Chegg Solutions for Microelectronic Circuits (Adel S Sedra, Kenneth C Smith) (Z-Library)_parte_078

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Step of 5 8.046P Calculate the value of the voltage Substitute 0.526 V for and V for =5-0.526 =4.474 V Therefore, the value of the voltage is, 4.474 Step of 5 Calculate the value of the voltage Substitute 0.6 V for and 0.526 V for =1.126 V Therefore, the value of the voltage IS 1.126 V Step of 5 The drain currents of the transistors and will be equal for the linear region of the characteristics in Figure 8.16(b) from the text book. That is, Substitute and The values and are equal. Hence, Substitute 200 for 65 for 0.6 V for and 1.126 V for for 20 V for and 10 V for (1) Let and and Substitute 4.474 V V for Therefore, the value of the voltage for = 4.474 V is 0.878 V Step of 5 Recall equation (1). Let and Substitute Substitute Solve for the value of we get = V. =0.95 V and = V Chose the value of to be =0.95 V so that Hence, the value of is 0.95 V Step of 5 Calculate the value of the voltage Substitute 0.95 V for and 0.6 V for = =0.35 V Therefore, the value of the voltage is 0.35 V Therefore, the linear region at the output extends in the range > VI occurs for the input range 0.878 V V