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Solutions for Conjugated Systems, Orbital Symmetry, and Ultraviolet Spectroscopy 27 continued H H O HH2C H2C H O HH H2C C H O HH C H H O HH2C (e) most significant contributor— negative charge on more electronegative atom H2C C C H H OCH3 C OCH3 C H H H2C H2C C C H H OCH3 (h) Most significant contributor—all atoms have full octets. (g) CH O CH2 O HC CH2 O CH2 O CH2 (f) OO O O H CO O Most significant contributor—all atoms have full octets. A λmax = 232 nm Solved Problem 3 λmax = 232 nm compare with dienes: A = ε c l ε = c l l = 1 cm A = 0.74 convert mass to moles: 0.0010 g x 1 mole 255 g = 3.9 x 10−6 moles c = 3.9 x 10−6 moles 100 mL 1000 mL 1 L = 3.9 x 10−5 Mx ε = 0.74 ( 3.9 x 10−5 ) ( 1 ) ≈ 28 (a) 19,000 (b) This large value of ε could only come from a conjugated system, eliminating the first structure. The absorption maximum at 235 nm is most likely a diene rather than a triene. The most reasonable structure is: Table 2 350