span><span class="fc1 sc0">quaç</span><span class="fc1 sc0">õ</span><span class="fc1 sc0">e</span><span class="fc1 sc0">s</span></div><div class="t m0 x1 h4 yc1 ff6 fs0 fc0 sc0 ls0 ws1">Chamamos <span class="blank _13"> </span>de <span class="blank _1"> </span><span class="ff7">desigualdade <span class="blank _15"> </span></span>uma <span class="blank _1"> </span>expr<span class="blank _2"></span>essão <span class="blank _1"> </span>que <span class="blank _1"> </span>estabelece <span class="blank _13"> </span>uma <span class="blank _1"> </span>ordem <span class="blank _1"> </span>entr<span class="blank _2"></span>e</div><div class="t m0 x1 hd yc2 ff6 fs0 fc0 sc0 ls0 ws1">elementos. <span class="blank _1"> </span>No <span class="blank _5"> </span>conjunt<span class="blank _2"></span>o <span class="blank _1"> </span>dos <span class="blank _5"> </span>números <span class="blank _5"> </span>r<span class="blank _2"></span>eais, <span class="blank _1"> </span>quando <span class="blank _5"> </span>pret<span class="blank _2"></span>endemos <span class="blank _5"> </span>indicar <span class="blank _1"> </span>uma</div><div class="t m0 x1 hd yc3 ff6 fs0 fc0 sc0 ls0 ws1">desigualdade <span class="blank _16"> </span>usamos <span class="blank _16"> </span>um <span class="blank _16"> </span>dos <span class="blank _16"> </span>símbolos: <span class="blank _16"> </span>>, <span class="blank _16"> </span>que <span class="blank _16"> </span>signi\ue67dca <span class="blank _16"> </span>maior <span class="blank _4"> </span>que, <span class="blank _16"> </span><, <span class="blank _16"> </span>que <span class="blank _16"> </span>signi\ue67dca</div><div class="t m0 x1 hd yc4 ff6 fs0 fc0 sc0 ls0 ws1">menor <span class="blank"> </span>que, <span class="blank _2d"> </span> <span class="blank"> </span>para <span class="blank"> </span>representar <span class="blank"> </span>maior <span class="blank"> </span>ou <span class="blank"> </span>igual <span class="blank"> </span>a, <span class="blank"> </span>e <span class="blank _13"> </span>\ue6d0<span class="blank _2d"> </span> <span class="blank _13"> </span>para <span class="blank"> </span>menor <span class="blank _13"> </span>ou <span class="blank"> </span>igual <span class="blank _13"> </span>a.</div><div class="t m0 x1 hd yc5 ff6 fs0 fc0 sc0 ls0 ws1">T<span class="blank _2"></span>ambém podemos incluir o símbolo <span class="blank _2e"> </span> para r<span class="blank _2"></span>epresentar difer<span class="blank _2"></span>ent<span class="blank _2"></span>e.</div><div class="t m0 x1 hd yc6 ff6 fs0 fc0 sc0 ls0 ws1">Dados <span class="blank _16"> </span>a, <span class="blank _16"> </span>x <span class="blank _27"> </span>e <span class="blank _16"> </span>y<span class="blank _2"></span>, <span class="blank _16"> </span>números <span class="blank _16"> </span>re<span class="blank _2"></span>ais, <span class="blank _16"> </span>então <span class="blank _16"> </span>a <span class="blank _27"> </span>desigualdade <span class="blank _16"> </span>tem <span class="blank _4"> </span>como <span class="blank _16"> </span>propriedades <span class="blank _16"> </span>(< <span class="blank _16"> </span>e <span class="blank _27"> </span>></div><div class="t m0 x1 hd yc7 ff6 fs0 fc0 sc0 ls0 ws1">podem ser substituídos por <span class="ffd ws7">\u2264</span> e por <span class="ffd ls1">\u2265</span><span class="ws8">):</span></div><div class="t m0 x19 hd yc8 ff6 fs0 fc0 sc0 ls0 ws1">1<span class="blank _2"></span>. <span class="blank _3"> </span>x > y \ue6d0<span class="ff9 ws7">\u21d2</span>x + a > y + a</div><div class="t m0 x1b hd yc9 ff6 fs0 fc0 sc0 ls0 ws1">2<span class="blank _0"></span>. <span class="blank _4"> </span>x > y \ue6d0<span class="ff9 ws7">\u21d2</span>x \u2013 a > y \u2013 a</div><div class="t m0 x1b hd yca ff6 fs0 fc0 sc0 ls0 ws1">3<span class="blank _0"></span>. <span class="blank _4"> </span>a > 0 \ue6d0<span class="ff9 ws7">\u21d2</span>x > y então ax > ay</div><div class="t m0 x1b hd ycb ff6 fs0 fc0 sc0 ls0 ws1">4. a < 0 \ue6d0<span class="ff9 ws7">\u21d2<span class="blank _2"></span><span class="ff6 ws1">x > y então ax < ay</span></span></div><div class="t m0 x1 h4 ycc ff6 fs0 fc0 sc0 ls0 ws1">Ainda, <span class="blank"> </span>damos <span class="blank _13"> </span>o <span class="blank _13"> </span>nome <span class="blank"> </span>de <span class="blank _13"> </span><span class="ff7 ws0">inequa<span class="blank _3"> </span>ção</span> <span class="blank"> </span>à <span class="blank _13"> </span>desigualdade <span class="blank _13"> </span>literal <span class="blank"> </span>que <span class="blank _13"> </span>é <span class="blank _13"> </span>satisfeita <span class="blank"> </span>por</div><div class="t m0 x1 hd ycd ff6 fs0 fc0 sc0 ls0 ws1">valor<span class="blank _2"></span>es <span class="blank"> </span>especí\ue67dcos <span class="blank _13"> </span>para <span class="blank"> </span>suas <span class="blank _13"> </span>incógnitas. <span class="blank _13"> </span>Pode <span class="blank"> </span>também <span class="blank _13"> </span>ser <span class="blank _13"> </span>de\ue67dnida <span class="blank _13"> </span>como <span class="blank _13"> </span>uma</div><div class="t m0 x1 hd yce ff6 fs0 fc0 sc0 ls0 ws1">sentença <span class="blank _16"> </span>matemática <span class="blank _16"> </span>expressas <span class="blank _16"> </span>por <span class="blank _16"> </span>um <span class="blank _27"> </span>dos <span class="blank _27"> </span>sinais <span class="blank _27"> </span>de <span class="blank _27"> </span>desigualdade, <span class="blank _27"> </span>fat<span class="blank _2"></span>o <span class="blank _27"> </span>que <span class="blank _27"> </span>a <span class="blank _16"> </span>faz</div><div class="t m0 x1 hd ycf ff6 fs0 fc0 sc0 ls0 ws1">difer<span class="blank _2"></span>enciar-se <span class="blank _27"> </span>da <span class="blank _b"> </span>equação <span class="blank _b"> </span>que <span class="blank _b"> </span>representa <span class="blank _27"> </span>relações <span class="blank _27"> </span>de <span class="blank _b"> </span>equivalência. <span class="blank _27"> </span>As <span class="blank _b"> </span>inequações</div><div class="t m0 x1 hd yd0 ff6 fs0 fc0 sc0 ls0 ws1">são <span class="blank _4"> </span>usadas <span class="blank _4"> </span>em <span class="blank _4"> </span>experiências, <span class="blank _4"> </span>estatísticas, <span class="blank _4"> </span>análise <span class="blank _4"> </span>de <span class="blank _4"> </span>dados <span class="blank _4"> </span>e <span class="blank _4"> </span>comparações, <span class="blank _3"> </span>ela <span class="blank _16"> </span>serve</div><div class="t m0 x1 hd yd1 ff6 fs0 fc0 sc0 ls0 ws1">de recurso da linguagem par<span class="blank _2"></span>a organizar pr<span class="blank _2"></span>oblemas.</div><div class="t m0 x1 hd yd2 ff6 fs0 fc0 sc0 ls0 ws1">Deter<span class="blank _2"></span>minar <span class="blank"> </span>a <span class="blank"> </span>solução <span class="blank _13"> </span>de <span class="blank"> </span>uma <span class="blank"> </span>inequação <span class="blank _13"> </span>é <span class="blank"> </span>obter <span class="blank"> </span>os <span class="blank"> </span>valor<span class="blank _2"></span>es <span class="blank"> </span>das <span class="blank"> </span>incógnitas <span class="blank"> </span>que</div><div class="t m0 x1 hd yd3 ff6 fs0 fc0 sc0 ls0 ws1">satisfazem <span class="blank _13"> </span>a <span class="blank _1"> </span>desigualdade, <span class="blank _1"> </span>t<span class="blank _0"></span>ornando<span class="blank _3"> </span>-a, <span class="blank _13"> </span>assim, <span class="blank _1"> </span>uma <span class="blank _1"> </span>e<span class="blank _2"></span>xpressão <span class="blank _13"> </span>numérica. <span class="blank _1"> </span>Iremos</div><div class="t m0 x1 hd yd4 ff6 fs0 fc0 sc0 ls0 ws1">trabalhar<span class="blank _2"></span>, nas unidades seguintes desse mat<span class="blank _2"></span>erial v<span class="blank _2"></span>ários tipos de inequações.</div><div class="t m0 x1 h4 yd5 ff7 fs0 fc0 sc0 ls0 ws0">Ex<span class="blank _2"></span>emplos:</div><div class="t m0 x19 hd yd6 ff6 fs0 fc0 sc0 ls0 ws1">1<span class="blank _2"></span>. <span class="blank _3"> </span>As expressões 2<span class="blank _2"></span>x + 9 > 0, x2 \u2013 8x <span class="ffd ws7">\u2264</span> 0<span class="blank _2"></span>, 6x + 7 <span class="ffd ls1">\u2264</span> 0 são inequações.</div><div class="t m0 x1b hd yd7 ff6 fs0 fc0 sc0 ls0 ws1">2<span class="blank _0"></span>. <span class="blank _4"> </span>A <span class="blank _4"> </span>\ue67dgura <span class="blank _3"> </span>a <span class="blank _4"> </span>seguir <span class="blank _4"> </span>mostra <span class="blank _3"> </span>uma <span class="blank _4"> </span>balança <span class="blank _4"> </span>ao <span class="blank _3"> </span>\ue67dnal <span class="blank _4"> </span>de <span class="blank _4"> </span>uma <span class="blank _4"> </span>pesagem. <span class="blank _4"> </span>Em <span class="blank _3"> </span>cada <span class="blank _4"> </span>um</div><div class="t m0 x1a hd yd8 ff6 fs0 fc0 sc0 ls0 ws1">dos <span class="blank _8"> </span>pratos, <span class="blank _8"> </span>há <span class="blank _8"> </span>um <span class="blank _8"> </span>peso <span class="blank _21"> </span>de <span class="blank _8"> </span>valor <span class="blank _8"> </span>conhecido <span class="blank _8"> </span>e <span class="blank _8"> </span>esferas <span class="blank _8"> </span>de <span class="blank _8"> </span>peso <span class="blank _8"> </span>x, <span class="blank _21"> </span>t<span class="blank _2"></span>odos</div><div class="t m0 x1a hd yd9 ff6 fs0 fc0 sc0 ls0 ws1">repr<span class="blank _2"></span>esentados na mesma unidade de medida.</div><div class="t m0 x3e h7 yda ffe fs2 fc0 sc0 ls0 wsd"><span class="fc1 sc0">5</span><span class="fc1 sc0">.</span><span class="fc1 sc0">1</span><span class="blank"> </span><span class="fc1 sc0">+</span><span class="blank"> </span><span class="fc1 sc0">4</span></div><div class="t m0 x3f h7 yda ff11 fs2 fc0 sc0 ls0"><span class="fc1 sc0">y</span></div><div class="t m0 x22 h7 yda ffe fs2 fc0 sc0 ls0 ws10"><span class="fc1 sc0">=</span><span class="blank"> </span><span class="fc1 sc0">1</span><span class="fc1 sc0">7</span></div><div class="t m0 x3e h7 ydb ffe fs2 fc0 sc0 ls0 wsf"><span class="fc1 sc0">5</span><span class="blank"> </span><span class="fc1 sc0">+</span><span class="blank"> </span><span class="fc1 sc0">4</span></div><div class="t m0 x36 h7 ydb ff11 fs2 fc0 sc0 ls0"><span class="fc1 sc0">y</span></div><div class="t m0 x3f h7 ydb ffe fs2 fc0 sc0 ls0 ws10"><span class="fc1 sc0">=</span><span class="blank"> </span><span class="fc1 sc0">1</span><span class="fc1 sc0">7</span></div><div class="t m0 x3e h7 ydc ffe fs2 fc0 sc0 ls0"><span class="fc1 sc0">4</span></div><div class="t m0 x40 h7 ydc ff11 fs2 fc0 sc0 ls0"><span class="fc1 sc0">y</span></div><div class="t m0 x11 h7 ydc ffe fs2 fc0 sc0 ls0 wsf"><span class="fc1 sc0">=</span><span class="blank _1"> </span><span class="fc1 sc0">1</span><span class="fc1 sc0">7</span><span class="blank"> </span><span class="fc1 sc0">\u2212</span><span class="blank"> </span><span class="fc1 sc0">5</span></div><div class="t m0 x3e h7 ydd ffe fs2 fc0 sc0 ls0"><span class="fc1 sc0">4</span></div><div class="t m0 x40 h7 ydd ff11 fs2 fc0 sc0 ls0"><span class="fc1 sc0">y</span></div><div class="t m0 x11 h7 ydd ffe fs2 fc0 sc0 ls0 ws10"><span class="fc1 sc0">=</span><span class="blank"> </span><span class="fc1 sc0">1</span><span class="fc1 sc0">2</span></div><div class="t m0 x3e h7 yde ff11 fs2 fc0 sc0 ls0"><span class="fc1 sc0">y</span></div><div class="t m0 x2e h7 yde ffe fs2 fc0 sc0 ls0 ws13"><span class="fc1 sc0">=</span><span class="blank"> </span><span class="fc1 sc0">\u21d2</span></div><div class="t m0 x37 h7 yde ff11 fs2 fc0 sc0 ls0"><span class="fc1 sc0">y</span></div><div class="t m0 x41 h7 yde ffe fs2 fc0 sc0 ls0 ws10"><span class="fc1 sc0">=</span><span class="blank"> </span><span class="fc1 sc0">3</span></div><div class="t m0 x2c h5 ydf ffe fs1 fc0 sc0 ls0 ws1"><span class="fc1 sc0">1</span><span class="fc1 sc0">2</span></div><div class="t m0 x36 h5 ye0 ffe fs1 fc0 sc0 ls0"><span class="fc1 sc0">4</span></div><div class="t m0 x42 h7 yc4 ffe fs2 fc0 sc0 ls0 ws14"><span class="fc1 sc0">\u2265</span><span class="blank"> </span><span class="fc1 sc0">\u2264</span></div><div class="t m0 x4 h7 yc5 ffe fs2 fc0 sc0 ls0"><span class="fc1 sc0">\u2260</span></div></div></div><div class="pi" data-data="{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}"></div></div> <div id="pf9" class="pf w0 h0" data-page-no="9"><div class="pc pc9 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x0 ye1 w1 h19" alt="" src="https://files.passeidireto.com/6ccd0e70-466b-42b0-aeb8-73a512191ddb/bg9.png"><div class="c x0 y6e w2 h10"><div class="t m0 x1 hd ye2 ff6 fs0 fc0 sc0 ls0 ws1">Podemos e<span class="blank _2"></span>xpressar a situação atra<span class="blank _2"></span>vés da inequação 3x + 5 > 2<span class="blank _2"></span>x + 8.</div></div></div><div class="pi" data-data="{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}"></div></div> <div id="pfa" class="pf w0 h0" data-page-no="a"><div class="pc pca w0 h0"><img fetchpriority="low" loading="lazy" class="bi x0 y0 w3 h1" alt="" src="https://files.passeidireto.com/6ccd0e70-466b-42b0-aeb8-73a512191ddb/bga.png"><div class="c x0 y1 w2 h2"><div class="t m0 x14 ha y31 ff14 fs3 fc2 sc0 ls0 ws1"><span class="fc1 sc0">T</span><span class="blank _2f"></span><span class="fc1 sc0">e</span><span class="fc1 sc0">or</span><span class="fc1 sc0">ia </span><span class="fc1 sc0">d</span><span class="fc1 sc0">os </span><span class="fc1 sc0">Co</span><span class="fc1 sc0">njun</span><span class="blank _2"></span><span class="fc1 sc0">t</span><span class="blank _2"></span><span class="fc1 sc0">os</span></div><div class="t m0 x15 h1a y32 ff15 fs4 fc2 sc0 ls0 ws5">AU<span class="blank _2"></span>TORIA</div><div class="t m0 x15 hc y33 ff16 fs5 fc2 sc0 ls0 ws1">Luciano Xa<span class="blank _2"></span>vier de Azev<span class="blank _0"></span>edo</div></div><a class="l" data-dest-detail="[10,"XYZ",56,799.92,null]"><div class="d m1" style="border-style:none;position:absolute;left:101.000008px;bottom:700.169980px;width:393.000022px;height:43.500000px;background-color:rgba(255,255,255,0.000001);"></div></a></div><div class="pi" data-data="{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}"></div></div>
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