trabalho de funções

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X
	F(X)=Y
	
C.A=2 C.L=5
Raiz = 2x+5=0
2x= -5
X= -5/2
X= -2,5
	 -2
	2. (-2) +5=1
	
	-1
	2. (-1) +5=3
	
	0
	2.0+5=5
	
	1
	2.1+5=7
	
	2
	2.2+5=9
	
	3
	2.3+5=11
	
B)Y= -3x+6
	X
	F(X)=Y
	
C.A= -3 C.L=6
Raíz -3x+6=0
X= -6/-3
X=2
	-2
	-3.(-2)+6=12
	
	-1
	-3.(-1)+6=9
	
	0
	-3.0+6=6
	
	1
	-3.1+6=3
	
	2
	-3.2+6=0
	
	3
	-3.3+6=-3
	
C)Y= 4x-8
	X
	F(X)=Y
	
C.A= 4 C.L= -8
Raíz 4x-8=0
X=8/4
X=2
	-1
	4.(-1)-8=-12
	
	0
	4.0-8=-8
	
	1
	4.1-8=-4
	
	2
	4.2-8=0
	
	3
	4.3-8=4
	
D)Y=-5x-10
	X
	F(X)=Y
	
C.A= -5 C.L= -10
Raíz -5x-10=0
X=10/-5
X= -2
	-2
	-5.(-2)-10=0
	
	-1
	-5.(-1)-10=-5
	
	0
	-5.0-10=-10
	
	2
	-5.2-10=0
	
	3
	-5.3-10=0
	
E)Y=x-7
	X
	F(X)=Y
	
C.A=1 C.L= -7
Raíz x-7=0
X=7
	-2
	-2-7=-9
	
	-1
	-1-7=-8
	
	0
	0-7=-7
	
	1
	1-7=-6
	
	2
	2-7=-5
	
	3
	3-7=-4
	
F)Y=7x
	X
	F(X)=Y
	
C.A=7 C.L=0
Raíz 7x=0
X=0
	-2
	7.(-2)=-14
	
	-1
	7.(-1)=-7
	
	0
	7.0=0
	
	1
	7.1=7
	
	2
	7.2=14
	
	3
	7.3=21
	
G)Y= -2x
	X
	F(X)=Y
	
C.A=-2 C.L=0
Raíz -2x=0
X=0
	-2
	-2.(-2)=4
	
	-1
	-2.(-1)=2
	
	0
	-2.0=0
	
	1
	-2.1=-2
	
	2
	-2.2=-4
	
	3
	-2.3=-6
	
H)Y= 2 I)Y= -3/2
C.A = 0 C.L = 2 C.A = 0 C.L = -3/2
Raíz = Raíz = 
Função do 2° grau
Calcule as raízes,e as coordenadas dos vértice V(Xv,Yv) e faça um esboço do gráfico.
Y=-2x-3
Y=+2x-1
Y=-2x+4
A) Y=-2x-3 
X1= =3 X2= = -1 
Vértice: V(1,-4)
Xv= =1 Yv= = -4
	X
	F(X)=Y
	-1
	-1²-2.(-1)-3= 0
	0
	0²-2.0-3= -3
	1
	1²-2.1-3=-4
	2
	2²-2.2-3= -3
	3
	3²-2.3-3= 0
B) Y=+2x-1
X1= =1 X2= =1
Vértice: V(1,0)
Xv= =1 Yv= = 0
	X
	F(X)=Y
	-1
	1²+2.(-1)-1= -2
	0
	0²+2.0-1= -1
	1
	1²+2.1-1= 2
	2
	2²+2.2-1= 7
	3
	3²+2.3-1=14
C) Y=-2x+4
= X
<0 
Vértice: V(1,3)
Xv= =1 Yv= = 3
	X
	F(X)=Y
	-1
	-1²-2.(-1)+4= 7
	0
	0²-2.0+4=4
	1
	1²-2.1+4=3
	2
	2²-2.2+4=4
	3
	3²-2.3+4=7