Dada a função f(x) = 3x + 1, calcule:a) f(1)b) f(-2)c) f (-5)

4,-5,-14

a)

\[\eqalign{ & f(1) = f\left( {x = 1} \right) \cr & f\left( 1 \right) = 3 \cdot 1 + 1 \cr & f\left( 1 \right) = 3 + 1 \cr & \boxed{f\left( 1 \right) = 4} }\]

b)

\[\eqalign{ & f(-2) = f\left( {x = -2} \right) \cr & f\left( -2 \right) = 3 \cdot (-2) + 1 \cr & f\left( -2 \right) = -6 + 1 \cr & \boxed{f\left( 1 \right) = 5} }\]

c)

\[\eqalign{ & f(-5) = f\left( {x = -5} \right) \cr & f\left( -5 \right) = 3 \cdot (-5) + 1 \cr & f\left( -5\right) = -15 + 1 \cr & \boxed{f\left( 1 \right) = -14} }\]