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PROBLEM
4-3
3-Ethyl-1,1-dimethylcyclopentane
PROBLEM
4-4
(a) trans-1-Chloro-4-methylcyclohexane (b) cis-1-Ethyl-3-methylcycloheptane
PROBLEM
4-5
(a) (b) (c)
PROBLEM
4-6
The two hydroxyl groups are cis. The two side chains are trans.
PROBLEM
4-7
(a) cis-1,2-Dimethylcyclopentane (b) cis-1-Bromo-3-methylcyclobutane
PROBLEM
4-8
Six interactions; 21% of strain
PROBLEM
4-9
The cis isomer is less stable because the methyl groups nearly eclipse each other.
PROBLEM
4-10
Ten eclipsing interactions; 40 kJ/mol; 35% is relieved.
PROBLEM
4-11
Conformation (a) is more stable because the methyl groups are farther apart.
PROBLEM
4-12
PROBLEM
4-13
PROBLEM
4-14
Before the ring-flip, red and blue are equatorial and green is axial. After the ring-flip, red and blue
are axial and green is equatorial.
PROBLEM
4-15
4.2 kJ/mol
PROBLEM
4-16
Cyano group points straight up.
PROBLEM
4-17
Equatorial = 70%; axial = 30%
PROBLEM
4-18
(a) 2.0 kJ/mol (axial Cl) (b) 11.4 kJ/mol (axial CH3) (c) 2.0 kJ/mol (axial Br)
(d) 8.0 kJ/mol (axial CH2CH3)
PROBLEM
4-19
PROBLEM
4-20
trans-Decalin is more stable because it has no 1,3-diaxial interactions.
PROBLEM
4-21
Both ring-fusions are trans.
Chapter 5
PROBLEM Chiral: screw, shoe
Answer Key 1193
5-1
PROBLEM
5-2
(a) (b) (c)
PROBLEM
5-3
PROBLEM
5-4
(a) (b)
PROBLEM
5-5
Levorotatory
PROBLEM
5-6
+16.1°
PROBLEM
5-7
(a) −Br (b) −Br (c) −CH2CH3 (d) −OH (e) −CH2OH (f) −CH O
PROBLEM
5-8
(a) −OH, −CH2CH2OH, −CH2CH3, −H (b) −OH, −CO2CH3, −CO2H, −CH2OH
(c) −NH2, −CN, −CH2NHCH3, −CH2NH2 (d) −SSCH3, −SH, −CH2SCH3, −CH3
PROBLEM
5-9
(a) S (b) R (c) S
PROBLEM
5-10
(a) S (b) S (c) R
PROBLEM
5-11
PROBLEM
5-12
S
PROBLEM
5-13
Compound (a) is D-erythrose 4-phosphate, (d) is its enantiomer, and (b) and (c) are diastereomers.
PROBLEM
5-14
Five chirality centers and 25 = 32 stereoisomers
PROBLEM
5-15
S,S
PROBLEM
5-16
Compounds (a) and (d) are meso.
PROBLEM
5-17
Compounds (a) and (c) have meso forms.
PROBLEM
5-18
PROBLEM
5-20
Two diastereomeric salts: (R)-lactic acid plus (S)-1-phenylethylamine and (S)-lactic acid plus
(S)-1-phenylethylamine
1194 Answer Key
Access for free at openstax.org
PROBLEM
5-21
(a) Constitutional isomers (b) Diastereomers
PROBLEM
5-22
(a) (b)
PROBLEM
5-23
(a) (b)
PROBLEM
5-24
(S)-Lactate
PROBLEM
5-25
The −OH adds to the Re face of C2, and −H adds to the Re face of C3. The overall addition has anti
stereochemistry.
Chapter 6
PROBLEM
6-1
(a) Substitution (b) Elimination (c) Addition
PROBLEM
6-2
(a) Carbon is electrophilic. (b) Sulfur is nucleophilic. (c) Nitrogens are nucleophilic.
(d) Oxygen is nucleophilic; carbon is electrophilic.
PROBLEM
6-3
PROBLEM
6-4
Bromocyclohexane; chlorocyclohexane
PROBLEM
6-5
The mechanism is shown in Figure 6.4
PROBLEM
6-6
(a)
(b)
(c)
Answer Key 1195
PROBLEM
6-7
PROBLEM
6-8
1-Chloro-2-methylpentane, 2-chloro-2-methylpentane, 3-chloro-2-methylpentane,
2-chloro-4-methylpentane, 1-chloro- 4-methylpentane
PROBLEM
6-9
PROBLEM
6-10
Negative ΔG° is favored.
PROBLEM
6-11
Larger Keq is more exergonic.
PROBLEM
6-12
Lower ΔG‡ is faster.
PROBLEM
6-13
Chapter 7
PROBLEM
7-1
(a) 1 (b) 2 (c) 2
PROBLEM
7-2
(a) 5 (b) 5 (c) 3 (d) 1 (e) 6 (f) 5
PROBLEM
7-3
C16H13ClN2O
PROBLEM
7-4
(a) 3,4,4-Trimethyl-1-pentene (b) 3-Methyl-3-hexene (c) 4,7-Dimethyl-2,5-octadiene
(d) 6-Ethyl-7-methyl-4-nonene
PROBLEM
7-5
(a) (b) (c)
1196 Answer Key
Access for free at openstax.org
(d)
PROBLEM
7-6
(a) 1,2-Dimethylcyclohexene (b) 4,4-Dimethylcycloheptene (c) 3-Isopropylcyclopentene
PROBLEM
7-7
(a) 2,5,5-Trimethylhex-2-ene (b) 2,3-Dimethylcyclohexa-1,3-diene
PROBLEM
7-8
PROBLEM
7-9
Compounds (c), (e), and (f) have cis–trans isomers.
PROBLEM
7-10
(a) cis-4,5-Dimethyl-2-hexene (b) trans-6-Methyl-3-heptene
PROBLEM
7-11
(a) −CH3 (b) −Cl (c) −CH CH2 (d) −OCH3 (e) −CH O (f) −CH O
PROBLEM
7-12
(a) −Cl, −OH, −CH3, −H (b) −CH2OH, −CH CH2, −CH2CH3, −CH3
(c) −CO2H, −CH2OH, −C N, −CH2NH2 (d) −CH2OCH3, −C N, −C CH, −CH2CH3
PROBLEM
7-13
(a) Z (b) E (c) Z (d) E
PROBLEM
7-14
PROBLEM
7-15
(a) 2-Methylpropene is more stable than 1-butene.
(b) trans-2-Hexene is more stable than cis-2-hexene.
(c) 1-Methylcyclohexene is more stable than 3-methylcyclohexene.
PROBLEM
7-16
(a) Chlorocyclohexane (b) 2-Bromo-2-methylpentane (c) 4-Methyl-2-pentanol
(d) 1-Bromo-1-methylcyclohexane
PROBLEM
7-17
(a) Cyclopentene (b) 1-Ethylcyclohexene or ethylidenecyclohexane (c) 3-Hexene
(d) Vinylcyclohexane (cyclohexylethylene)
PROBLEM
7-18
(a) (b)
PROBLEM
7-19
In the conformation shown, only the methyl- group C−H that is parallel to the carbocation p orbital
can show hyperconjugation.
PROBLEM
7-20
The second step is exergonic; the transition state resembles the carbocation.
PROBLEM
7-21
Chapter 8
PROBLEM
8-1
2-Methyl-2-butene and 2-methyl-1-butene
PROBLEM Five
Answer Key 1197
	Answer Key
	Chapter 5
	Chapter 6
	Chapter 7
	Chapter 8

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