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Step of 7 6.041P Consider the equation. = 100 Substitute =0 in the above equation to find the intercept of the straight line characteristics on the ic axis. 100 = 10 for = 0.65 V the intercept is 0.65 = 0.2 mA The slope of the curve = 0.65 V is Slope = ic = 0.2 mA 100 Slope 0.002 mA/V Step of 7 For = 0.70 V the intercept is ic 10⁻¹⁵ 0.70 = 1.45 mA The slope of the curve = 0.70 V is Slope = ic 1.45 mA = 100 Slope 0.0145 mA/V Step 3 of 7 For 0.72 V the intercept is ic 0.72 3.22 mA The slope of the curve = 0.72 V is Slope = ic 3.22 mA = 100 Slope 0.0322 mA/V Step of 7 For V the intercept is 0.73 ic 4.80 mA The slope of the curve =0.73 V is Slope = ic 4.8 mA = 100 Slope 0.048 mA/V Step of 7 For =0.74 V V the intercept is 0.74 ic 10⁻¹⁵ = 7.16 mA The slope of the curve = 0.74 V is Slope 7.16 mA = 100 Slope 0.0716 mA/V Step of 7 Tabulate the values as shown in Table 1 0.65 0.70 0.72 0.73 0.74 intercept (mA) 0.20 1.46 3.21 4.80 7.16 Slope (mA/V) 0.002 0.0146 0.0321 0.048 0.0716 Table Step of 7 The plot of ic versus is shown in Figure 1. 0.74 V 7 6 0.73 V 5 4 =0.72 V 3 2 0.70 V 1 0.65 V 5 10 15 Figure 1