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Step of 6 8.018P Refer to Figure 8.12(a) from the text book. Calculate the value of the output current Substitute 4 for and 200 for = 800 Therefore, the value of the output current is 800 Step of 6 Calculate the value of the output resistance Substitute 20 V/µm for for and 800 for 20 20 k 800 L = 20 L = 20 L 0.8 µm Therefore, the value of the length L is 0.8 : Step of 6 Consider the expression for the input resistance. 1 Substitute 500 Ω for 500 1 500 mS Therefore, the value of the transconductance is 2 mS Step of 6 Consider the expression for transconductance 8ml in terms of the over drive voltage and the bias current. Substitute 100 for and 2 mA for 2 m 400 0.2 V Therefore, the value of the over drive voltage is Step of 6 Consider the expression for the transconductance Substitute 0.2 V for 2 mA for 0.8 µm for 4 and 400 for = = 20 µm Therefore, the value of the width is 20 µm Step of 6 Calculate the value of the current gain = Substitute 20 µm for 4 for and 4 for = 4 80 µm Therefore, the value of the width is 80