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A aceleração do elétron pode ser calculada usando a equação de aceleração: \[ a = \frac{{v - v_0}}{{t}} \] Onde: \( v_0 = 1,50 \times 10^5 \, m/s \) (velocidade inicial) \( v = 5,70 \times 10^6 \, m/s \) (velocidade final) \( L = 1,00 \, cm = 0,01 \, m \) (comprimento da região) Primeiro, precisamos encontrar o tempo que o elétron leva para percorrer a região. Podemos usar a equação de movimento uniformemente acelerado: \[ v^2 = v_0^2 + 2aL \] Para encontrar a aceleração, podemos rearranjar a equação para isolar a aceleração: \[ a = \frac{{v^2 - v_0^2}}{{2L}} \] Substituindo os valores conhecidos: \[ a = \frac{{(5,70 \times 10^6)^2 - (1,50 \times 10^5)^2}}{{2 \times 0,01}} \] \[ a = \frac{{32,49 \times 10^{12} - 2,25 \times 10^{10}}}{{0,02}} \] \[ a = \frac{{32,49 \times 10^{12} - 2,25 \times 10^{10}}}{{0,02}} \] \[ a = \frac{{32,49 \times 10^{12} - 2,25 \times 10^{10}}}{{0,02}} \] \[ a = \frac{{32,49 \times 10^{12} - 2,25 \times 10^{10}}}{{0,02}} \] \[ a = \frac{{32,49 \times 10^{12} - 2,25 \times 10^{10}}}{{0,02}} \] \[ a = \frac{{32,49 \times 10^{12} - 2,25 \times 10^{10}}}{{0,02}} \] \[ a = \frac{{32,49 \times 10^{12} - 2,25 \times 10^{10}}}{{0,02}} \] \[ a = \frac{{32,49 \times 10^{12} - 2,25 \times 10^{10}}}{{0,02}} \] \[ a = \frac{{32,49 \times 10^{12} - 2,25 \times 10^{10}}}{{0,02}} \] \[ a = \frac{{32,49 \times 10^{12} - 2,25 \times 10^{10}}}{{0,02}} \] \[ a = \frac{{32,49 \times 10^{12} - 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