Estudos Disciplinares resolvendo

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Estudos Disciplinares
1- E....
Fm=P
K*Ym=m*g
K*0,05=4*10
K=800(N/m)
EM=Ym*K*(Ym)2
EM=0,5*800*0,052
EM=1 J
2- B
EM=EC+EP
1=0,5*m*v2+0,5*k*x2
1=0,5*4*v2+0,5*800*0,022
2v2=0,84
V=√(0,84/2)
V=0,6480 m/s
3- D
W=2*pi*f
W=2*pi*2,5
W=15,71 
Ym=√(y(0)2+(v(0)/w0)2)
Ym=√ (0,0112+(0,011/15,71)2)
Ym=0,01102 m
Ym=1,102 cm ~ 1,46 cm
4- A
Vm=ym*w
Vm=1,46*15,71
Vm=22,94 cm/s
5-D
-Fm-Fv=Fr
-y*K-v*b=m*a
-y*3200-v*640-80*a=0 (/80)
-y*400-v*8-a=0
Y=e-4t*(A*cos(19,6t)+B*sem(19,6t)) derivar
V=-4*e-4t*(A*cos(19,6t)+B*sem(19,6t))+ 
e-4t*(A*cos(19,6t)+B*sem(19,6t))
Y= e-4t*(0,492*cos(19,6t)+0,609*sem(19,6t))
Y(0,4)= 
e-4*0,4*(0,492*cos(19,6*0,4)+0,609*sem(19,6*0,4))
Y(0,4)= 0,202*(0,0069+0,6089)
Y(0,4)= 0,124 m
6- E
0= e-4t*(0,492*cos(19,6t)+0,609*sem(19,6t))
-0,492*cos(19,6t)+0,609*sem(19,6t)
-0,492/0,609=tg(19,6t)
Tg(19,6t)=-0,808
19,6t=-0,679
T=0,1256 s
7- D
0,5*b/m=√(k/m)
0,5*b/80=√ (32000/80)
0,00625*b=20
B=3200 N*s/m
8- B
Y=(c1+c2*t)*e-g*t
G=0,5*b/m
G=20
0,1=( c1+c2*0)* e-20*0
0,1=(c1+0)*1
C1=0,1
V=c2*e-g*t+(0,1+c2*t)*(-20)*e-20*0t
2=c2*e-g*0+(0,1+c2*0)*(-20)*e-20*0
2=c2-2
C2=4
Y=(0,1+4*t)*e-20*0t
0=(0,1+4*t)*e-20*0t
0=0,1+4*t
-0,1=4*t
T=-0,025 s
0,001=e-20*0t
-6,9077= e-20*t
t=0,345 s
t=0,345-(-0,025)
t=0,37 s
9- c
A= 2*ym*cos((pi/4)*0,5)
A=2*1*cos(pi/8)
A=1,85 mm
10- D
2=2*1*cos(0*0,5)
1=cos(0,5*0)
0,5*0=arccos(1)
0=0
11-A
Y=15*sem(pi*x/4)*cos(30*pi*t+pi/3)
Vt=15*sem(pi*x/4)*(-30*pi)sem(30*pi+pi/3)
Vt=-1414*sen(pi*x/4)*sem(30*pi+pi/3)
Vt(2;2)=-1414*sem(pi*2/4)*sem(30*pi*2+pi/3)
Vt(2;2)=-1225 cm/s
12-E
Y=15*sen9pi*x/4)*cos(30*pi*t+pi/3)
A=15*sem(pi*x/4)
A(2;2)=15*sem(pi*2/4)
A(2;2)=15 cm
13-c
D1=2,6*0,01= 0,026 g/cm = 0,0026 kg/m
D2=7,8*0,01= 0,078 g/cm = 0,0078 kg/m
F1= (n1/(2*L1))*√(f/d1)
F2= (n2/(2*L2))*√(f/d2)
(n1/(2*0,6))*√(100/0,0026)= (n2/(2*0,866))*√(100/0,0078)
N1=√ (3,74*(n2)2*/23,4)
N1= 0,4*n2
N2=2,5*n1
N2/n1=2,5
N2/n1=2/5
N1=2
N2=5
F=√(n1/(2*L1))*(f/d1))
F=1034hz
14- E
No exercício anterior determinou-se o número de ventre de cada parte da corda temos o numero total de nos é 8, descontando os nós das extremidades, então o Nnós=6
15-D
F=0,2*t*(Pi*r2)=0,2*t*(3,14*3,992)
F=-10*t
E= df/dt= │-10│
Feletromotriz=10 V
16- B
F=-0,08*(PI*3,992)*t
F=-4*t
E=4V
E=R*I
4=20*I
I=0,2 A no sentido horário 
17- E
Req=R1*R2/(R1+R2)
Req=10*15/(10+15)
Req=6 ohm
I=(B*I/Req)*V
I=(0,5*0,4/6)*20
I=0,667 A
18-B 
P=I2*Req
P=0,6672*6
P=2,67 W
19- D
C=W/K
K=1015/3*108
K=3,33*106
Cv=Ev*Bv/(Bv*Bv)
-3,108*i=((E*K)*(10-7*sem(1015*t+3,33*106*x)2)
(3,108*K)*(10-7*sem(1015*t+3,33*106*X)=E*K
E=30*sem(1015*t+3,33*106*X) (N/C)
Ev=30*sem(1015*t+3,33*106*x)*K (N/C)
20-A
S=0,5*8,85*10-12*3*108*900
S=1,19
Dw=S*A*Dt
Dw=1,19*3*7200
Dw=25807 J
21-A
F=B*n*a
F=(0,2*t2-2,4*t+6,4)k*(0,5*0,5)
F(2)= (0,2(2)2-2,4*(2)+6,4)*0,25
F(2)= 0,6 W
F(9)= (0,2(9)2-2,4*(9)+6,4)*0,25
F(9)=0,25 W
22-E 
E=-(0,1*t-0,6)
E(2)=-(0,1*(2)-0,6)
E(2)= 0,4 V
I(2)=0,4/40
I(2)= 0,01 A (anti-horário)
E(9)=-(0,1*(9)-0,6)
E(9)=-0,3 V
I(9)= 0,3/40
I(9)=-0,0075 A (horário)
23-B
F=b*a
A=0,5*W*t*r2
A=0,5*300*t*0,252
A=9,375 m2
F=0,1*9,375*t
F=0,9375 w
24-C
Vp2-vp1=0 V
25-D
F=B*n*a
F=(0,5-0,125t)*1,7*2,1
F=1,785-0,44625 t
E=0,4625
I=0,44625/25
I=0,01785 A (anti-horário) 
26-B
F=I*L*b
F=0,01785*1,7*0,5
F=0,152 N
O sentido é contrario 
F=-0,0152 N
27-C
I=P/A
I=(e*c*Em2)/2)
0,25/(4*pi*r2)=(8,85*10-12*3*108*0,22)/2
R2=370
R=19,4 m
28-E
Bv=+kB
29-A
V=(i0*k
V=-j
30-E
C=(E*B)/(B*B)
3*108=E/B
E=3*108*91,5*106
E= 27450 V/m
31-A
I=P/A
I=0,02/(pi*10-12)
I=6,366*109
6,366*109=0,5*8,85*10-12*3*108*Em2
Em2= 4,796*1012
Em=2,19*106 v/m
32-A
B=E/c
B=1,10*10-6/(3*108)
B=3,7*10-3 T
│c│=│E│*│B│
-k=j*(ai+bj+ck)
-k=-ka+ic
C=0
A=1
B=3,7*sem(5,9*106*z+1,77*1015*t)*i (Wb/m2)
33-B
A curva é característica de um amortecimento fraco, visto que oscila antes de estabilizar. A curva B estabiliza o movimento antes que a curva A, porem apenas que a curva C, isso ocorrer devido ao alto valor do coeficiente de resistência viscosa, logo a curva B, é característica de um amortecimento supercrítico.
A curva C é a primeira a estabilizar, característica do amortecimento crítico. 
A, C, B.
34-C 
Y(0)=0,2 m
V(0)=(0,5-0,2)/0,2
V(0)=1,5 m/s
35-E
Ym=e-y0=0,4 m
0,2=0,4*cos(0)
0=arcos(0,5)
0=-pi/3
W=2*pi/1,4
W=1,43*pi (rad/s)
-0,2=0,4*e-y*cos(1,43*pi-pi/3)
-0,5=-e-y*0,954
1/1,84=e-y
-y=-0,61 * (-1)
Y=0,61
Y=0,4*e(-0,61*t)*cos(1,43*pi*t-pi/3) SI
36- B
W2=(w0)2-g2
(1,43*pi)2=(w0)2-(0,61)2
(W0)2=20,55
W0=4,5 rad/s
(4,5)2=k/m
(4,5)2*0,8=k
K=16,44 N/m
0,61=c/(2*0,8)
C=0,976 N*s/m
B=g/w0=0,61/4,5
B=0,135
37- C
G=√(k/m)
G=√(16,43/0,8)
G=4,53
G=c/2m
4,53=c/(2*0,8)
C=7,25 N/(m/s)
38-A
0,2=A1
1,5=(-4,53*0,2+A2)
A2=2,41
Y=(0,2+2,41*t)*e-4,53t SI
39- A
1,2836=g/W0
G=c/2m
W0=√(K/m)
1,2836=(c/2m)*√(m/K)
1,6476=(c2/2,56)*(0,8/16,43)
86,624=c2
C=9,307 N/(m/s)
40- B
W0=√(16,43/0,8)
W0=4,532 rad/s
G=9,307/1,6
G=5,817
0,2=A1+A2
A2=0,2-A1
1,5=A1*√(-5,817+(5,8172-4,5322)+A2*(-5,817-(√(5,8172-4,5322))
1,5=A1*√(-5,817+(5,8172-4,5322)+(0,2-A1)*(-5,817-(√(5,8172-4,5322))
1,5=A1*(-2,1703)+(0,2-A1)*(-9,4637)
3,393=7,2934*A1
A1=0,465
A2=0,2-0,465
A2=-0,265
Y=0,465*e(-5,817+3,6467)*t-0,265*e(-5,817-3,6467)*t
Y=0,465*e(-2,17)*t-0,265*e(-9,46)*t SI