Cálculos de Circuitos Elétricos

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Alunos: Maicon Douglas Jorge de Moraes, Ryan Gaertner Fernandes, Yann Gonçalves. 
Q1) 
R = 1Ω 
E = 6V 
VD = 0.7V 
ID = (E – VD) / R = (6 – 0.7) / 1000 = 0.0053A 
VR = E – VD = 6 – 0.7 = 5.3V 
I = VR / R = 5.3 / 1000 = 0.0053A 
PD = I * V = 0.0053 * 0.7 = 0.00371W 
PR = 0.0053 * 5.3 = 0,02809W 
 
Q2) 
VD = 0.7 
V1 = 12V 
V2 = 6V 
R1 = 1Ω 
R2 = 1Ω 
R3 = 3Ω 
I3 = I1 + I2 
VR1 + VR3 + VD - V1 = 0 
12 = R1*I1 + R3*I3 + 0.7 
12 = 1*I1 + 3*I3 + 0.7 
11.3 = I1 + 3*I3  3*I3 = 11.3 - I1 
VR2 + VR3 + VD - V2 = 0 
6 = R2*I2 + R3*I3 + 0.7 
6 = 1*I2 + 3*I3 + 0.7 
5.3 = 12 + 3*I3  3I3 = 5.3 - I2 
 
I3 = 11.3 – 3*I3 + 5.3 – 3*I3 
I3 = 16.6 – 6*I3 
7*I3 = 16.6 
I3 = 2.37A 
 
3*I3 = 5.3 - I2 
3*2.37 = 5.3 – I2 
I2 = -7.11 + 5.3 
I2 = -1.81A 
 
3*I3 = 11.3 - I1 
I1 = -3*2.37 + 11.3 
I1 = -7.11 + 11.3 
I1 = 4.19A 
I1 
 
I2 
 
I3 
 
 
Q3) 
Vtotal – VD = (R1 + R2) * Itotal 
12 – 0.7 = (R1 + R2) * 0.006 
(R1 + R2) = 11.3 / 0.006 = 1.9kΩ 
2R = 1.9kΩ 
R =~ 1kΩ 
R1 = R2 = 1kΩ 
 
I1 = Itotal 
I3 = I1 – I2 
I3 = 6.6 – 4.8 = 1.8 mA 
 
VR1 + VR3 – V = 0 
R1 * I1 + R3 * I3 – V = 0 
1000 * 0.0066 + 0.0018 * R3 – 12 = 0 
R3 = (12 – 6.6) / 0.0018 = 3kΩ 
 
 
 
Q4) 
Vi = 5V 
R1 = 2KΩ 
R2 = 200KΩ 
Vi / R1 = -V0 / R2 
5 / 2000 = -V0 / 200000 
V0 = -(5 / 2000 * 200000) = -500V 
Q5) 
VCC = 10V 
Ic = 2mA 
VCE = VCC / 2 
B = 120 
 
Ic = Ib * B 
2000 = Ib * 120 
Ib = 2000 / 120 = 16.66 uA 
 
Tb = 10 – 0.7 = 9.3 
Ib = T / R 
16.66 * R = 9.3 
Rb = 9.3 / 16.66 = 558KΩ 
 
Vce = Vcc – Vrc 
Vcc / 2 = Vcc - Vrc 
Vrc = 10 – 5 = 5V 
 
Vrc = Rc * Ic 
5 = Rc * 2000 
Rc = 5 / 2000 = 2.5KΩ