Chegg Solutions for Microelectronic Circuits (Adel S Sedra, Kenneth C Smith) (Z-Library)_parte_1364

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Step 12.005E (a) For class AB circuit, Increase the linearity of the class AB output stage, the quiescent current is increased. The quiescent power dissipation The total power dissipation two transistors the quiescent power dissipation Step 2 of 9 (b) The current increased =0 At =0 the currents conducted by transistors $ and =10 mA The output resistance 25 10+10 25 20 =1.25 Ω The voltage 100 =0.988 voltage gain =0 0.988 Step 3 of 9 Determine the load =10 V 10 100 =0.1A Use quadratic =0 this quadratic equation obtain the current Determine 0.101 Step The output resistance 0.025 0.101 The voltage 100 =0.998 Thus voltage gain Step The percentage change voltage 1-0.988 %Change 100 =1.2% the percentage voltage gain for output voltage change from to Step example 11.3 the quiescent current mA voltage At =0 the currents conducted by transistors and The output 25 2+2 25 The voltage gain is 100 100+6.25 =0.941 the 10 100 =0.1A Use quadratic =0 Solve this equation obtain the current 0.1 A Step 8 of 9 The output voltage 0.025 = =0.25 Ω The voltage 100 100+0.25 =0.998 The percentage change the voltage 100 =0.06 =6% Thus the percentage for output voltage change from to 6% Step (c) power dissipation in two transistors Thus transistors