What is the midpoint of the sides AB, BC, and AC of the triangle? a) AB = (1,0), BC = (-1.5,0.5), AC = (0.5,2.5) b) AB = (-1.5,0.5), BC = (0.5,2....
What is the midpoint of the sides AB, BC, and AC of the triangle?
a) AB = (1,0), BC = (-1.5,0.5), AC = (0.5,2.5)
b) AB = (-1.5,0.5), BC = (0.5,2.5), AC = (1,0)
c) AB = (0.5,2.5), BC = (-1.5,0.5), AC = (1,0)
a) AB = (1,0), BC = (-1.5,0.5), AC = (0.5,2.5)
b) AB = (-1.5,0.5), BC = (0.5,2.5), AC = (1,0)
c) AB = (0.5,2.5), BC = (-1.5,0.5), AC = (1,0)
💡 1 Resposta
Ed 
Para encontrar o ponto médio de um segmento de reta, é necessário somar as coordenadas dos pontos extremos e dividir por 2. Assim, temos: a) AB = ((1+(-1.5))/2, (0+0.5)/2) = (-0.25, 0.25) BC = ((-1.5+0.5)/2, (0.5+2.5)/2) = (-0.5, 1.5) AC = ((1+0.5)/2, (0+2.5)/2) = (0.75, 1.25) Portanto, os pontos médios dos lados AB, BC e AC são, respectivamente, (-0.25, 0.25), (-0.5, 1.5) e (0.75, 1.25).
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