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Answers for Student Exercise 2.1 – 2.9 1 N a. benzonitrile H2N b. isobutylamine S O O c. diphenyl sulfone O O d. dioxane N+ O O- e. 1-nitropropane OHO f. formic acid g. biphenyl O HO h. benzoic acid O H2N i. benzamide O O Butyl acetate O NH2 Butyramide H2N Isobutylamine C11H23 O HO Lauric acid Na+ O O- Sodium propionate Spectrum E Spectrum H Spectrum I Spectrum F Spectrum G O Allyl phenyl ether O Benzaldehyde H HO o-Cresol O HO m-Toluic acid Spectrum L Spectrum M Spectrum K Spectrum J 2.1. Since the indicated carbon of phenylacetonitrile is sp3 hybridized, it is reasonable for this compound to show C−H stretching at less than 3000 cm-1 (2960-2940 cm-1). Where as benzonitrile has only aromatic C−H stretching which is typically between 3100 - 3000 cm-1 (page 87). 2.2. 2.3. 2.4. 2.5. C CH2 N phenylacetonitrile C N benzonitrile 1,3-Cyclohexadiene Diphenylacetylene 1-Octene 2-Pentene Spectrum B Spectrum A Spectrum D Spectrum C Answers for Student Exercise 2.1 – 2.9 2 H2N Aniline N N Azobenzene N HO Benzophenone oxime H2N Benzylamine NH2 Cl Dimethylamine hydrochloride Spectrum Q Spectrum O Spectrum P Spectrum N Spectrum R O O O O H enol 2.6. 2.7. Methyl isothiocyanate CH3−N=C=S 2.8. This diketone exists primarily (~ 90%) in enol form (in CCl4) Enols such as this display broad, shallow O−H stretching bands (here from 3400-2500 cm-1). The strong band at ~1600 cm-1 is the enolic coupled C=C−OH band. (See pages 80, 94, and 98) Answers for Student Exercise 2.1 – 2.9 3 O 4-Heptanone OH 3-Heptanol Br 4-Bromotoluene Br 2-Bromopentane O 2-Hexanone O OH Propionic Acid H2N Butylamine OH Propargyl alcohol N+ O O- 1-Nitropropane O OH 2-Phenoxylethanol O Phenetole O O Methyl Butyrate HO O O Methyl salicylate O HN Caprolactam N N 2-methylpyrazine N+ O -O Cl 1-Chloro-4-Nitrobenzene O HO Br 7-Bromo Heptanoic Acid HO 5-Hexyn-1-ol O 6-Methyl-5-hepten-2-one O HO Hexanoic acid Cl ClHO 2,6-Dichlorophenol HO 2,6-Dimethylphenol O 2-Cyclohexen-1-one A B C D E F G H I J K L M N O P Q R S T U V W H 2.9.
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