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1) NaNH₂ c) CH₃-C=C-H 2) PhCH₂Br 10.24 Br⁻ S + a) SPh b) c) CH₃CH₂CH₂CH₂SCH₃ d) S 10.25 CH₃ CH₃ OH a) OCH₃ b) OH c) OH 10.26 a)CH₃CH₂CH=CH₂ b) c) + d) major minor 10.27 a) This is not a good way to prepare the desired alkene because the alkene shown would be a minor product according to Zaitsev's rule. b) This is a good method to prepare the desired alkene. The alkene shown would be the only significant product because it is conjugated. 10.28 The top reaction is better because 3-bromopentane is symmetrical and will produce only the desired alkene. The bottom reaction would produce 1-pentene also. 154