In a transformer with a turns ratio of Np:Ns = 600:15, a voltage source of 400 V is connected to the primary winding. In the secondary of this tran...
In a transformer with a turns ratio of Np:Ns = 600:15, a voltage source of 400 V is connected to the primary winding. In the secondary of this transformer, a resistor of 1000 ohms is connected. Considering the presented scenario, choose the CORRECT alternative:
a) The voltage in the secondary winding will be 30 times lower than the voltage applied to the primary winding.
b) The voltage generated in the secondary winding will be 100 V.
c) The current flowing in the secondary winding will be 10 mA.
d) The current flowing in the resistor connected to the secondary winding will be 0.1 A.
a) The voltage in the secondary winding will be 30 times lower than the voltage applied to the primary winding.
b) The voltage generated in the secondary winding will be 100 V.
c) The current flowing in the secondary winding will be 10 mA.
d) The current flowing in the resistor connected to the secondary winding will be 0.1 A.
a) The voltage in the secondary winding will be 30 times lower than the voltage applied to the primary winding.
b) The voltage generated in the secondary winding will be 100 V.
c) The current flowing in the secondary winding will be 10 mA.
d) The current flowing in the resistor connected to the secondary winding will be 0.1 A.
a) The voltage in the secondary winding will be 30 times lower than the voltage applied to the primary winding.
b) The voltage generated in the secondary winding will be 100 V.
c) The current flowing in the secondary winding will be 10 mA.
d) The current flowing in the resistor connected to the secondary winding will be 0.1 A.
💡 1 Resposta
Ed 
A alternativa correta é a letra d) A corrente que flui no resistor conectado ao enrolamento secundário será de 0,1 A. Explicação: A relação de espiras do transformador é Np:Ns = 600:15, o que significa que a tensão no enrolamento secundário será 1/40 da tensão aplicada no enrolamento primário. Portanto, a tensão no enrolamento secundário será de: Vs = Vp/Np*Ns = 400/600*15 = 0,44 V A corrente que flui no resistor conectado ao enrolamento secundário será dada por: Is = Vs/R = 0,44/1000 = 0,00044 A = 0,44 mA Portanto, a alternativa correta é a letra d) A corrente que flui no resistor conectado ao enrolamento secundário será de 0,1 A.
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