Sabendo que vale a soma das matrizes: [x1-5y]+[41-53]=[32-106] Determinar os valores de x e y, respectivamente

OBS.: x1 = 1x = x

[x -5y] + [41 -53] = [32 -106]

[x+41  -5y-53] = [32 -106]

----------------------------------------------

x+41 = 32  _________________________-5y - 53 = -106

x = 32 - 41_________________________ y = (-106 + 53)/-5

x = -9_____________________________ y = -53 / -5

__________________________________ y = 53/5

\(\[\begin{align} & 1x\text{ }=\text{ }x \\ & \left[ x\text{ }-5y \right]\text{ }+\text{ }\left[ 41\text{ }-53 \right]\text{ }=\text{ }\left[ 32\text{ }-106 \right] \\ & \left[ x+41~\text{ }-5y-53 \right]\text{ }=\text{ }\left[ 32\text{ }-106 \right] \\ & x+41\text{ }=\text{ }32~\text{ } \\ & -5y\text{ }-\text{ }53\text{ }=\text{ }-106 \\ & x\text{ }=\text{ }32\text{ }-\text{ }41 \\ & y\text{ }=\text{ }\frac{\left( -106\text{ }+\text{ }53 \right)}{-5} \\ & y\text{ }=\text{ }\frac{-53\text{ }}{-5}\text{ } \\ & \mathbf{x}\text{ }=\text{ }-\mathbf{9} \\ & \mathbf{y}\text{ }=\text{ }\frac{\mathbf{53}}{5} \\ \end{align}\] \)