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292 Chapter 14 Chemical Kinetics 14.111 Using the energy diagram shown and using Hess's law, we can see that the activation energy for the decomposition is equal to the acti- vation energy for the formation reaction plus the heat of formation of 2 moles of HI, or formation = decomposition + formation decomposition So formation = 185 kJ + 2 = 174kJ. activation activation E energy energy Check: Because the reaction is endothermic, we expect the activation energy in the reverse direction to be less than that in the forward direction. I₂ (2 mol)(-5.65 kJ/Mol) 2 HI Reaction progress Note: Energy axis is not to scale. Challenge Problems 14.113 (a) Because the rate-determining step involves the collision of two molecules, the expected reaction order would be second-order. (b) The proposed mechanism is + CH3NC* + CH3NC (fast) CH₃CN (slow) CH₃NC CH₃CN So the sum matches the overall reaction. is the activated molecule. Because the second step is the rate-determining step, Rate = k₃ [CH₃NC*] Because is an intermediate, its concentration cannot appear in the rate law. Using the fast equilibrium in the first step, we see that = or [CH₃NC*] = Substitut- ing this into the first rate expression, we get Rate = which simplifies to Rate = k[CH₃NC]. This matches the experimental observation of first order, and the mechanism is valid. 14.115 Rate = and Rate = d[A] , so d[A] = Moving the A terms to the left and the t and constants to the right, we have d[A] = kdt. Integrating, we get [A] [A]₀ d[A] [A] = 0 kdt. When we evaluate this integral, = kt = kt + A or [A], 1 = kt + 1 which is the desired integrated rate law. 14.117 For this mechanism, the overall reaction is the sum of the steps in the mechanism: CICO(g) + + CO(g) + + No overall reaction is given. Because the third step is the rate-determining step, Rate = k₅[ Because CICO is an intermediate, its concentration cannot appear in the rate law. Using the fast equilibrium in the second step, we see that = or [CICO] = k₃ k₄ Substituting this expression into the first rate Copyright © 2017 Pearson Education, Inc.

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