Analysing the following exercises about the ionization of water and pH and pOH, choose the correct alternative: 01) A clothes bleach, of the "lau...
Analysing the following exercises about the ionization of water and pH and pOH, choose the correct alternative:
01) A clothes bleach, of the "laundry water" type, presents [OH–] approximately equal to 1.0 x 10–4 mol/L. In these conditions, the concentration of H+ will be of the order of:
a) 10–2.
b) 10–3.
c) 10–10.
d) 10–14.
e) zero.
02) Which of the expressions below is known as "water ion product, KW"?
a) Kw = [H2][O2].
b) Kw = [H+] / [OH–].
c) Kw = [H+][OH–].
d) Kw = [H2O].
e) Kw = [2H][O2].
a) 10–3 and Kw = [H+][OH–].
b) 10–2 and Kw = [H2O].
c) 10–14 and Kw = [H+] / [OH–].
d) 10–10 and Kw = [H2][O2].
e) Zero and Kw = [2H][O2].
01) A clothes bleach, of the "laundry water" type, presents [OH–] approximately equal to 1.0 x 10–4 mol/L. In these conditions, the concentration of H+ will be of the order of:
a) 10–2.
b) 10–3.
c) 10–10.
d) 10–14.
e) zero.
02) Which of the expressions below is known as "water ion product, KW"?
a) Kw = [H2][O2].
b) Kw = [H+] / [OH–].
c) Kw = [H+][OH–].
d) Kw = [H2O].
e) Kw = [2H][O2].
a) 10–3 and Kw = [H+][OH–].
b) 10–2 and Kw = [H2O].
c) 10–14 and Kw = [H+] / [OH–].
d) 10–10 and Kw = [H2][O2].
e) Zero and Kw = [2H][O2].
💡 1 Resposta
Ed 
01) A resposta correta é a letra b) 10^-10. A partir da concentração de OH- fornecida, podemos calcular a concentração de H+ utilizando a equação de produto iônico da água: [H+][OH-] = 10^-14. Substituindo o valor de [OH-] fornecido, temos: [H+][10^-4] = 10^-14. Isolando [H+], temos: [H+] = 10^-14 / 10^-4 = 10^-10. 02) A resposta correta é a letra c) Kw = [H+][OH-]. O produto iônico da água é definido como o produto das concentrações de íons H+ e OH-, ou seja, Kw = [H+][OH-].
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