<div id="pf1" class="pf w0 h0" data-page-no="1"><div class="pc pc1 w0 h0"><img class="bi x0 y0 w1 h1" alt="" src="https://files.passeidireto.com/868a3c38-c1d0-44ad-8f6b-33462bb64b2f/bg1.png"><div class="t m0 x1 h2 y1 ff1 fs0 fc0 sc0 ls0 ws0"> </div><div class="t m0 x2 h2 y2 ff1 fs0 fc0 sc0 ls0 ws0">1 </div><div class="c x1 y3 w2 h3"><div class="t m0 x0 h2 y4 ff1 fs0 fc0 sc0 ls0 ws0"> </div></div><div class="t m0 x1 h4 y5 ff2 fs1 fc1 sc0 ls0 ws0">Vibrações Mecânicas \u2013 <span class="_0 blank"> </span>Resumo </div><div class="t m0 x1 h4 y6 ff2 fs1 fc1 sc0 ls0 ws0"> </div><div class="t m0 x1 h5 y7 ff3 fs2 fc0 sc0 ls0 ws0">ISOLAMENTO DE VIBRAÇÕES \u2013 </div><div class="t m0 x1 h5 y8 ff3 fs2 fc0 sc0 ls0 ws0">ISOLAMENTO PASSIVO<span class="fs3 fc2"> </span></div><div class="t m0 x1 h6 y9 ff3 fs3 fc1 sc0 ls0 ws0"> Introdução: </div><div class="t m0 x1 h7 ya ff2 fs4 fc0 sc0 ls0 ws0">Na aula <span class="_1 blank"></span>anterior vimos <span class="_1 blank"></span>o isolamento <span class="_1 blank"></span>ativo que <span class="_1 blank"></span>visa reduzir <span class="_1 blank"></span>a transmissão a <span class="_1 blank"></span>base ou <span class="_1 blank"></span>solo </div><div class="t m0 x1 h7 yb ff2 fs4 fc0 sc0 ls0 ws0">de forças de excitação geradas pelas máquinas. </div><div class="t m0 x1 h7 yc ff2 fs4 fc0 sc0 ls0 ws0">Existem situações <span class="_0 blank"> </span>que não <span class="_0 blank"> </span>é possível <span class="_0 blank"> </span>alterar os <span class="_0 blank"> </span>parâmetros <span class="_0 blank"> </span>dos sistemas e <span class="_0 blank"> </span>os <span class="_0 blank"> </span>níveis de </div><div class="t m0 x1 h7 yd ff2 fs4 fc0 sc0 ls0 ws0">transmissão de vibrações podem ser signi<span class="_1 blank"></span>ficativos. </div><div class="t m0 x1 h7 ye ff2 fs4 fc0 sc0 ls0 ws0">Nesse <span class="_2 blank"> </span>caso, <span class="_2 blank"> </span>temos <span class="_2 blank"> </span>de usar <span class="_2 blank"> </span>um <span class="_2 blank"> </span>elemento <span class="_2 blank"> </span>externo, <span class="_2 blank"> </span>ou <span class="_2 blank"> </span>seja, caímos <span class="_2 blank"> </span>no <span class="_2 blank"> </span>isolamento </div><div class="t m0 x1 h7 yf ff2 fs4 fc0 sc0 ls0 ws0">passivo. </div><div class="t m0 x1 h7 y10 ff2 fs4 fc0 sc0 ls0 ws0">Um <span class="_3 blank"> </span>exemplo, <span class="_3 blank"> </span>são <span class="_3 blank"> </span>os <span class="_3 blank"> </span>laboratórios <span class="_3 blank"> </span>de <span class="_3 blank"> </span>metrologia <span class="_3 blank"> </span>que <span class="_3 blank"> </span>devem <span class="_3 blank"> </span>ter <span class="_3 blank"> </span>piso <span class="_3 blank"> </span>distinto <span class="_3 blank"> </span>e <span class="_3 blank"> </span>isolado </div><div class="t m0 x1 h7 y11 ff2 fs4 fc0 sc0 ls0 ws0">do <span class="_0 blank"> </span>demais <span class="_3 blank"> </span>pisos <span class="_0 blank"> </span>dos <span class="_3 blank"> </span>edifícios, <span class="_0 blank"> </span>para <span class="_3 blank"> </span>não <span class="_0 blank"> </span>ter <span class="_3 blank"> </span>a <span class="_0 blank"> </span>qualidade <span class="_0 blank"> </span>de <span class="_3 blank"> </span>medição <span class="_0 blank"> </span>das <span class="_3 blank"> </span>peças <span class="_0 blank"> </span>a <span class="_3 blank"> </span>serem </div><div class="t m0 x1 h7 y12 ff2 fs4 fc0 sc0 ls0 ws0">medidas prejudicadas. Ou seja, isolar a excitação da base para a máquina. </div><div class="t m0 x1 h6 y13 ff3 fs3 fc1 sc0 ls0 ws0">Isolamento Passivo </div><div class="t m0 x1 h7 y14 ff2 fs4 fc0 sc0 ls0 ws0">Como comentamos também <span class="_1 blank"></span>na aula ant<span class="_1 blank"></span>erior, o isolamento <span class="_1 blank"></span>passivo é feito <span class="_1 blank"></span>por meio de </div><div class="t m0 x1 h7 y15 ff2 fs4 fc0 sc0 ls0 ws0">um <span class="_1 blank"></span>element<span class="_1 blank"></span>o <span class="_1 blank"></span>resiliente <span class="_4 blank"></span>externo. <span class="_4 blank"></span>Sendo <span class="_1 blank"></span>os <span class="_4 blank"></span>mais comuns,<span class="_1 blank"></span> <span class="_4 blank"></span>o<span class="_0 blank"> </span> <span class="_4 blank"></span>sem am<span class="_1 blank"></span>ortecimento <span class="_4 blank"></span>(a), <span class="_1 blank"></span>com </div><div class="t m0 x1 h7 y16 ff2 fs4 fc0 sc0 ls0 ws0">amortecimento (b) e o suporte pneumático de borracha (d). Como ilustrado na figura. </div><div class="t m0 x3 h7 y17 ff2 fs4 fc0 sc0 ls0 ws0"> </div><div class="t m0 x4 h8 y18 ff2 fs5 fc0 sc0 ls0 ws0">Figura 1: Tipos de Isoladore<span class="_1 blank"></span>s de vibrações (Fonte: <span class="_1 blank"></span>Livro Singiresu RAO) </div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div> <div id="pf2" class="pf w0 h0" data-page-no="2"><div class="pc pc2 w0 h0"><img class="bi x0 y0 w1 h1" alt="" src="https://files.passeidireto.com/868a3c38-c1d0-44ad-8f6b-33462bb64b2f/bg2.png"><div class="t m0 x1 h2 y1 ff1 fs0 fc0 sc0 ls0 ws0"> </div><div class="t m0 x2 h2 y2 ff1 fs0 fc0 sc0 ls0 ws0">2 </div><div class="c x1 y3 w2 h3"><div class="t m0 x0 h2 y4 ff1 fs0 fc0 sc0 ls0 ws0"> </div></div><div class="t m0 x1 h7 y19 ff2 fs4 fc0 sc0 ls0 ws0">A figura a seguir mostra o sistema com isolamento passivo. </div><div class="t m0 x5 h7 y1a ff2 fs4 fc0 sc0 ls0 ws0">Onde: </div><div class="t m0 x6 h9 y1b ff4 fs4 fc0 sc0 ls0 ws0">\u2022 <span class="_5 blank"> </span><span class="ff2">x(t) <span class="ff5 ls1">\uf0e0</span> vibração da base para a máquina; </span></div><div class="t m0 x6 h9 y1c ff4 fs4 fc0 sc0 ls0 ws0">\u2022 <span class="_5 blank"> </span><span class="ff2">y(t) <span class="ff5 ls1">\uf0e0</span> vibração da base; </span></div><div class="t m0 x6 h9 y1d ff4 fs4 fc0 sc0 ls0 ws0">\u2022 <span class="_5 blank"> </span><span class="ff2">z(t) <span class="ff5 ls1">\uf0e0</span> vibração relativa; </span></div><div class="t m0 x1 h7 y1e ff2 fs4 fc0 sc0 ls0 ws0"> </div><div class="t m0 x1 h7 y1f ff2 fs4 fc0 sc0 ls0 ws0">A Amplitude das Forças nas molas e amortecedores em regime permanent<span class="_1 blank"></span>e, são: </div><div class="t m0 x7 ha y20 ff2 fs4 fc0 sc0 ls0 ws0">Mola: <span class="ff6">\ue728</span></div><div class="t m0 x8 hb y21 ff6 fs6 fc0 sc0 ls0 ws1">\uebe0\uebe2\uebdf\uebd4 <span class="fs4 ws2 v1">=<span class="_6 blank"> </span>\ue747 .<span class="_7 blank"> </span>\ue756<span class="fs7 fc3 ls2 ws0"> </span>=<span class="_6 blank"> </span>\ue747 <span class="ws3 v2">(</span><span class="ws4">\ue754<span class="_6 blank"> </span>\u2212 \ue755<span class="ls3 v2">)</span><span class="fs7 fc3 ls4 ws0"> </span><span class="ws0">=<span class="_6 blank"> </span>\ue747\ue754 \u2212 \ue747\ue755<span class="_0 blank"></span><span class="ff2"> </span></span></span></span></div><div class="t m0 x9 ha y22 ff2 fs4 fc0 sc0 ls0 ws0">Amortecedor: <span class="ff6">\ue728</span></div><div class="t m0 xa hb y23 ff6 fs6 fc0 sc0 ls0 ws5">\uebd4\uebe0 <span class="fs4 ws6 v1">=<span class="_6 blank"> </span>\ue73f .<span class="_7 blank"> </span>\ue756<span class="_1 blank"></span>\u0307<span class="_7 blank"> </span><span class="fs7 fc3 ls4 ws0"> </span><span class="ws7">=<span class="_6 blank"> </span>\ue73f <span class="ws3 v2">(</span><span class="ws8">\ue754<span class="_4 blank"></span>\u0307<span class="_8 blank"> </span>\u2212<span class="_2 blank"> </span>\ue755<span class="_9 blank"></span>\u0307 <span class="ws3 v2">)</span><span class="ff2 ls5 ws0"> </span><span class="ws7">=<span class="_6 blank"> </span>\ue73f \ue754<span class="_9 blank"></span>\u0307<span class="_a blank"> </span>\u2212<span class="_2 blank"> </span>\ue73f \ue755<span class="_9 blank"></span>\u0307<span class="_b blank"> </span><span class="ff2 ws0"> </span></span></span></span></span></div><div class="t m0 x1 h7 y24 ff2 fs4 fc0 sc0 ls0 ws0">Onde: </div><div class="t m0 xb h9 y25 ff7 fs4 fc0 sc0 ls0 ws9">\uf0b7<span class="ff4 ls6 ws0"> <span class="ff2 ls0">F <span class="ff5 ls1">\uf0e0</span> A força na mola ou amortecedor, no SI é dada em N (Newtons); </span></span></div><div class="t m0 xb h9 y26 ff7 fs4 fc0 sc0 ls0 ws9">\uf0b7<span class="ff4 ls6 ws0"> <span class="ff2 ls0">k <span class="_2 blank"> </span><span class="ff5 ls1">\uf0e0</span> <span class="_6 blank"> </span>A <span class="_2 blank"> </span>rigidez, <span class="_c blank"> </span>constante <span class="_2 blank"> </span>de <span class="_c blank"> </span>mola <span class="_c blank"> </span>ou <span class="_c blank"> </span>elasticidade, <span class="_2 blank"> </span>no <span class="_c blank"> </span>SI <span class="_c blank"> </span>é <span class="_c blank"> </span>dada <span class="_2 blank"> </span>em <span class="_c blank"> </span>N/m </span></span></div><div class="t m0 xc h7 y27 ff2 fs4 fc0 sc0 ls0 ws0">(Newtons por metro); </div><div class="t m0 xb h9 y28 ff7 fs4 fc0 sc0 ls0 ws9">\uf0b7<span class="ff4 ls6 ws0"> <span class="ff2 ls0">x <span class="ff5 ls1">\uf0e0</span> O deslocamento, no SI é dado em m (metros); </span></span></div><div class="t m0 xb h9 y29 ff7 fs4 fc0 sc0 ls0 ws9">\uf0b7<span class="ff4 ls6 ws0"> <span class="ff2 ls1">X<span class="fs8 ls7 v3">p</span><span class="ff5">\uf0e0</span><span class="ls0"> A amplitude máxima de deslocamento, no SI é dada em m (metros); </span></span></span></div><div class="t m0 xb h9 y2a ff7 fs4 fc0 sc0 ls0 ws9">\uf0b7<span class="ff4 ls6 ws0"> </span>\uf077<span class="ff2 ls8 ws0"> <span class="ff5 ls1">\uf0e0</span><span class="ls0"> <span class="_b blank"> </span>A <span class="_b blank"> </span>frequência <span class="_b blank"> </span>angular <span class="_b blank"> </span>de <span class="_d blank"> </span>excitação, <span class="_b blank"> </span>no <span class="_b blank"> </span>SI <span class="_b blank"> </span>é <span class="_d blank"> </span>dada <span class="_d blank"> </span>em <span class="_b blank"> </span>rad/s <span class="_b blank"> </span>(radianos <span class="_d blank"> </span>por </span></span></div><div class="t m0 xc h7 y2b ff2 fs4 fc0 sc0 ls0 ws0">segundo); </div><div class="t m0 xb h9 y2c ff7 fs4 fc0 sc0 ls0 ws9">\uf0b7<span class="ff4 ls6 ws0"> <span class="ff2 ls0">t <span class="ff5 ls1">\uf0e0</span> tempo, no SI é dado em s (segundos); </span></span></div><div class="t m0 xb h9 y2d ff7 fs4 fc0 sc0 ls0 ws9">\uf0b7<span class="ff4 ls6 ws0"> </span>\uf066<span class="ff2 ws0"> <span class="ff5 ls1">\uf0e0</span> O ângulo de fase, no SI é dado em rad (radianos); </span></div><div class="t m0 xb h9 y2e ff7 fs4 fc0 sc0 ls0 ws9">\uf0b7<span class="ff4 ls6 ws0"> <span class="ff2 ls0">c <span class="ff5 ls1">\uf0e0</span> <span class="_4 blank"></span>O coeficiente <span class="_4 blank"></span>de amortecimento <span class="_1 blank"></span>viscosos, <span class="_4 blank"></span>no SI <span class="_1 blank"></span>é <span class="_1 blank"></span>dado <span class="_1 blank"></span>em <span class="_1 blank"></span>N.s/m <span class="_1 blank"></span>(Newtons </span></span></div><div class="t m0 xc h7 y2f ff2 fs4 fc0 sc0 ls0 ws0">vezes segundos por metro); </div><div class="t m0 xb ha y30 ff7 fs4 fc0 sc0 ls0 ws9">\uf0b7<span class="ff4 ls6 ws0"> </span><span class="ff6 ws8">\ue754<span class="_4 blank"></span>\u0307 <span class="ff2 ws0"> <span class="ff5 ls1">\uf0e0</span> A velocidade, no SI é dada por m/s (metros por segund<span class="_1 blank"></span>o) </span></span></div><div class="t m0 xd h7 y31 ff2 fs4 fc0 sc0 ls0 ws0"> </div><div class="t m0 x1 h7 y32 ff2 fs4 fc0 sc0 ls0 ws0">A equação do movimento para o sistema máquinas-base é: </div><div class="t m0 xe ha y33 ff6 fs4 fc0 sc0 ls0 ws4">\ue749\ue754<span class="_4 blank"></span>\u0308<span class="_8 blank"> </span>+ \ue73f<span class="_3 blank"> </span>\ue754<span class="_9 blank"></span>\u0307<span class="_a blank"> </span>+ \ue747\ue754<span class="_8 blank"> </span>=<span class="_6 blank"> </span>\ue73f<span class="_0 blank"> </span>.<span class="_7 blank"> </span>\ue755<span class="_9 blank"></span>\u0307<span class="_a blank"> </span>+ \ue747<span class="_0 blank"> </span>.<span class="_7 blank"> </span>\ue755<span class="ff2 ws0"> </span></div><div class="t m0 x1 h7 y34 ff2 fs4 fc0 sc0 ls0 ws0">Tendo <span class="_c blank"> </span>em <span class="_6 blank"> </span>vista, <span class="_c blank"> </span>que <span class="_6 blank"> </span>para <span class="_c blank"> </span>equipamentos <span class="_6 blank"> </span>rotativos, <span class="_c blank"> </span>sujeitos <span class="_c blank"> </span>a <span class="_6 blank"> </span>desbalance<span class="_0 blank"> </span>amento, </div><div class="t m0 x1 hc y35 ff2 fs4 fc0 sc0 ls0 ws0">podemos <span class="_b blank"> </span>assumir <span class="_b blank"> </span>que <span class="_b blank"> </span>a <span class="_b blank"> </span>base <span class="_b blank"> </span>tem <span class="_b blank"> </span>mo<span class="_0 blank"> </span>vimento <span class="_b blank"> </span>harmônico <span class="_d blank"> </span><span class="ff6 ls9">\ue755<span class="ls0 ws3 v2">(</span><span class="lsa">\ue750<span class="lsb v2">)</span><span class="ls0">=<span class="_6 blank"> </span>\ue73b \ue74f\ue741\ue74a (\ue7f1.<span class="_7 blank"> </span>\ue750<span class="_0 blank"> </span>)</span></span></span>, <span class="_b blank"> </span>assim </div><div class="t m0 x1 h7 y36 ff2 fs4 fc0 sc0 ls0 ws0">fica: </div><div class="t m0 x9 hc y37 ff6 fs4 fc0 sc0 ls0 wsa">\ue749\ue754<span class="_4 blank"></span>\u0308<span class="_8 blank"> </span>+<span class="_2 blank"> </span>\ue73f<span class="_3 blank"> </span>\ue754<span class="_4 blank"></span>\u0307<span class="_8 blank"> </span>+<span class="_2 blank"> </span>\ue747\ue754<span class="_8 blank"> </span>=<span class="_6 blank"> </span>\ue73f<span class="_0 blank"> </span>. \ue7f1<span class="_0 blank"> </span>. \ue73b<span class="_0 blank"> </span>. \ue73f\ue74b\ue74f<span class="_0 blank"> </span><span class="ws3 v2">(</span><span class="wsb">\ue7f1\ue750 <span class="lsc v2">)</span>+<span class="_2 blank"> </span>\ue747 .<span class="_7 blank"> </span>\ue73b .<span class="_7 blank"> </span>\ue74f\ue741\ue74a(\ue7f1\ue750 )<span class="ff2 ws0"> </span></span></div><div class="t m0 x1 h7 y38 ff2 fs4 fc0 sc0 ls0 ws0">Já a Transmissibilidade, T<span class="fs8 lsd v3">R</span>, não muda e fica: </div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div> <div id="pf3" class="pf w0 h0" data-page-no="3"><div class="pc pc3 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x0 y0 w1 h1" alt="" src="https://files.passeidireto.com/868a3c38-c1d0-44ad-8f6b-33462bb64b2f/bg3.png"><div class="t m0 x1 h2 y1 ff1 fs0 fc0 sc0 ls0 ws0"> </div><div class="t m0 x2 h2 y2 ff1 fs0 fc0 sc0 ls0 ws0">3 </div><div class="c x1 y3 w2 h3"><div class="t m0 x0 h2 y4 ff1 fs0 fc0 sc0 ls0 ws0"> </div></div><div class="t m0 xf ha y39 ff6 fs4 fc0 sc0 ls0">\ue736</div><div class="t m0 x10 hd y3a ff6 fs6 fc0 sc0 lse">\uebcb<span class="fs4 lsf v1">=<span class="ls10 v4">\ueda5<span class="ls0 wsc v0">1 + <span class="ws3 v2">(</span><span class="wsa">2. \ue7e6<span class="_3 blank"> </span>. \ue74e<span class="_0 blank"></span><span class="ws3 v2">)</span><span class="fs6 v5">\ueb36</span></span></span></span></span></div><div class="t m0 x11 he y3b ff6 fs4 fc0 sc0 ls10">\ueda5<span class="ls0 ws3 v2">(</span><span class="ls0 wsd v0">1<span class="_2 blank"> </span>\u2212<span class="_2 blank"> </span>\ue74e <span class="fs6 ls11 v5">\ueb36</span><span class="ws3 v2">)</span><span class="fs6 ls12 v5">\ueb36</span><span class="ls13">+</span><span class="ws3 v2">(</span><span class="wse">2.<span class="_7 blank"> </span>\ue7e6 .<span class="_7 blank"> </span>\ue74e<span class="ws3 v2">)</span><span class="fs6 ls14 v5">\ueb36</span><span class="ff2 ws0"> <span class="v6"> </span></span></span></span></div><div class="t m0 x1 ha y3c ff2 fs4 fc0 sc0 ls0 ws0">Lembrando que r é a razão de frequências e <span class="ff6 ls15">\ue7e6</span> o fator de amortecimento. </div><div class="t m0 x1 hf y3d ff2 fs9 fc0 sc0 ls0 ws0">Para ilustrar, vamos a um exercíci<span class="_1 blank"></span>o:<span class="ff3"> </span></div><div class="t m0 x1 h6 y3e ff3 fs3 fc1 sc0 ls0 ws0">Exercício Resolvido: Isolamento Passivo </div><div class="t m0 x1 h10 y3f ff2 fs4 fc0 sc0 ls0 ws0">Um moto-ventilador é mo<span class="_0 blank"> </span>ntado sobre duas <span class="_0 blank"> </span>vigas I de <span class="_0 blank"> </span>ação com E = <span class="_0 blank"> </span>210x10<span class="_0 blank"> </span><span class="fs8 ls16 v7">9</span> (N/m<span class="fs8 ls17 v7">2</span>), de </div><div class="t m0 x1 h10 y40 ff2 fs4 fc0 sc0 ls0 ws0">comprimento <span class="_e blank"> </span>2 <span class="_e blank"> </span>m, <span class="_e blank"> </span>cujo <span class="_e blank"> </span>momento <span class="_e blank"> </span>de <span class="_e blank"> </span>inércia <span class="_e blank"> </span>é <span class="_e blank"> </span>2700 <span class="_e blank"> </span>cm<span class="fs8 ls18 v7">4</span>. <span class="_e blank"> </span>O <span class="_e blank"> </span>equipamento <span class="_e blank"> </span>tem <span class="_e blank"> </span>massa </div><div class="t m0 x1 h7 y41 ff2 fs4 fc0 sc0 ls0 ws0">m=7300 <span class="_2 blank"> </span>kg <span class="_2 blank"> </span>e <span class="_2 blank"> </span>atua <span class="_2 blank"> </span>c<span class="_0 blank"> </span>om <span class="_2 blank"> </span>rotação <span class="_2 blank"> </span>de <span class="_2 blank"> </span>900 <span class="_2 blank"> </span>RPM. <span class="_c blank"> </span>Considerando <span class="_c blank"> </span>\u03be <span class="_2 blank"> </span>= <span class="_2 blank"> </span>0,05, <span class="_c blank"> </span>avalie <span class="_2 blank"> </span>se <span class="_2 blank"> </span>a </div><div class="t m0 x1 h7 y42 ff2 fs4 fc0 sc0 ls0 ws0">transmissibilidade absoluta está <span class="_7 blank"> </span>em um nível aceitável? Caso <span class="_7 blank"> </span>não, qual será % <span class="_7 blank"> </span>de </div><div class="t m0 x1 h7 y43 ff2 fs4 fc0 sc0 ls0 ws0">redução, interpondo <span class="_1 blank"></span>entre a <span class="_1 blank"></span>viga e <span class="_1 blank"></span>o grupo <span class="_1 blank"></span>em série, <span class="_1 blank"></span>isoladores de <span class="_1 blank"></span>molas heli<span class="_1 blank"></span>coida<span class="_0 blank"> </span>is de </div><div class="t m0 x1 h10 y44 ff2 fs4 fc0 sc0 ls0 ws0">rigidez total de 4x10<span class="fs8 v7">6 </span>(N/m)? </div><div class="t m0 x1 h10 y45 ff2 fs4 fc0 sc0 ls0 ws0">Lembrando que: 1 (cm<span class="fs8 ls18 v7">4</span>) = 1 (10<span class="fs8 wsf v7">-2</span><span class="ws10">m)<span class="fs8 wsf v7">4</span></span>= 10<span class="fs8 v7">-8 </span><span class="ws10">(m<span class="fs8 ls18 v7">4</span>)</span><span class="fs8 v7"> </span></div><div class="t m0 x1 h7 y46 ff2 fs4 fc0 sc0 ls0 ws0">Resolução: Esboços </div><div class="t m0 x1 h7 y47 ff2 fs4 fc0 sc0 ls0 ws0"> No <span class="_e blank"> </span>caso <span class="_e blank"> </span>01, <span class="_3 blank"> </span>temos <span class="_e blank"> </span>o <span class="_e blank"> </span>moto-ventilador <span class="_e blank"> </span>representado </div><div class="t m0 x1 h7 y48 ff2 fs4 fc0 sc0 ls0 ws0">pelo <span class="_f blank"> </span>retângulo <span class="_f blank"> </span>em <span class="_f blank"> </span>vermelho, <span class="_f blank"> </span>apoiado <span class="_a blank"> </span>nas <span class="_f blank"> </span>vigas </div><div class="t m0 x1 h7 y49 ff2 fs4 fc0 sc0 ls0 ws0">representadas <span class="_7 blank"> </span>pelos r<span class="_1 blank"></span>etângulos <span class="_7 blank"> </span>em v<span class="_1 blank"></span>erde, q<span class="_1 blank"></span>ue <span class="_7 blank"> </span>por </div><div class="t m0 x1 h7 y4a ff2 fs4 fc0 sc0 ls0 ws0">sua <span class="_10 blank"> </span>vez, <span class="_10 blank"> </span>estão <span class="_10 blank"> </span>sobre <span class="_10 blank"> </span>a <span class="_10 blank"> </span>base <span class="_10 blank"> </span>representada <span class="_f blank"> </span>pelo </div><div class="t m0 x1 h7 y4b ff2 fs4 fc0 sc0 ls0 ws0">retângulo em azul marinho. </div><div class="t m0 x1 h7 y4c ff2 fs4 fc0 sc0 ls0 ws0">No <span class="_3 blank"> </span>caso <span class="_0 blank"> </span>02, <span class="_3 blank"> </span>temos <span class="_3 blank"> </span>entre <span class="_3 blank"> </span>as <span class="_3 blank"> </span>vigas <span class="_0 blank"> </span>de <span class="_3 blank"> </span>suporte <span class="_3 blank"> </span>e <span class="_3 blank"> </span>a <span class="_3 blank"> </span>base, <span class="_0 blank"> </span>o <span class="_3 blank"> </span>isolador <span class="_3 blank"> </span>de <span class="_3 blank"> </span>vibração <span class="_3 blank"> </span>indicado </div><div class="t m0 x1 h7 y4d ff2 fs4 fc0 sc0 ls0 ws0">pelo retângulo em roxo. </div><div class="t m0 x1 h11 y4e ff2 fs4 fc1 sc0 ls0 ws10">Resolução<span class="ff3 ws0">: </span></div><div class="t m0 x1 h11 y4f ff2 fs4 fc0 sc0 ls0 ws0">Calculando a <span class="fc1">frequência de excitação, <span class="ff7 ws9">\uf077<span class="ff3 ls19">:</span></span></span> </div><div class="t m0 x12 h12 y50 ff6 fs4 fc0 sc0 ls0 wsa">\ue7f1<span class="_6 blank"> </span>=<span class="_6 blank"> </span>\ue734\ue74b\ue750\ue73dçã\ue74b<span class="_0 blank"> </span>. <span class="fs6 ws11 v8">\ueb36\uec17</span></div><div class="t m0 x13 h13 y51 ff6 fs6 fc0 sc0 ls0 ws12">\ueb3a\ueb34 <span class="ff2 fs4 ws0 v9"> <span class="ff6 wsa">=<span class="_6 blank"> </span>900. </span></span><span class="ws11 va">\ueb36\uec17</span></div><div class="t m0 xd h14 y51 ff6 fs6 fc0 sc0 ls0 ws13">\ueb3a\ueb34 <span class="fs4 ws0 v9">=<span class="_6 blank"> </span>\ueae2\ueadd,<span class="_7 blank"> </span>\ueadc <span class="ff3 ws14">(rad/s)<span class="ff2 ws0"> </span></span></span></div><div class="t m0 x1 h7 y52 ff2 fs4 fc0 sc0 ls0 ws0">Calculando a rigidez, K, das vigas em paralelo: </div><div class="t m0 x4 h12 y53 ff6 fs4 fc0 sc0 ls0 ws3">\ue747<span class="fs6 ws15 vb">\uebd8\uebe4 </span><span class="ws0">=<span class="_6 blank"> </span>2 .<span class="_7 blank"> </span> <span class="_7 blank"> </span><span class="fs6 v8">\ueb38\ueb3c \uebbe.\uebc2</span></span></div><div class="t m0 x14 h15 y54 ff6 fs6 fc0 sc0 ls1a">\uebc5<span class="fsa ls1b v1">\uec2f</span><span class="fs4 ls0 ws0 v9">=<span class="_6 blank"> </span>2 .<span class="_7 blank"> </span> <span class="_7 blank"> </span></span><span class="ls0 ws0 va">\ueb38\ueb3c .\ueb36\ueb35\ueb34.\ueb35\ueb34</span><span class="fsa ls1c vc">\uec35</span><span class="ls0 ws11 va">.\ueb36\ueb3b\ueb34\ueb34.\ueb35<span class="_1 blank"></span>\ueb34<span class="fsa ws16 vd">\uec37\uec34</span></span></div><div class="t m0 x15 h14 y54 ff6 fs6 fc0 sc0 ls0 ws11">\ueb36<span class="fsa ls1d v1">\uec2f</span><span class="fs4 ws0 v9">=<span class="_6 blank"> </span> <span class="ff3">6,8 x 10<span class="fs8 v7">7 </span><span class="ws14">(N/m)</span><span class="ff2"> </span></span></span></div><div class="t m0 x1 ha y55 ff2 fs4 fc0 sc0 ls0 ws0">Calculando a frequência angular natural, <span class="ff6">\ue7f1</span></div><div class="t m0 x16 h16 y56 ff6 fs6 fc0 sc0 ls1e">\uebe1<span class="ff2 fs4 ls0 ws0 v1">: </span></div><div class="t m0 x17 ha y57 ff6 fs4 fc0 sc0 ls0">\ue7f1</div><div class="t m0 x10 h17 y58 ff6 fs6 fc0 sc0 ls1f">\uebe1<span class="fs4 ls0 ws0 v1">=<span class="_6 blank"> </span> <span class="ws3 v2">\ueda7</span></span><span class="ls20 ve">\uebde</span><span class="fsa ls0 ws16 vf">\uecd0\uecdc</span></div><div class="t m0 x18 h18 y59 ff6 fs6 fc0 sc0 ls21">\uebe0<span class="fs4 ls22 v9">=<span class="ls0 ws3 v10">\ueda7</span></span><span class="ls0 ws11 va">\ueb3a,\ueb3c.\ueb35\ueb34<span class="fsa v1">\uec33</span></span></div><div class="t m0 x19 h14 y59 ff6 fs6 fc0 sc0 ls0 ws17">\ueb3b\ueb37\ueb34\ueb34 <span class="ff2 fs4 ws0 v9"> <span class="ff6">=<span class="_6 blank"> </span>\ueae2\ueadf,<span class="_7 blank"> </span>\ueade <span class="ff3">(rad/s) </span></span></span></div><div class="t m0 x1 h7 y5a ff2 fs4 fc0 sc0 ls0 ws0">Calculando a razão de frequência, r. </div><div class="t m0 x1a h12 y5b ff6 fs4 fc0 sc0 ls0 ws18">\ue74e =<span class="_11 blank"> </span><span class="fs6 v8">\uec20</span></div><div class="t m0 x1b h13 y5c ff6 fs6 fc0 sc0 ls0 ws11">\uec20<span class="fsa ls23 v11">\uecd9</span><span class="fs4 ls22 v9">=</span><span class="va">\ueb3d\ueb38,\ueb37</span></div><div class="t m0 x1c h14 y5c ff6 fs6 fc0 sc0 ls0 ws11">\ueb3d\ueb3a,\ueb39<span class="ff2 fs4 ws0 v9"> <span class="ff6 ws3">=</span> 0,98 <span class="ff5 ls1">\uf0e0</span> <span class="ff6 ls24">r<<span class="ls0 ws3 v12">\u221a</span><span class="ls25">2</span></span> <span class="ff5 ls1">\uf0e0</span> Faixa de Ampliação </span></div><div class="t m0 x1 ha y5d ff2 fs4 fc0 sc0 ls0 ws0">Calculando a transmissibilidade absoluta, <span class="ff6">\ue736</span></div><div class="t m0 x1d h16 y5e ff6 fs6 fc0 sc0 ls26">\uebcb<span class="ff2 fs4 ls0 ws0 v1">: </span></div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div> <div id="pf4" class="pf w0 h0" data-page-no="4"><div class="pc pc4 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x0 y0 w1 h1" alt="" src="https://files.passeidireto.com/868a3c38-c1d0-44ad-8f6b-33462bb64b2f/bg4.png"><div class="t m0 x1 h2 y1 ff1 fs0 fc0 sc0 ls0 ws0"> </div><div class="t m0 x2 h2 y2 ff1 fs0 fc0 sc0 ls0 ws0">4 </div><div class="c x1 y3 w2 h3"><div class="t m0 x0 h2 y4 ff1 fs0 fc0 sc0 ls0 ws0"> </div></div><div class="t m0 x1e ha y5f ff6 fs4 fc0 sc0 ls0">\ue736</div><div class="t m0 x1f h19 y60 ff6 fs6 fc0 sc0 lse">\uebcb<span class="fs4 ls27 v1">=</span><span class="ls0 ws11 v13">\ueda5<span class="v0">\ueb35\ueb3e<span class="ls28 v2">(</span><span class="ws19">\ueb36.\uec15 .\uebe5 <span class="ls28 v2">)</span><span class="fsa v1">\uec2e</span></span></span></span></div><div class="t m0 x9 h1a y61 ff6 fs6 fc0 sc0 ls0 ws11">\ueda5<span class="ls28 v0">(</span><span class="ws1a v0">\ueb35\ueb3f\uebe5 <span class="fsa ls1c v1">\uec2e</span></span><span class="v0">)<span class="fsa ls1c v1">\uec2e</span><span class="v12">\ueb3e</span><span class="ls28">(</span><span class="ws19 v12">\ueb36.\uec15.\uebe5 </span><span class="ls28">)<span class="fsa ls29 v1">\uec2e</span><span class="ff2 ls2a ws0 v12"> </span><span class="fs4 ls2b v9">=</span></span><span class="v14">\ueda5<span class="v0">\ueb35\ueb3e(\ueb36.\ueb34,\ueb34\ueb39.\ueb34,\ueb3d\ueb3c)<span class="fsa v1">\uec2e</span></span></span></span></div><div class="t m0 x20 h1b y61 ff6 fs6 fc0 sc0 ls0 ws11">\ueda5<span class="ls28 v2">(</span><span class="v0">\ueb35\ueb3f\ueb34,\ueb3d\ueb3c\ueb36<span class="ls28 v2">)</span><span class="ws0">\ueb36 \ueb3e(\ueb36.\ueb34,\ueb34\ueb39.\ueb34<span class="_1 blank"></span>,\ueb3d\ueb3c)<span class="fsa ls1c v1">\uec2e</span><span class="ff2"> <span class="fs4 v15"> <span class="ff6 ws3">=<span class="ff3 ws0"> 9,5</span></span> </span></span></span></span></div><div class="t m0 x1 h7 y62 ff2 fs4 fc0 sc0 ls0 ws0">No <span class="_4 blank"></span>caso <span class="_4 blank"></span>em <span class="_1 blank"></span>questão <span class="_4 blank"></span>a <span class="_4 blank"></span>transmissibilidade <span class="_4 blank"></span>absoluta <span class="_4 blank"></span>é <span class="_1 blank"></span>muito <span class="_4 blank"></span>alta <span class="_4 blank"></span>e <span class="_4 blank"></span>não <span class="_4 blank"></span>é <span class="_1 blank"></span>aceitável <span class="_4 blank"></span>e <span class="_4 blank"></span>temos </div><div class="t m0 x1 h7 y63 ff2 fs4 fc0 sc0 ls0 ws0">necessidade de usar um isolador de vibrações. </div><div class="t m0 x1 h7 y64 ff2 fs4 fc0 sc0 ls0 ws0">Calculando a nova rigidez equivalente: </div><div class="t m0 x1 h7 y65 ff2 fs4 fc0 sc0 ls0 ws0">Para molas em série, temos: </div><div class="t m0 x21 h16 y66 ff6 fs6 fc0 sc0 ls0">\ueb35</div><div class="t m0 xc h13 y67 ff6 fs6 fc0 sc0 ls20">\uebde<span class="fsa ls0 ws1b v11">\uecd0\uecdc </span><span class="fs4 ls2c v9">=</span><span class="ls0 va">\ueb35</span></div><div class="t m0 x22 h13 y67 ff2 fs6 fc0 sc0 ls0 ws0"> <span class="ff6 ls20">\uebde<span class="fsa ls0 ws1c v11">\uecde\uecd4\uecde\uecdf\uecd0\uecd8\ueccc </span><span class="fs4 ls2d v9">+</span><span class="ls0 va">\ueb35</span></span></div><div class="t m0 x23 h13 y67 ff2 fs6 fc0 sc0 ls0 ws0"> <span class="ff6 ls20">\uebde<span class="fsa ls0 ws1d v11">\uecd4\uecde\uecda\uecd7\ueccc\ueccf\uecda\uecdd</span></span><span class="fs4 v9"> <span class="ff6 ls2e">\u2192</span></span><span class="ff6 va">\ueb35</span></div><div class="t m0 x11 h13 y67 ff6 fs6 fc0 sc0 ls20">\uebde<span class="fsa ls0 ws1e v11">\uecd0\uecdc </span><span class="fs4 ls2f v9">=</span><span class="ls0 va">\ueb35</span></div><div class="t m0 x24 h13 y67 ff2 fs6 fc0 sc0 ls0 ws0"> <span class="ff6 ws11">\ueb3a,\ueb3c.\ueb35\ueb34<span class="fsa ls30 v1">\uec33</span><span class="fs4 ls31 v9">+</span><span class="va">\ueb35</span></span></div><div class="t m0 x25 h1c y67 ff2 fs6 fc0 sc0 ls0 ws0"> <span class="ff6 ws11">\ueb38,\ueb34.\ueb35\ueb34<span class="fsa ls29 v1">\uec32</span></span><span class="fs4 v9"> <span class="ff5 ls1">\uf0e0</span> <span class="ff3 ws14">k<span class="fs8 ws1f v3">eq</span><span class="ws0"> = 3,78.10<span class="fs8 v7">6 </span></span>(N/m)</span> </span></div><div class="t m0 x1 h1d y68 ff2 fs0 fc0 sc0 ls0 ws0"> </div><div class="t m0 x1 ha y69 ff2 fs4 fc0 sc0 ls0 ws0">Calculando a nova frequência angular natural, <span class="ff6">\ue7f1</span></div><div class="t m0 x26 h16 y6a ff6 fs6 fc0 sc0 ls1e">\uebe1<span class="ff2 fs4 ls0 ws0 v1">: </span></div><div class="t m0 x27 ha y6b ff6 fs4 fc0 sc0 ls0">\ue7f1</div><div class="t m0 x28 h17 y6c ff6 fs6 fc0 sc0 ls1f">\uebe1<span class="fs4 ls0 ws0 v1">=<span class="_6 blank"> </span> <span class="ws3 v2">\ueda7</span></span><span class="ls20 ve">\uebde</span><span class="fsa ls0 ws16 vf">\uecd0\uecdc</span></div><div class="t m0 x13 h18 y6d ff6 fs6 fc0 sc0 ls21">\uebe0<span class="fs4 ls22 v9">=<span class="ls0 ws3 v10">\ueda7</span></span><span class="ls0 ws11 va">\ueb37,\ueb3b\ueb3c.\ueb35\ueb34<span class="fsa v1">\uec32</span></span></div><div class="t m0 x19 h14 y6d ff6 fs6 fc0 sc0 ls0 ws20">\ueb3b\ueb37\ueb34\ueb34 <span class="ff2 fs4 ws0 v9"> <span class="ff6">=<span class="_6 blank"> </span>\ueadb\ueadb,<span class="_7 blank"> </span>\ueae0 <span class="ff3 ws14">(rad/s)</span></span> </span></div><div class="t m0 x1 h7 y6e ff2 fs4 fc0 sc0 ls0 ws0">Calculando a nova razão de frequência, r. </div><div class="t m0 x1a h12 y6f ff6 fs4 fc0 sc0 ls0 ws18">\ue74e =<span class="_11 blank"> </span><span class="fs6 v8">\uec20</span></div><div class="t m0 x1b h13 y70 ff6 fs6 fc0 sc0 ls0 ws11">\uec20<span class="fsa ls23 v11">\uecd9</span><span class="fs4 ls32 v9">=</span><span class="va">\ueb3d\ueb38,\ueb37</span></div><div class="t m0 x1c h14 y70 ff6 fs6 fc0 sc0 ls0 ws21">\ueb36\ueb36,\ueb3b <span class="fs4 ws0 v9">= <span class="ff2 ws10">4,15<span class="ff5 ls1">\uf0e0</span><span class="ws0"> <span class="ff6 ws22">r > <span class="ws3 v12">\u221a</span><span class="ls1">2</span></span> <span class="ff5 ls1">\uf0e0</span> Faixa de Isolamento </span></span></span></div><div class="t m0 x1 ha y71 ff2 fs4 fc0 sc0 ls0 ws0">Calculando a transmissibilidade absoluta, <span class="ff6">\ue736</span></div><div class="t m0 x1d h16 y72 ff6 fs6 fc0 sc0 ls26">\uebcb<span class="ff2 fs4 ls0 ws0 v1">: </span></div><div class="t m0 x29 ha y73 ff6 fs4 fc0 sc0 ls0">\ue736</div><div class="t m0 x2a h19 y74 ff6 fs6 fc0 sc0 lse">\uebcb<span class="fs4 ls27 v1">=</span><span class="ls0 ws11 v13">\ueda5<span class="v0">\ueb35\ueb3e<span class="ls28 v2">(</span><span class="ws19">\ueb36.\uec15 .\uebe5 <span class="ls28 v2">)</span><span class="fsa v1">\uec2e</span></span></span></span></div><div class="t m0 x2b h1a y75 ff6 fs6 fc0 sc0 ls0 ws11">\ueda5<span class="ls28 v0">(</span><span class="ws1a v0">\ueb35\ueb3f\uebe5 <span class="fsa ls1c v1">\uec2e</span></span><span class="v0">)<span class="fsa ls1c v1">\uec2e</span><span class="v12">\ueb3e</span><span class="ls28">(</span><span class="ws19 v12">\ueb36.\uec15.\uebe5 </span><span class="ls28">)<span class="fsa ls29 v1">\uec2e</span><span class="ff2 ls2a ws0 v12"> </span><span class="fs4 ls33 v9">=</span></span><span class="v14">\ueda5<span class="v0">\ueb35\ueb3e(\ueb36.\ueb34,\ueb34\ueb39.\ueb38,\ueb35\ueb39)<span class="fsa v1">\uec2e</span></span></span></span></div><div class="t m0 x2c h1e y75 ff6 fs6 fc0 sc0 ls0 ws11">\ueda5<span class="ls28 v2">(</span><span class="v0">\ueb35\ueb3f\ueb38,\ueb35\ueb39\ueb36<span class="ls28 v2">)</span><span class="ws0">\ueb36 \ueb3e(\ueb36.\ueb34,\ueb34\ueb39.\ueb38<span class="_1 blank"></span>,\ueb35\ueb39)<span class="fsa ls1c v1">\uec2e</span><span class="ff2"> </span></span></span></div><div class="t m0 x2d ha y73 ff2 fs4 fc0 sc0 ls0 ws0"> <span class="ff6 ws3">=</span><span class="ff3"> 0,0667</span> </div><div class="t m0 x1 h7 y76 ff2 fs4 fc0 sc0 ls0 ws0">Transmissibilidade absoluta em um índice aceitável<span class="_1 blank"></span>. </div><div class="t m0 x1 h7 y77 ff2 fs4 fc0 sc0 ls0 ws0">Calculando a (%) de redução: </div><div class="t m0 x1 h1f y78 ff2 fs4 fc0 sc0 ls0 ws0">Temos que <span class="ff6 fs6 ws11 v16">\uebe0.\uebd1</span></div><div class="t m0 x29 h20 y79 ff6 fsa fc0 sc0 ls0">\uecdb</div><div class="t m0 x2e h15 y7a ff6 fs6 fc0 sc0 ls34">\uebe0<span class="fsa ls35 v11">\uecda</span><span class="ls0 ws23">.\uebd7 <span class="fs4 ls36 v9">=</span><span class="ls37 va">\uebe5</span><span class="fsa vc">\uec2e</span></span></div><div class="t m0 x2f h21 y7b ff6 fs6 fc0 sc0 ls0 ws11">\ueda5<span class="ls28 v0">(</span><span class="ws1a v0">\ueb35\ueb3f\uebe5 <span class="fsa ls1c v1">\uec2e</span></span><span class="v0">)<span class="fsa ls1c v1">\uec2e</span><span class="v12">\ueb3e</span><span class="ls28">(</span><span class="ws19 v12">\ueb36.\uec15.\uebe5 </span><span class="ls28">)<span class="fsa ls29 v1">\uec2e</span></span><span class="ff2 ws0 v12"> <span class="fs4 v15"> </span></span></span></div><div class="t m0 x1 h1f y7c ff2 fs4 fc0 sc0 ls0 ws0">Antes: <span class="ff6 fs6 ws11 v16">\uebe0.\uebd1</span></div><div class="t m0 x30 h20 y7d ff6 fsa fc0 sc0 ls0">\uecdb\uecda</div><div class="t m0 xc h15 y7e ff6 fs6 fc0 sc0 ls34">\uebe0<span class="fsa ls35 v11">\uecda</span><span class="ls0 ws24">.\uebd7 <span class="fs4 ls38 v9">=</span><span class="ws11 va">\ueb34,\ueb3d\ueb3c</span><span class="fsa vc">\uec2e</span></span></div><div class="t m0 x31 h1b y7f ff6 fs6 fc0 sc0 ls0 ws11">\ueda5<span class="ls28 v0">(</span><span class="v12">\ueb35\ueb3f\ueb34,\ueb3d\ueb3c</span><span class="fsa ls1c v1">\uec2e</span><span class="ls28 v0">)<span class="fsa ls29 v1">\uec2e</span></span><span class="v12">\ueb3e</span><span class="ls28 v0">(</span><span class="v12">\ueb36.\ueb34,\ueb34\ueb39.\ueb34,\ueb3d\ueb3c<span class="_1 blank"></span><span class="ls28 v2">)<span class="fsa ls29 v1">\uec2e</span><span class="ff2 ls0 ws0 v12"> <span class="fs4 v15"> <span class="ff6 ws3">=<span class="ff3 ws0"> 9,33 </span></span> </span></span></span></span></div><div class="t m0 x1 h7 y80 ff2 fs4 fc0 sc0 ls0 ws0"> </div><div class="t m0 x1 h1f y81 ff2 fs4 fc0 sc0 ls0 ws0">Depois: <span class="ff6 fs6 ws11 v16">\uebe0.\uebd1</span></div><div class="t m0 x32 h20 y82 ff6 fsa fc0 sc0 ls0 ws16">\uecdb\uec2d</div><div class="t m0 x33 h15 y83 ff6 fs6 fc0 sc0 ls34">\uebe0<span class="fsa ls39 v11">\uecda</span><span class="ls0 ws25">.\uebd7 <span class="fs4 ls3a v9">=</span><span class="ws11 va">\ueb38,\ueb35\ueb39</span><span class="fsa vc">\uec2e</span></span></div><div class="t m0 x1a h1b y84 ff6 fs6 fc0 sc0 ls0 ws11">\ueda5<span class="ls28 v0">(</span><span class="v12">\ueb35\ueb3f\ueb38,\ueb35\ueb39</span><span class="fsa ls1c v1">\uec2e</span><span class="ls28 v0">)<span class="fsa ls29 v1">\uec2e</span></span><span class="v12">\ueb3e</span><span class="ls28 v0">(</span><span class="v12">\ueb36.\ueb34,\ueb34\ueb39.\ueb38,\ueb35\ueb39<span class="_1 blank"></span><span class="ls28 v2">)<span class="fsa ls29 v1">\uec2e</span><span class="ff2 ls2a ws0 v12"> </span><span class="fs4 ls3b v15">=<span class="ff8 ls0 ws0"> 1,06 <span class="ff9"> </span></span></span></span></span></div><div class="t m0 x1 h7 y85 ff2 fs4 fc0 sc0 ls0 ws0">Como a massas do sistema e de desbalanceamento não mudam, a relaç<span class="_1 blank"></span>ão entre a </div><div class="t m0 x1 h7 y86 ff2 fs4 fc0 sc0 ls0 ws0">amplitude antes e depois do isolador, será: </div><div class="t m0 x34 h16 y87 ff6 fs6 fc0 sc0 ls0">\uebd1</div><div class="t m0 x35 h20 y88 ff6 fsa fc0 sc0 ls0">\uecdb\uecda</div><div class="t m0 x34 h16 y89 ff6 fs6 fc0 sc0 ls0">\uebd1</div><div class="t m0 x35 h22 y8a ff6 fsa fc0 sc0 ls0 ws26">\uecdb\uec2d <span class="fs4 ls32 v16">=</span><span class="fs6 ws11 v17">\ueb3d,\ueb37\ueb37</span></div><div class="t m0 x36 h14 y89 ff6 fs6 fc0 sc0 ls0 ws11">\ueb35,\ueb34\ueb3a<span class="ff2 fs4 ws0 v9"> <span class="ff5 ls1">\uf0e0</span> <span class="ff6">\ue73a</span></span></div><div class="t m0 x15 h23 y8b ff6 fs6 fc0 sc0 ls0 ws27">\uebe3\ueb35 <span class="fs4 ws28 v1">= 0,11\ue73a</span></div><div class="t m0 x37 h16 y8b ff6 fs6 fc0 sc0 ls0 ws29">\uebe3\uebe2 <span class="ff2 fs4 ws0 v1"> </span></div><div class="t m0 x1 h7 y8c ff2 fs4 fc0 sc0 ls0 ws0">Ou seja, houve uma redução de 89% na ampli<span class="_1 blank"></span>tude após o uso do isolador de </div><div class="t m0 x1 h7 y8d ff2 fs4 fc0 sc0 ls0 ws0">vibrações. </div><div class="t m0 x1 h7 y8e ff2 fs4 fc0 sc0 ls0 ws0">Chegando assim ao resultado desejado. </div><div class="t m0 x1 h1d y8f ff2 fs0 fc0 sc0 ls0 ws0"> <span class="_12 blank"> </span> </div><div class="t m0 x1 h2 y90 ff1 fs0 fc0 sc0 ls0 ws0"> </div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div>
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