1 (116)

Prévia do material em texto

119 24.11 CA = ? = 0,6041 Let US start by evaluating CA&CB, CB, = and then the rate PAin = 101325 3500 = 28.95 CBin = 300 CAin = m3/s Since CB we have an excess of B we can take CB constant = 300 Now to the rate of rx MH = 1.4x10 2.05 0.25/120 E' 5 we have = 300(3500) = 11.36 E = 2.05 101325 so 3500 3500 + 0.025(2.05) PA = = 1.457x10 PA = 1.4764 0+ 68292 + 337 pure CO2 at atm, 195% of the resistance and rA"" = const From Eq 15 XA because = constant dXA XA = 0 XA = Vr FAO = 0.6041 1.05 (1.48) = 85% = CAO = = 1,05