<div id="pf1" class="pf w0 h0" data-page-no="1"><div class="pc pc1 w0 h0"><img class="bi x0 y0 w1 h0" alt="" src="https://files.passeidireto.com/2ad68bfe-a2d1-4610-a80e-55fd9936ed96/bg1.png"><div class="t m0 x1 h1 y1 ff1 fs0 fc0 sc0 ls1d ws42">Curso Enem Gratuit<span class="blank _0"></span>o</div><div class="t m0 x2 h2 y2 ff2 fs1 fc1 sc0 ls1e ws0">Impacthub<span class="blank"> </span><span class="ls1f ws1">Uniasselvi<span class="blank"> </span><span class="ls20 ws42">Enem 100%</span></span></div><div class="t m0 x2 h2 y3 ff2 fs1 fc1 sc0 ls21 ws2">Ac<span class="blank"> </span>a<span class="blank"> </span>t<span class="blank"> </span>e<span class="blank _1"> </span><span class="ls1f ws3">Univ<span class="blank _0"></span>esp<span class="blank"> </span><span class="ls22 ws4">Senac</span></span></div><div class="t m0 x3 h2 y4 ff2 fs1 fc1 sc0 ls23 ws42">Red<span class="blank _2"> </span>e <span class="blank _2"> </span>Vi<span class="blank _2"> </span>da</div><div class="t m0 x4 h3 y5 ff3 fs2 fc2 sc0 ls0">!<span class="ff1 fs0 fc3 ls1 ws42 v1"> <span class="fs3 fc4 ls24 ws5">ENTRAR</span></span></div><div class="c x5 y6 w2 h4"><div class="t m0 x6 h2 y7 ff4 fs1 fc2 sc0 ls25 ws42">Te<span class="blank _3"> </span>r<span class="blank _3"> </span>m<span class="blank _3"> </span>i<span class="blank _3"> </span>n<span class="blank _3"> </span>a<span class="blank _3"> </span>r<span class="blank _3"> </span> <span class="blank _3"> </span>Q<span class="blank _3"> </span>u<span class="blank _3"> </span>e<span class="blank _3"> </span>s<span class="blank _3"> </span>t<span class="blank _3"> </span>i<span class="blank _3"> </span>o<span class="blank _3"> </span>n<span class="blank _3"> </span>á<span class="blank _3"> </span>r<span class="blank _3"> </span>i<span class="blank _3"> </span>o</div></div><div class="t m0 x7 h5 y8 ff5 fs4 fc2 sc0 ls26 ws42">pH e pOH \u2013 Ex<span class="blank _0"></span>er<span class="blank _0"></span>cícios de Química</div><div class="t m0 x6 h6 y9 ff6 fs5 fc4 sc0 ls27 ws42">Av<span class="blank _4"> </span>a<span class="blank _5"> </span>l<span class="blank _5"> </span>i<span class="blank _5"> </span>e<span class="blank _5"> </span> <span class="blank _5"> </span>s<span class="blank _5"> </span>e<span class="blank _5"> </span>u<span class="blank _5"> </span>s<span class="blank _5"> </span> <span class="blank _5"> </span>c<span class="blank _5"> </span>o<span class="blank _5"> </span>n<span class="blank _4"> </span>h<span class="blank _5"> </span>e<span class="blank _5"> </span>c<span class="blank _5"> </span>i<span class="blank _5"> </span>m<span class="blank _5"> </span>e<span class="blank _5"> </span>n<span class="blank _5"> </span>t<span class="blank _5"> </span>o<span class="blank _5"> </span>s<span class="blank _5"> </span> <span class="blank _5"> </span>d<span class="blank _5"> </span>e<span class="blank _5"> </span> <span class="blank _5"> </span>Q<span class="blank _5"> </span>u<span class="blank _5"> </span>í<span class="blank _5"> </span>m<span class="blank _5"> </span>i<span class="blank _5"> </span>c<span class="blank _5"> </span>a<span class="blank _5"> </span> <span class="blank _5"> </span>c<span class="blank _5"> </span>o<span class="blank _5"> </span>m<span class="blank _5"> </span> <span class="blank _5"> </span>a</div><div class="t m0 x6 h6 ya ff6 fs5 fc4 sc0 ls28 ws42">lista de e<span class="blank _0"></span>x<span class="blank _0"></span>er<span class="blank _0"></span>cícios sobr<span class="blank _0"></span>e pH e pOH. Antes de</div><div class="t m0 x6 h6 yb ff6 fs5 fc4 sc0 ls29 ws42">res<span class="blank _2"> </span>o<span class="blank _2"> </span>lver<span class="blank _2"> </span> a<span class="blank _2"> </span>s <span class="blank _2"> </span>qu<span class="blank _2"> </span>e<span class="blank _2"> </span>stõ<span class="blank _2"> </span>es<span class="blank _2"> </span>, <span class="blank _2"> </span>co<span class="blank _2"> </span>nf<span class="blank _2"> </span>ir<span class="blank _2"> </span>a <span class="blank _2"> </span>um<span class="blank _2"> </span> re<span class="blank _2"> </span>su<span class="blank _2"> </span>mo<span class="blank _2"> </span> s<span class="blank _2"> </span>o<span class="blank _2"> </span>bre<span class="blank _2"> </span> o</div><div class="t m0 x6 h6 yc ff6 fs5 fc4 sc0 ls2a ws6">assunt<span class="blank _0"></span>o<span class="ff7 ls2b">!</span></div><div class="t m0 x6 h2 yd ff2 fs1 fc3 sc0 ls2c ws42">O cálculo do pH e do pOH estão sempr<span class="blank _0"></span>e pr<span class="blank _0"></span>esent<span class="blank _0"></span>es</div><div class="t m0 x6 h2 ye ff2 fs1 fc3 sc0 ls2c ws42">nas questões de v<span class="blank _6"></span>estibular<span class="blank _6"></span>es e já caíram vá<span class="blank _0"></span>rias v<span class="blank _6"></span>ezes</div><div class="t m0 x6 h2 yf ff2 fs1 fc3 sc0 ls2c ws42">no Enem. P<span class="blank _6"></span>ara se preparar para as pr<span class="blank _6"></span>ov<span class="blank _6"></span>as de Química,</div><div class="t m0 x6 h2 y10 ff2 fs1 fc3 sc0 ls1e ws42">confira o nosso r<span class="blank _0"></span>esumo e resolv<span class="blank _6"></span>a a li<span class="blank _2"> </span>s<span class="blank _0"></span>ta de ex<span class="blank _6"></span>er<span class="blank _0"></span>cícios</div><div class="t m0 x6 h2 y11 ff2 fs1 fc3 sc0 ls2d ws42">sobr<span class="blank _0"></span>e pH e pOH<span class="ff8 ls2b">!</span></div><div class="t m0 x6 h7 y12 ff9 fs2 fc4 sc0 ls2e ws42">Resu<span class="blank _2"> </span>mo s<span class="blank _2"> </span>obr<span class="blank _6"></span>e<span class="blank _2"> </span> pH e<span class="blank _2"> </span> pOH</div><div class="t m0 x6 h2 y13 ff2 fs1 fc3 sc0 ls2c ws42">Os v<span class="blank _6"></span>alores de pH e pOH r<span class="blank _0"></span>epresenta<span class="blank _0"></span>m a quantidade de</div><div class="t m0 x6 h2 y14 ff2 fs1 fc3 sc0 ls2">H<span class="ls22 ws42"> e OH<span class="blank _7"> </span> present<span class="blank _6"></span>es em uma <span class="fc0 ls2d ws7">solução</span><span class="ls2f">. Assim, serv<span class="blank _6"></span>e<span class="blank _2"> </span>m</span></span></div><div class="t m0 x6 h2 y15 ff2 fs1 fc3 sc0 ls1f ws42">para analisar a acidez e a basicidade de soluç<span class="blank _0"></span>ões</div><div class="t m0 x6 h2 y16 ff2 fs1 fc3 sc0 ls20 ws42">aquosas. Para calcular os v<span class="blank _6"></span>alores do pH e pOH de</div><div class="t m0 x6 h2 y17 ff2 fs1 fc3 sc0 ls2c ws42">uma solução<span class="blank _0"></span>, dev<span class="blank _6"></span>emos relembrar do pr<span class="blank _6"></span>ocesso de</div><div class="t m0 x6 h2 y18 ff2 fs1 fc0 sc0 ls1f ws8">equilíbrio<span class="fc3 ls22 ws42"> da água.</span></div><div class="t m0 x6 h2 y19 ff2 fs1 fc3 sc0 ls2c ws42">Quando a água sofr<span class="blank _6"></span>e o processo<span class="blank _0"></span> de autoionização<span class="blank _6"></span>, ela</div><div class="t m0 x6 h2 y1a ff2 fs1 fc3 sc0 ls30 ws42">fo<span class="blank _2"> </span>r<span class="blank _2"> </span>m<span class="blank _2"> </span>a <span class="blank _2"> </span>o<span class="blank _2"> </span>s <span class="blank _2"> </span>í<span class="blank _2"> </span>o<span class="blank _2"> </span>ns<span class="blank _2"> </span> <span class="blank _2"> </span>H<span class="blank _8"> </span><span class="ls22"> e OH<span class="blank _7"> </span><span class="ls2b">:</span></span></div><div class="t m0 x8 h2 y1b ff2 fs1 fc3 sc0 ls2b ws9">H<span class="blank"> </span>O<span class="blank _0"></span><span class="ff8 wsa">"<span class="blank _6"></span><span class="ff2 ws42"> <span class="ffa ls3">\u21cb</span><span class="ff8 wsa">"<span class="blank _6"></span><span class="ff2 ls22 ws42"> H+(aq)<span class="ff8 wsb">""</span> +<span class="ff8 wsb">""</span> OH-(aq)</span></span></span></span></div><div class="t m0 x9 h2 y1c ff2 fs1 fc0 sc0 ls2f ws42">Curso gratuito de R<span class="blank _6"></span>edação Enem</div><div class="t m0 x6 h2 y1d ff2 fs1 fc3 sc0 ls2f ws42">A partir desse proces<span class="blank _0"></span>so, é possív<span class="blank _6"></span>el calcular a</div><div class="t m0 x6 h2 y1e ff2 fs1 fc3 sc0 ls1e ws42">constante de equilíbrio da <span class="fc0 ls20 wsc">água</span><span class="ls22"> com a seguinte</span></div><div class="t m0 x6 h2 y1f ff2 fs1 fc3 sc0 ls30 wsd">fó<span class="blank"> </span>r<span class="blank"> </span>m<span class="blank"> </span>u<span class="blank"> </span>l<span class="blank"> </span>a<span class="blank"> </span>:</div><div class="t m0 xa h2 y20 ff4 fs1 fc4 sc0 ls31 ws42">Kw<span class="blank _4"> </span> <span class="blank _2"> </span>=<span class="blank _4"> </span> <span class="blank _4"> </span>[<span class="blank _4"> </span>H<span class="blank _9"> </span><span class="ls20">] . [OH<span class="blank _a"> </span><span class="ls2b">]</span></span></div><div class="t m0 x6 h2 y21 ff2 fs1 fc3 sc0 ls2f ws42">Como nessa autoionização é pr<span class="blank _6"></span>oduzido o mesmo</div><div class="t m0 x6 h2 y22 ff2 fs1 fc3 sc0 ls2c ws42">número<span class="blank _0"></span> de íons <span class="ls4">H<span class="ls22"> e OH<span class="blank _7"> </span><span class="ls2f">, a água é considerada</span></span></span></div><div class="t m0 x6 h2 y23 ff2 fs1 fc3 sc0 ls2c ws42">neutra. A <span class="fc0 ls1e wse">concentração</span><span class="ls22"> de H<span class="blank _a"> </span> possui o v<span class="blank _6"></span>alor de 10<span class="blank _b"> </span><span class="ls2f">, e</span></span></div><div class="t m0 x6 h2 y24 ff2 fs1 fc3 sc0 ls22 ws42">de OH<span class="blank _7"> </span> também é de 10<span class="blank _b"> </span><span class="ls2f">. A<span class="blank _0"></span>ssim, a constant<span class="blank _0"></span>e de</span></div><div class="t m0 x6 h2 y25 ff2 fs1 fc3 sc0 ls1f ws42">equilíbrio da água sempr<span class="blank _6"></span>e será de 10<span class="blank _c"> </span><span class="ls2b">:</span></div><div class="t m0 xb h2 y26 ff4 fs1 fc4 sc0 ls31 ws42">Kw<span class="blank _4"> </span> <span class="blank _2"> </span>=<span class="blank _4"> </span> <span class="blank _4"> </span>1<span class="blank _4"> </span>0</div><div class="t m0 x6 h2 y27 ff2 fs1 fc3 sc0 ls2f ws42">A partir desses apontamentos, podemos concluir que:</div><div class="t m0 xc h2 y28 ff2 fs1 fc3 sc0 ls1f ws42">Uma solução é ácida quando: [H<span class="blank _a"> </span><span class="ls2f">] > [OH<span class="blank _7"> </span><span class="ls2b">]</span></span></div><div class="t m0 xc h2 y29 ff2 fs1 fc3 sc0 ls1f ws42">Uma solução é básica quando: [H<span class="blank _a"> </span><span class="ls2f">] < [OH<span class="blank _7"> </span><span class="ls2b">]</span></span></div><div class="t m0 x6 h2 y2a ff2 fs1 fc3 sc0 ls2f ws42">A fim de que você ent<span class="blank _0"></span>enda como descobrir se uma</div><div class="t m0 x6 h2 y2b ff2 fs1 fc3 sc0 ls2d ws42">substância é ácida ou básica,<span class="blank _0"></span> confira o e<span class="blank _6"></span>xemplo do</div><div class="t m0 x6 h2 y2c ff2 fs1 fc3 sc0 ls32 ws42">vinagre, que apr<span class="blank _6"></span>esenta [H<span class="blank _a"> </span><span class="ls2f">] = 10<span class="blank _7"> </span><span class="ff8 ls2b wsa">³</span><span class="ls2c"> mol/L. Utiliz<span class="blank _0"></span>ando a</span></span></div><div class="t m0 x6 h2 y2d ff2 fs1 fc3 sc0 ls30 ws42">fó<span class="blank _2"> </span>r<span class="blank _2"> </span>m<span class="blank _2"> </span>ul<span class="blank _2"> </span>a<span class="blank _2"> </span>, <span class="blank _2"> </span>t<span class="blank _2"> </span>em<span class="blank _2"> </span>o<span class="blank _2"> </span>s<span class="blank _2"> </span>:</div><div class="t m0 xd h2 y2e ff2 fs1 fc0 sc0 ls20 ws42">E-book de Redação Enem</div><div class="t m0 xe h2 y2f ff2 fs1 fc3 sc0 ls33 ws42">Kw<span class="blank _4"> </span> <span class="blank _5"> </span>=<span class="blank _5"> </span> <span class="blank _4"> </span>[<span class="blank _5"> </span>H<span class="blank _d"> </span><span class="ls2f">] . [OH<span class="blank _7"> </span><span class="ls2b">]</span></span></div><div class="t m0 xf h2 y30 ff2 fs1 fc3 sc0 ls2f wsf">10<span class="blank"> </span><span class="ff8 ls2b wsa">"<span class="blank _0"></span><span class="ff2 ls22 ws42">= 10<span class="blank _e"> </span><span class="ff8 wsb">""</span>. [OH<span class="blank _7"> </span><span class="ls2b">]</span></span></span></div><div class="t m0 xf h2 y31 ff2 fs1 fc3 sc0 ls2f ws42">[OH-] =<span class="ff8 ls2b wsa">"<span class="blank _0"></span><span class="ff2 ls2f ws42"> 10<span class="blank _f"> </span><span class="ff8 ls2b wsa">"<span class="blank _0"></span><span class="ff2 ls22 ws4">mol/L</span></span></span></span></div><div class="t m0 x6 h2 y32 ff2 fs1 fc3 sc0 ls23 ws42">Por<span class="blank _2"> </span>t<span class="blank _2"> </span>an<span class="blank _2"> </span>to,<span class="blank _2"> </span> o<span class="blank _2"> </span> vi<span class="blank _2"> </span>na<span class="blank _2"> </span>gre<span class="blank _2"> </span> é<span class="blank _2"> </span> u<span class="blank _2"> </span>ma<span class="blank _2"> </span> s<span class="blank _2"> </span>ub<span class="blank _2"> </span>st<span class="blank _2"> </span>ân<span class="blank _2"> </span>ci<span class="blank _2"> </span>a <span class="blank _2"> </span>ác<span class="blank _2"> </span>ida<span class="blank _2"> </span>, <span class="blank _2"> </span>po<span class="blank _2"> </span>is<span class="blank _2"> </span> [<span class="blank _2"> </span>H<span class="blank _a"> </span><span class="ls2b">]</span></div><div class="t m0 x6 h2 y33 ff2 fs1 fc3 sc0 ls34 ws42">> [OH<span class="blank _7"> </span><span class="ls2f">]. Dessa maneira, podemos dizer que quanto</span></div><div class="t m0 x6 h2 y34 ff2 fs1 fc3 sc0 ls35 ws42">maior o pH, menor a acidez, e quanto menor o pH,</div><div class="t m0 x6 h2 y35 ff2 fs1 fc3 sc0 ls35 ws42">maior a acidez.</div><div class="t m0 x10 h2 y36 ff2 fs1 fc3 sc0 ls20 ws42">Escala de pH. De 1 a 6 a substância é ácida, 7 <span class="blank _2"> </span>é</div><div class="t m0 x11 h2 y37 ff2 fs1 fc3 sc0 ls2c ws42">neutra, e de 8 a 14 é básica. Font<span class="blank _6"></span>e da imagem:</div><div class="t m0 x12 h2 y38 ff2 fs1 fc3 sc0 ls1f ws8">https://bit.ly<span class="blank _10"></span>/3ET<span class="blank _11"></span>uDQ<span class="blank _6"></span>X</div><div class="t m0 x6 h5 y39 ff5 fs4 fc4 sc0 ls26 ws42">Como calcular pH e pOH</div><div class="t m0 x6 h2 y3a ff2 fs1 fc3 sc0 ls36 ws42">Pa<span class="blank _2"> </span>ra<span class="blank _2"> </span> <span class="blank _2"> </span>ca<span class="blank _2"> </span>lc<span class="blank _2"> </span>u<span class="blank _2"> </span>la<span class="blank _2"> </span>r<span class="blank _2"> </span> o<span class="blank _2"> </span> <span class="blank _2"> </span>pH<span class="blank _2"> </span> e<span class="blank _2"> </span> <span class="blank _2"> </span>pO<span class="blank _2"> </span>H<span class="blank _2"> </span>, <span class="blank _2"> </span>u<span class="blank _2"> </span>sa<span class="blank _2"> </span>m<span class="blank _2"> </span>os<span class="blank _2"> </span> <span class="blank _2"> </span>as<span class="blank _2"> </span> s<span class="blank _2"> </span>e<span class="blank _2"> </span>gu<span class="blank _2"> </span>i<span class="blank _2"> </span>nt<span class="blank _2"> </span>es</div><div class="t m0 x6 h2 y3b ff2 fs1 fc3 sc0 ls30 wsd">fó<span class="blank"> </span>r<span class="blank"> </span>m<span class="blank"> </span>u<span class="blank"> </span>l<span class="blank"> </span>a<span class="blank"> </span>s<span class="blank"> </span>:</div><div class="t m0 x13 h2 y3c ff4 fs1 fc4 sc0 ls34 ws42">pH = \u2013 log [H<span class="blank _8"> </span><span class="ls2b ws10">]<span class="ffb ls20 ws11">!!</span></span><span class="ls20"> e<span class="ffb ws11">!!!!</span> pOH = \u2013 log [OH<span class="blank _a"> </span><span class="ls2b">]</span></span></div><div class="t m0 x6 h2 y3d ff2 fs1 fc3 sc0 ls22 ws42">Sendo assim, a r<span class="blank _6"></span>elação entre pH e pOH equiv<span class="blank _6"></span>ale à</div><div class="t m0 x6 h2 y3e ff2 fs1 fc3 sc0 ls2d ws42">seguinte f<span class="blank _6"></span>órmula:</div><div class="t m0 x14 h2 y3f ff4 fs1 fc4 sc0 ls34 ws42">pH + pOH = 14</div><div class="t m0 x6 h7 y40 ff9 fs2 fc4 sc0 ls37 ws12">Vid<span class="blank _2"> </span>eo<span class="blank _2"> </span>au<span class="blank _2"> </span>la</div><div class="t m0 x6 h2 y41 ff2 fs1 fc3 sc0 ls2f ws42">Antes de r<span class="blank _0"></span>esolv<span class="blank _0"></span>er os e<span class="blank _0"></span>x<span class="blank _6"></span>ercícios sobre pH e pOH,</div><div class="t m0 x6 h2 y42 ff2 fs1 fc3 sc0 ls1e ws42">confira como utilizar essas f<span class="blank _0"></span>órmulas <span class="blank _2"> </span>na videoaula do</div><div class="t m0 x6 h2 y43 ff2 fs1 fc3 sc0 ls2c ws42">nosso canal<span class="blank _0"></span>:</div><div class="t m0 x6 h7 y44 ff9 fs2 fc4 sc0 ls38 ws42">Ex<span class="blank _6"></span>er<span class="blank _0"></span>cícios sobr<span class="blank _6"></span>e pH e pOH</div><div class="t m0 x6 h2 y45 ff2 fs1 fc3 sc0 ls23 ws42">Por<span class="blank _2"> </span> f<span class="blank _2"> </span>im<span class="blank _2"> </span>, <span class="blank _2"> </span>res<span class="blank _2"> </span>ol<span class="blank _2"> </span>va <span class="blank _2"> </span>a <span class="blank _2"> </span>lis<span class="blank _2"> </span>ta<span class="blank _2"> </span> d<span class="blank _2"> </span>e <span class="blank _2"> </span>ex<span class="blank _6"></span>e<span class="blank _2"> </span>rcí<span class="blank _2"> </span>ci<span class="blank _2"> </span>os<span class="blank _2"> </span> s<span class="blank _2"> </span>ob<span class="blank _2"> </span>re <span class="blank _2"> </span>pH<span class="blank _2"> </span> e<span class="blank _2"> </span> p<span class="blank _2"> </span>OH<span class="blank _2"> </span> e</div><div class="t m0 x6 h2 y46 ff2 fs1 fc3 sc0 ls39 ws42">teste<span class="blank _2"> </span> os <span class="blank _2"> </span>seus<span class="blank _2"> </span> con<span class="blank _2"> </span>hecim<span class="blank _2"> </span>entos<span class="blank _2"> </span><span class="ff8 ls2b">!</span></div><div class="t m0 x6 h5 y47 ff5 fs4 fc4 sc0 ls26 ws13">Compar<span class="blank"> </span>tilhe:</div><div class="c x0 y48 w0 h8"><div class="t m0 x15 h9 y49 ffc fs6 fc2 sc0 ls2b ws42">Simuladão Enem</div><div class="t m0 x15 h9 y4a ffc fs6 fc2 sc0 ls3a ws14">gr<span class="blank _6"></span>atuit<span class="blank _6"></span>o</div></div><div class="c x15 y4b w3 ha"><div class="t m0 x0 hb y4c ffd fs7 fc2 sc0 ls3b ws42"><span class="fc9 sc0">En</span><span class="fc9 sc0">em </span><span class="fc9 sc0">Act</span><span class="fc9 sc0">ion</span></div></div><div class="t m0 x16 hc y4d ff2 fs8 fc3 sc0 ls2b ws15">+<span class="blank"> </span>\u2013</div><div class="t m0 x17 hc y4e ff2 fs8 fc3 sc0 ls2b ws16">+<span class="blank"> </span>\u2013</div><div class="t m0 xd hc y4f ff2 fs8 fc3 sc0 ls2b">2</div><div class="t m0 x18 hc y50 ff4 fs8 fc4 sc0 ls2b ws17">+<span class="blank"> </span>\u2013</div><div class="t m0 x19 hc y51 ff2 fs8 fc3 sc0 ls2b ws16">+<span class="blank"> </span>\u2013</div><div class="t m0 x1a hc y52 ff2 fs8 fc3 sc0 ls5">+<span class="ls3c">-7</span></div><div class="t m0 x1b hc y53 ff2 fs8 fc3 sc0 ls6">\u2013<span class="ls3c">-7</span></div><div class="t m0 x1c hc y54 ff2 fs8 fc3 sc0 ls3c">-14</div><div class="t m0 x1d hc y55 ff4 fs8 fc4 sc0 ls7 ws18">-14</div><div class="t m0 x1e hc y56 ff2 fs8 fc3 sc0 ls2b ws19">+<span class="blank"> </span>\u2013</div><div class="t m0 x1f hc y57 ff2 fs8 fc3 sc0 ls2b ws19">+<span class="blank"> </span>\u2013</div><div class="t m0 x20 hc y58 ff2 fs8 fc3 sc0 ls2b ws1a">+<span class="blank"> </span>\u2013</div><div class="t m0 x18 hc y59 ff2 fs8 fc3 sc0 ls2b ws1b">+<span class="blank"> </span>\u2013</div><div class="t m0 x14 hc y5a ff2 fs8 fc3 sc0 ls3c ws1c">-14<span class="blank"> </span>-3<span class="blank _12"> </span><span class="ls2b">\u2013</span></div><div class="t m0 x1a hc y5b ff2 fs8 fc3 sc0 ls3c">-11</div><div class="t m0 x21 hc y5c ff2 fs8 fc3 sc0 ls2b">+</div><div class="t m0 x22 hc y5d ff2 fs8 fc3 sc0 ls2b">\u2013</div><div class="t m0 x23 hc y5e ff4 fs8 fc4 sc0 ls2b ws1d">+<span class="blank"> </span>\u2013</div><div class="c x24 y5f w4 hd"><div class="t m0 x6 he y60 ffe fs9 fc5 sc0 ls2b ws42">COMO CAL<span class="blank _6"></span>CULAR pH E pOH | R<span class="blank _6"></span>\u2026</div></div><div class="t m0 x6 h2 y61 ff4 fs1 fc4 sc0 ls20 ws42">(UEFS BA/2017)<span class="ffb ls2b wsa">!</span><span class="ls2b"> <span class="blank _6"></span><span class="ffb ls2f">!!</span></span></div><div class="t m0 x6 h2 y62 ff2 fs1 fc3 sc0 ls21 ws42">Ac<span class="blank _2"> </span>i<span class="blank _2"> </span>d<span class="blank _2"> </span>o<span class="blank _2"> </span>s<span class="blank _2"> </span>e<span class="blank _2"> </span> <span class="blank _2"> </span>e<span class="blank _2"> </span> <span class="blank _2"> </span>a<span class="blank _2"> </span>l<span class="blank _2"> </span>c<span class="blank _2"> </span>a<span class="blank _2"> </span>l<span class="blank _2"> </span>o<span class="blank _2"> </span>s<span class="blank _2"> </span>e<span class="blank _2"> </span> <span class="blank _2"> </span>s<span class="blank _2"> </span>ã<span class="blank _2"> </span>o<span class="blank _2"> </span> <span class="blank _2"> </span>e<span class="blank _2"> </span>st<span class="blank _2"> </span>a<span class="blank _2"> </span>d<span class="blank _2"> </span>o<span class="blank _2"> </span>s<span class="blank _2"> </span> <span class="blank _2"> </span>a<span class="blank _2"> </span>n<span class="blank _2"> </span>o<span class="blank _2"> </span>r<span class="blank _4"> </span>m<span class="blank _2"> </span>a<span class="blank _2"> </span>i<span class="blank _2"> </span>s<span class="blank _2"> </span> <span class="blank _2"> </span>re<span class="blank _2"> </span>s<span class="blank _2"> </span>u<span class="blank _2"> </span>l<span class="blank _2"> </span>t<span class="blank _2"> </span>a<span class="blank _2"> </span>n<span class="blank _2"> </span>t<span class="blank _2"> </span>e<span class="blank _2"> </span>s</div><div class="t m0 x6 h2 y63 ff2 fs1 fc3 sc0 ls22 ws42">de e<span class="blank _0"></span>x<span class="blank _6"></span>cesso de ácidos ou de bases no sangue. A<span class="blank _6"></span>cidose</div><div class="t m0 x6 h2 y64 ff2 fs1 fc3 sc0 ls1f ws42">é um e<span class="blank _6"></span>xces<span class="blank _6"></span>so de ácido no sangue, com pH abaix<span class="blank _6"></span>o de</div><div class="t m0 x6 h2 y65 ff2 fs1 fc3 sc0 ls3d ws42">7,<span class="blank _5"> </span>3<span class="blank _13"> </span>5<span class="blank _5"> </span>,<span class="blank _3"> </span> <span class="blank _13"> </span>e<span class="blank _13"> </span> <span class="blank _13"> </span>a<span class="blank _3"> </span>l<span class="blank _13"> </span>c<span class="blank _13"> </span>a<span class="blank _13"> </span>l<span class="blank _3"> </span>o<span class="blank _13"> </span>s<span class="blank _13"> </span>e<span class="blank _13"> </span> <span class="blank _3"> </span>é<span class="blank _13"> </span> <span class="blank _13"> </span>u<span class="blank _13"> </span>m<span class="blank _3"> </span> <span class="blank _13"> </span>e<span class="blank _3"> </span>x<span class="blank _5"> </span>c<span class="blank _13"> </span>e<span class="blank _13"> </span>s<span class="blank _3"> </span>s<span class="blank _13"> </span>o<span class="blank _13"> </span> <span class="blank _3"> </span>d<span class="blank _13"> </span>e<span class="blank _13"> </span> <span class="blank _13"> </span>b<span class="blank _3"> </span>a<span class="blank _13"> </span>s<span class="blank _13"> </span>e<span class="blank _13"> </span> <span class="blank _3"> </span>n<span class="blank _13"> </span>o<span class="blank _13"> </span> <span class="blank _13"> </span>s<span class="blank _3"> </span>a<span class="blank _13"> </span>n<span class="blank _13"> </span>g<span class="blank _13"> </span>u<span class="blank _3"> </span>e<span class="blank _13"> </span>,</div><div class="t m0 x6 h2 y66 ff2 fs1 fc3 sc0 ls1e ws42">com pH acima de 7<span class="blank _14"></span>,<span class="blank _6"></span>45<span class="blank _6"></span>. Muitos distúrbios e doenças</div><div class="t m0 x6 h2 y67 ff2 fs1 fc3 sc0 ls1f ws42">podem inter<span class="blank _2"> </span>f<span class="blank _6"></span>erir no contr<span class="blank _0"></span>ole do pH sanguíneo,</div><div class="t m0 x6 h2 y68 ff2 fs1 fc3 sc0 ls1e ws42">causando acidose ou alcalose.</div><div class="t m0 x25 h2 y69 ff2 fs1 fc3 sc0 ls2f ws42">(www<span class="blank _11"></span>.labtestsonline.<span class="blank _6"></span>org.br<span class="blank _11"></span>. A<span class="blank _6"></span>daptado.)</div><div class="t m0 x6 h2 y6a ff2 fs1 fc3 sc0 ls2c ws42">Os equilíbrios químicos simultâneos en<span class="blank _6"></span>v<span class="blank _0"></span>olvidos na</div><div class="t m0 x6 h2 y6b ff2 fs1 fc3 sc0 ls20 ws42">acidose respiratória es<span class="blank _0"></span>tão repr<span class="blank _6"></span>ese<span class="blank _2"> </span>ntados a seguir:</div><div class="t m0 x6 h2 y6c ff2 fs1 fc3 sc0 ls2">H<span class="ls2f ws42">(aq) + (aq) </span><span class="ff8 ls2b wsa">"<span class="blank _0"></span><span class="ff2 ls8">H<span class="ls2f ws1e">CO<span class="blank"> </span><span class="ls22 ws42"> (aq) </span></span><span class="ff8 ls2b">"<span class="blank _6"></span><span class="ff2 ls9">H<span class="ls2c ws42">O (</span><span class="fff ls2b">l</span><span class="ls2f ws42">) + CO<span class="blank _7"> </span><span class="ls22"> (g)</span></span></span></span></span></span></div><div class="t m0 x6 h2 y6d ff2 fs1 fc3 sc0 ls2c ws42">O risco de morte pela v<span class="blank _6"></span>ariação do pH sanguíneo</div><div class="t m0 x6 h2 y6e ff2 fs1 fc3 sc0 ls20 ws42">acontece quando o v<span class="blank _0"></span>alor do pH chega pró<span class="blank _6"></span>ximo a 6<span class="blank _6"></span>,<span class="blank _6"></span>8<span class="blank _0"></span>,</div><div class="t m0 x6 h2 y6f ff2 fs1 fc3 sc0 ls2c ws42">no caso de acidose, e a 7<span class="blank _15"></span>,<span class="blank _6"></span>8<span class="blank _6"></span>, no caso de alcalose. A</div><div class="t m0 x6 h2 y70 ff2 fs1 fc3 sc0 ls3e ws42">va<span class="blank _2"> </span>ri<span class="blank _2"> </span>a<span class="blank _2"> </span>çã<span class="blank _2"> </span>o <span class="blank _2"> </span>d<span class="blank _2"> </span>a <span class="blank _2"> </span>c<span class="blank _2"> </span>on<span class="blank _2"> </span>c<span class="blank _2"> </span>en<span class="blank _2"> </span>t<span class="blank _2"> </span>ra<span class="blank _2"> </span>ç<span class="blank _2"> </span>ão<span class="blank _2"> </span> d<span class="blank _2"> </span>o<span class="blank _2"> </span>s <span class="blank _2"> </span>í<span class="blank _2"> </span>on<span class="blank _2"> </span>s<span class="blank _2"> </span> H<span class="blank _8"> </span><span class="ls22"> no intervalo de</span></div><div class="t m0 x6 h2 y71 ff2 fs1 fc3 sc0 ls1f ws42">pH de 6<span class="blank _6"></span>,<span class="blank _6"></span>8 a 7<span class="blank _15"></span>,<span class="blank _6"></span>8 corresponde a</div><div class="t m0 x10 h2 y72 ff2 fs1 fc3 sc0 ls22 ws42"> 50 v<span class="blank _6"></span>ezes.</div><div class="t m0 x10 h2 y73 ff2 fs1 fc3 sc0 ls22 ws42"> 10 v<span class="blank _6"></span>ezes.</div><div class="t m0 x10 h2 y74 ff2 fs1 fc3 sc0 ls22 ws42"> 20 v<span class="blank _6"></span>ezes.</div><div class="t m0 x10 h2 y75 ff2 fs1 fc3 sc0 ls22 ws42"> 100 v<span class="blank _6"></span>ezes.</div><div class="t m0 x10 h2 y76 ff2 fs1 fc3 sc0 ls22 ws42"> 200 v<span class="blank _6"></span>ezes.</div><div class="t m0 x16 hc y77 ff2 fs8 fc3 sc0 lsa">+<span class="ls2b ws1f v2">2<span class="blank"> </span>3<span class="blank _16"> </span>2<span class="blank _17"> </span>2</span></div><div class="t m0 x26 hc y78 ff2 fs8 fc3 sc0 ls2b">+</div><div class="t m0 x6 h2 y79 ff4 fs1 fc4 sc0 ls20 ws42">(UNIT<span class="blank _11"></span>AU SP<span class="blank _10"></span>/2016)<span class="ffb ls2b wsa">!<span class="blank _0"></span><span class="ff4 ws42"> <span class="blank _6"></span><span class="ffb ls2f">!!</span></span></span></div><div class="t m0 x6 h2 y7a ff2 fs1 fc3 sc0 ls2c ws42">O pH de uma solução 0<span class="blank _10"></span>,<span class="blank _6"></span>005 M de NaOH é</div><div class="t m0 x6 h2 y7b ff2 fs1 fc3 sc0 ls2b ws42">D<span class="blank _6"></span>ad<span class="blank _6"></span>os<span class="blank _6"></span>: <span class="blank _6"></span>l<span class="blank _0"></span>o<span class="blank _0"></span>g<span class="blank _6"></span> 2<span class="blank _6"></span> =<span class="blank _6"></span> 0<span class="blank _11"></span>,<span class="blank _10"></span>30<span class="blank _6"></span>10<span class="blank _6"></span>3<span class="blank _0"></span>;<span class="blank _0"></span> <span class="blank _6"></span>lo<span class="blank _6"></span>g <span class="blank _6"></span>3 <span class="blank _6"></span>=<span class="blank _0"></span> <span class="blank _0"></span>0<span class="blank _10"></span>,<span class="blank _10"></span>477<span class="blank _6"></span>1<span class="blank _0"></span>2<span class="blank _0"></span>;<span class="blank _6"></span> l<span class="blank _6"></span>og<span class="blank _6"></span>5 <span class="blank _6"></span>=</div><div class="t m0 x6 h2 y7c ff2 fs1 fc3 sc0 ls3f ws42">0,6<span class="blank _2"> </span>9<span class="blank _4"> </span>8<span class="blank _2"> </span>9<span class="blank _2"> </span>7;<span class="blank _2"> </span> <span class="blank _4"> </span>l<span class="blank _2"> </span>o<span class="blank _4"> </span>g<span class="blank _2"> </span> <span class="blank _4"> </span>7<span class="blank _2"> </span> <span class="blank _2"> </span>=<span class="blank _4"> </span> <span class="blank _2"> </span>0,8<span class="blank _4"> </span>4<span class="blank _2"> </span>5<span class="blank _4"> </span>0<span class="blank _2"> </span>9</div><div class="t m0 x10 h2 y7d ff2 fs1 fc3 sc0 ls22 ws42"> 8<span class="blank _6"></span>,<span class="blank _6"></span>9</div><div class="t m0 x10 h2 y7e ff2 fs1 fc3 sc0 ls22 ws42"> 4<span class="blank _6"></span>,<span class="blank _6"></span>0</div><div class="t m0 x10 h2 y7f ff2 fs1 fc3 sc0 ls22 ws42"> 11<span class="blank _6"></span>,<span class="blank _6"></span>7</div><div class="t m0 x10 h2 y80 ff2 fs1 fc3 sc0 ls22 ws42"> 2,<span class="blank _10"></span>3</div><div class="t m0 x10 h2 y81 ff2 fs1 fc3 sc0 ls22 ws42"> 5<span class="blank _6"></span>,<span class="blank _6"></span>3</div><div class="t m0 x6 h2 y82 ff4 fs1 fc4 sc0 ls20 ws20">(UERN/2015)<span class="ffb ls2b wsa">!<span class="blank _0"></span><span class="ff4 ws42"> <span class="blank _6"></span><span class="ffb">!</span></span></span></div><div class="t m0 x6 h2 y83 ff2 fs1 fc3 sc0 ls2f ws42">Considere a concentração de uma solução de ácido</div><div class="t m0 x6 h2 y84 ff2 fs1 fc3 sc0 ls20 ws42">acético (CH<span class="blank _a"> </span><span class="ls2f">COOH) igual a 0<span class="blank _6"></span>,<span class="blank _6"></span>6 mol/L e o seu grau de</span></div><div class="t m0 x6 h2 y85 ff2 fs1 fc3 sc0 ls32 ws42">ionização igual a 3 % em temperatura ambiente. É</div><div class="t m0 x6 h2 y86 ff2 fs1 fc3 sc0 ls1e ws42">correto afirmar que</div><div class="t m0 x10 h2 y87 ff2 fs1 fc3 sc0 ls22 ws42"> A [H<span class="blank _a"> </span><span class="ls2f">] é igual 0<span class="blank _6"></span>,<span class="blank _6"></span>18<span class="blank _6"></span>.</span></div><div class="t m0 x10 h2 y88 ff2 fs1 fc3 sc0 ls22 ws42"> A constante de ionizaç<span class="blank _0"></span>ão é de,</div><div class="t m0 x4 h2 y89 ff2 fs1 fc3 sc0 ls20 ws42">apro<span class="blank _6"></span>ximadamente, 5<span class="blank _6"></span>,<span class="blank _6"></span>5 x 10<span class="blank _18"> </span><span class="ls2b">.</span></div><div class="t m0 x10 h2 y8a ff2 fs1 fc3 sc0 ls22 ws42"> A [H<span class="blank _a"> </span><span class="ls2f">] é pro<span class="blank _6"></span>v<span class="blank _0"></span>eniente de duas etapas.</span></div><div class="t m0 x10 h2 y8b ff2 fs1 fc3 sc0 ls22 ws42"> O v<span class="blank _6"></span>alor da [CH<span class="blank _a"> </span><span class="ls2f">COO<span class="blank _7"> </span>] é três v<span class="blank _0"></span>ezes maior que a</span></div><div class="t m0 x4 h2 y8c ff2 fs1 fc3 sc0 ls2f ws21">[H<span class="blank"> </span>].</div><div class="t m0 x27 hc y8d ff2 fs8 fc3 sc0 ls2b">3</div><div class="t m0 x28 hc y8e ff2 fs8 fc3 sc0 ls2b">+</div><div class="t m0 x29 hc y8f ff2 fs8 fc3 sc0 lsc">\u20134</div><div class="t m0 x28 hc y90 ff2 fs8 fc3 sc0 ls2b">+</div><div class="t m0 x2a hc y91 ff2 fs8 fc3 sc0 ls2b ws22">3<span class="blank"> </span>\u2013</div><div class="t m0 x10 hc y92 ff2 fs8 fc3 sc0 ls2b">+</div><div class="t m0 x6 h2 y93 ff4 fs1 fc4 sc0 ls20 ws42">(UNIRG T<span class="blank _6"></span>O/2017)<span class="ffb ls2b wsa">!<span class="blank _6"></span><span class="ff4 ws42"> <span class="ffb ls2f">!!</span></span></span></div><div class="t m0 x6 h2 y94 ff2 fs1 fc3 sc0 ls2f ws42">A partir dos dados sobre a concentração</div><div class="t m0 x6 h2 y95 ff2 fs1 fc3 sc0 ls1f ws42">hidro<span class="blank _0"></span>geniônica ou hidr<span class="blank _0"></span>o<span class="blank _6"></span>xiliônica a 25<span class="ff8 ls2b wsa">º<span class="blank _6"></span><span class="ff2 ls40 ws42">C , em <span class="blank _2"> </span>mol.L<span class="blank _b"> </span><span class="ls2b">,</span></span></span></div><div class="t m0 x6 h2 y96 ff2 fs1 fc3 sc0 ls22 ws42">de alguns pr<span class="blank _0"></span>odutos aqui apr<span class="blank _6"></span>esentados:</div><div class="t m0 x6 h2 y97 ff4 fs1 fc4 sc0 ls41 ws23">Produto<span class="ffb ws24">!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!</span><span class="ws42"> Concentr<span class="blank _0"></span>ação em mol.L</span></div><div class="t m0 x6 h2 y98 ffb fs1 fc4 sc0 ls2f ws25">!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!<span class="ff4 ws42"> de íons H<span class="blank _8"> </span> ou OH</span></div><div class="t m0 x6 h2 y99 ff2 fs1 fc3 sc0 ls2f ws42">Vinagre\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026..[OH<span class="blank _7"> </span>] = 1<span class="blank _6"></span>,<span class="blank _6"></span>010</div><div class="t m0 x6 h2 y9a ff2 fs1 fc3 sc0 ls2f ws42">Caf<span class="blank _6"></span>ezinh<span class="blank _2"> </span>o \u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.[H<span class="blank _a"> </span>] = 1<span class="blank _6"></span>,<span class="blank _6"></span>010</div><div class="t m0 x6 h2 y9b ff2 fs1 fc3 sc0 ls2f ws42">Clara de o<span class="blank _0"></span>v<span class="blank _6"></span>o\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026\u2026.[OH<span class="blank _7"> </span>] = 1<span class="blank _0"></span>,<span class="blank _6"></span>010</div><div class="t m0 x6 h2 y9c ff2 fs1 fc3 sc0 ls1e ws42">Desinf<span class="blank _0"></span>etante com amônia\u2026\u2026\u2026..<span class="ff8 ls2c ws26">""</span><span class="ls2c"> [H<span class="blank _a"> </span><span class="ls2f">] = 1<span class="blank _6"></span>,<span class="blank _6"></span>010</span></span></div><div class="t m0 x6 h2 y9d ff2 fs1 fc3 sc0 ls22 ws42">São f<span class="blank _6"></span>eitas as seguintes afirmações:</div><div class="t m0 x6 h2 y9e ff2 fs1 fc3 sc0 ls1e ws42">I. O v<span class="blank _0"></span>alor de pOH do cafezinho é 9<span class="blank _6"></span>.</div><div class="t m0 x6 h2 y9f ff2 fs1 fc3 sc0 ls1e ws42">II. A clara de ov<span class="blank _6"></span>o é mais básica qu<span class="blank _2"> </span>e o caf<span class="blank _6"></span>ezinho.</div><div class="t m0 x6 h2 ya0 ff2 fs1 fc3 sc0 ls1e ws42">III. Em relação aos pr<span class="blank _6"></span>od<span class="blank _2"> </span>ut<span class="blank _6"></span>os<span class="blank _2"> </span> aqui apr<span class="blank _6"></span>ese<span class="blank _2"> </span>ntados, a</div><div class="t m0 x6 h2 ya1 ff2 fs1 fc3 sc0 ls20 ws42">amostra mais alcalina é o vinagre.</div><div class="t m0 x6 h2 ya2 ff2 fs1 fc3 sc0 ls1e ws42">IV<span class="blank _14"></span>. O desinfetant<span class="blank _0"></span>e com amônia não apresentaria</div><div class="t m0 x6 h2 ya3 ff2 fs1 fc3 sc0 ls20 ws42">alteração na cor<span class="blank _11"></span>, após adição <span class="blank _2"> </span>de algumas gotas de</div><div class="t m0 x6 h2 ya4 ff2 fs1 fc3 sc0 ls30 wsd">fe<span class="blank"> </span>n<span class="blank"> </span>o<span class="blank"> </span>l<span class="blank"> </span>f<span class="blank"> </span>t<span class="blank"> </span>a<span class="blank"> </span>l<span class="blank"> </span>e<span class="blank"> </span>í<span class="blank"> </span>n<span class="blank"> </span>a<span class="blank"> </span>.</div><div class="t m0 x6 h2 ya5 ff2 fs1 fc3 sc0 ls42 ws42">Assi<span class="blank _2"> </span>nal<span class="blank _2"> </span>e a<span class="blank _2"> </span> ún<span class="blank _2"> </span>ica<span class="blank _2"> </span> al<span class="blank _2"> </span>ter<span class="blank _2"> </span>na<span class="blank _2"> </span>tiva <span class="blank _2"> </span>em <span class="blank _2"> </span>que<span class="blank _2"> </span> tod<span class="blank _2"> </span>os <span class="blank _2"> </span>os <span class="blank _2"> </span>iten<span class="blank _2"> </span>s <span class="blank _2"> </span>são</div><div class="t m0 x6 h2 ya6 ff2 fs1 fc3 sc0 ls1e wse">corretos.</div><div class="t m0 x10 h2 ya7 ff2 fs1 fc3 sc0 ls22 ws42"> II, apenas.</div><div class="t m0 x10 h2 ya8 ff2 fs1 fc3 sc0 ls22 ws42"> II e IV<span class="blank _14"></span>, apenas.</div><div class="t m0 x10 h2 ya9 ff2 fs1 fc3 sc0 ls22 ws42"> I e II, apenas.</div><div class="t m0 x10 h2 yaa ff2 fs1 fc3 sc0 ls22 ws42"> I e III, apenas.</div><div class="t m0 x2b hc yab ff2 fs8 fc3 sc0 lsc">\u20131</div><div class="t m0 x21 hc yac ff4 fs8 fc4 sc0 ls2b ws27">\u20131</div><div class="t m0 x2c hc yad ff4 fs8 fc4 sc0 ls2b ws28">+<span class="blank"> </span>\u2013</div><div class="t m0 x2d hc yae ff2 fs8 fc3 sc0 lsb">\u2013<span class="lsc ws29">\u201311</span></div><div class="t m0 x2e hc yaf ff2 fs8 fc3 sc0 lsd">+<span class="lsc">\u20135</span></div><div class="t m0 x2f hc yb0 ff2 fs8 fc3 sc0 lsb">\u2013<span class="lsc">\u20136</span></div><div class="t m0 x30 hc yb1 ff2 fs8 fc3 sc0 lsd">+<span class="lsc ws29">\u201312</span></div><div class="t m0 x6 h2 yb2 ff4 fs1 fc4 sc0 ls20 ws42">(F<span class="blank _6"></span>ac. Israelita de C. da Saúde Alber<span class="blank _2"> </span>t Einst<span class="blank _0"></span>ein</div><div class="t m0 x6 h2 yb3 ff4 fs1 fc4 sc0 ls32 ws2a">SP<span class="blank _10"></span>/2019)</div><div class="t m0 x6 h2 yb4 ff2 fs1 fc3 sc0 ls2f ws42">A tabela mostra v<span class="blank _6"></span>alores do pH da água líquida em</div><div class="t m0 x6 h2 yb5 ff2 fs1 fc3 sc0 ls22 ws42">dif<span class="blank _6"></span>erentes t<span class="blank _0"></span>emperaturas.</div><div class="t m0 x6 h2 yb6 ff2 fs1 fc3 sc0 ls2f ws42">A análise desses dados permite afirmar q<span class="blank _2"> </span>ue o pr<span class="blank _6"></span>oduto</div><div class="t m0 x6 h2 yb7 ff2 fs1 fc3 sc0 ls32 ws42">iônico da água, K<span class="blank _11"></span>w<span class="blank _10"></span>, _<span class="blank _6"></span>_<span class="blank _10"></span>_<span class="blank _6"></span>_<span class="blank _6"></span>_<span class="blank _6"></span>_<span class="blank _6"></span>_<span class="blank _6"></span>_<span class="blank _10"></span>_<span class="blank _6"></span>_ com a elev<span class="blank _6"></span>ação da</div><div class="t m0 x6 h2 yb8 ff2 fs1 fc3 sc0 ls39 ws42">temp<span class="blank _2"> </span>erat<span class="blank _2"> </span>ura <span class="blank _2"> </span>e qu<span class="blank _2"> </span>e a rea<span class="blank _2"> </span>ção <span class="blank _2"> </span>de a<span class="blank _2"> </span>utoio<span class="blank _2"> </span>nizaç<span class="blank _2"> </span>ão d<span class="blank _2"> </span>a ág<span class="blank _2"> </span>ua</div><div class="t m0 x6 h2 yb9 ff2 fs1 fc3 sc0 ls43 ws42">__________<span class="blank _2"> </span> <span class="blank _4"> </span>e<span class="blank _2"> </span>n<span class="blank _2"> </span>e<span class="blank _4"> </span>r<span class="blank _2"> </span>g<span class="blank _2"> </span>i<span class="blank _2"> </span>a<span class="blank _4"> </span>,<span class="blank _2"> </span> <span class="blank _4"> </span>s<span class="blank _2"> </span>e<span class="blank _2"> </span>n<span class="blank _4"> </span>d<span class="blank _2"> </span>o<span class="blank _2"> </span>,<span class="blank _4"> </span> <span class="blank _2"> </span>p<span class="blank _2"> </span>o<span class="blank _4"> </span>r<span class="blank _4"> </span>t<span class="blank _2"> </span>a<span class="blank _2"> </span>n<span class="blank _4"> </span>t<span class="blank _2"> </span>o<span class="blank _2"> </span>,<span class="blank _2"> </span> <span class="blank _4"> </span>u<span class="blank _2"> </span>m<span class="blank _2"> </span> <span class="blank _4"> </span>p<span class="blank _2"> </span>r<span class="blank _2"> </span>o<span class="blank _2"> </span>c<span class="blank _4"> </span>e<span class="blank _2"> </span>s<span class="blank _2"> </span>s<span class="blank _2"> </span>o</div><div class="t m0 x6 h2 yba ff2 fs1 fc3 sc0 ls43 ws2b">__________<span class="blank"> </span>.</div><div class="t m0 x6 h2 ybb ff2 fs1 fc3 sc0 ls42 ws42">As <span class="blank _2"> </span>lac<span class="blank _2"> </span>una<span class="blank _2"> </span>s d<span class="blank _2"> </span>o tex<span class="blank _2"> </span>to d<span class="blank _2"> </span>ev<span class="blank _6"></span>e<span class="blank _2"> </span>m s<span class="blank _2"> </span>er <span class="blank _2"> </span>pree<span class="blank _2"> </span>nch<span class="blank _2"> </span>ida<span class="blank _2"> </span>s p<span class="blank _2"> </span>or:</div><div class="t m0 x10 h2 ybc ff2 fs1 fc3 sc0 ls22 ws42"> aumenta \u2013 absorv<span class="blank _0"></span>e \u2013 e<span class="blank _0"></span>x<span class="blank _6"></span>otérmico.</div><div class="t m0 x10 h2 ybd ff2 fs1 fc3 sc0 ls22 ws42"> diminui \u2013 absorv<span class="blank _0"></span>e \u2013 endotérmico.</div><div class="t m0 x10 h2 ybe ff2 fs1 fc3 sc0 ls22 ws42"> diminui \u2013 libera \u2013 e<span class="blank _6"></span>xot<span class="blank _0"></span>érmico.</div><div class="t m0 x10 h2 ybf ff2 fs1 fc3 sc0 ls22 ws42"> aumenta \u2013 absorv<span class="blank _0"></span>e \u2013 endotérmico.</div><div class="t m0 x10 h2 yc0 ff2 fs1 fc3 sc0 ls22 ws42"> aumenta \u2013 libera \u2013 endotérmico.</div><div class="t m0 x6 h2 yc1 ff4 fs1 fc4 sc0 ls20 ws42">(UEG GO<span class="blank _6"></span>/2020)<span class="ffb ls2b wsa">!</span><span class="ls2b"> <span class="blank _6"></span><span class="ffb ls2f">!!</span></span></div><div class="t m0 x6 h2 yc2 ff2 fs1 fc3 sc0 ls1f ws42">Uma solução aquosa de ácido clorídric<span class="blank _0"></span>o, cont<span class="blank _0"></span>endo</div><div class="t m0 x6 h2 yc3 ff2 fs1 fc3 sc0 ls3f ws42">0,0<span class="blank _2"> </span>9<span class="blank _4"> </span>1<span class="blank _2"> </span>2<span class="blank _2"> </span>5<span class="blank _4"> </span> <span class="blank _2"> </span>g<span class="blank _4"> </span> <span class="blank _2"> </span>d<span class="blank _4"> </span>e<span class="blank _2"> </span> <span class="blank _2"> </span>H<span class="blank _4"> </span>C<span class="blank _2"> </span>l<span class="blank _4"> </span>,<span class="blank _2"> </span> <span class="blank _4"> </span>fo<span class="blank _4"> </span>i<span class="blank _2"> </span> <span class="blank _4"> </span>d<span class="blank _2"> </span>i<span class="blank _2"> </span>l<span class="blank _4"> </span>u<span class="blank _2"> </span>í<span class="blank _4"> </span>d<span class="blank _2"> </span>a<span class="blank _2"> </span> <span class="blank _4"> </span>c<span class="blank _2"> </span>o<span class="blank _4"> </span>m<span class="blank _2"> </span> <span class="blank _4"> </span>á<span class="blank _2"> </span>g<span class="blank _2"> </span>u<span class="blank _4"> </span>a<span class="blank _2"> </span> <span class="blank _4"> </span>p<span class="blank _2"> </span>a<span class="blank _4"> </span>r<span class="blank _2"> </span>a<span class="blank _2"> </span> <span class="blank _4"> </span>2<span class="blank _2"> </span>5<span class="blank _4"> </span>0<span class="blank _2"> </span> <span class="blank _4"> </span>m<span class="blank _2"> </span>L<span class="blank _2"> </span>,</div><div class="t m0 x6 h2 yc4 ff2 fs1 fc3 sc0 ls1f ws42">em um balão v<span class="blank _6"></span>olumétrico.</div><div class="t m0 x6 h2 yc5 ff4 fs1 fc4 sc0 ls44 ws2c">Dado<span class="blank _2"> </span><span class="ff2 fc3 ls2f ws42">: MM(HCl) = 36<span class="blank _10"></span>,<span class="blank _6"></span>5 g/mol.</span></div><div class="t m0 x6 h2 yc6 ff2 fs1 fc3 sc0 ls2c ws42">O pH dessa solução<span class="blank _0"></span> será igual a:</div><div class="t m0 x10 h2 yc7 ff2 fs1 fc3 sc0 ls22 ws42"> 9</div><div class="t m0 x10 h2 yc8 ff2 fs1 fc3 sc0 ls22 ws42"> 0<span class="blank _6"></span>,<span class="blank _6"></span>2</div><div class="t m0 x10 h2 yc9 ff2 fs1 fc3 sc0 ls22 ws42"> 2</div><div class="t m0 x10 h2 yca ff2 fs1 fc3 sc0 ls22 ws42"> 0<span class="blank _6"></span>,<span class="blank _6"></span>1</div><div class="t m0 x10 h2 ycb ff2 fs1 fc3 sc0 ls22 ws42"> 1</div><div class="t m0 x6 h2 ycc ff4 fs1 fc4 sc0 ls20 ws20">(IF<span class="blank _6"></span>AL/2017)<span class="ffb ls2b wsa">!<span class="blank _6"></span><span class="ff4 ws42"> <span class="ffb ls2f">!!</span></span></span></div><div class="t m0 x6 h2 ycd ff2 fs1 fc3 sc0 ls2c ws42">O potencial de hidr<span class="blank _6"></span>ogênio (pH) das soluções é dado</div><div class="t m0 x6 h2 yce ff2 fs1 fc3 sc0 ls1f ws42">pela função: pH = \u2013log[H<span class="blank _a"> </span><span class="ls2f">], onde [H<span class="blank _a"> </span>] é a</span></div><div class="t m0 x6 h2 ycf ff2 fs1 fc3 sc0 ls1e ws42">concentração do cátion H<span class="blank _a"> </span><span class="ls22"> ou H<span class="blank _a"> </span><span class="lse">O</span> na solução. Se,</span></div><div class="t m0 x6 h2 yd0 ff2 fs1 fc3 sc0 ls1f ws42">em uma solução, a<span class="blank _0"></span> concentração de H<span class="blank _a"> </span><span class="ls22"> é 2.<span class="blank _10"></span>10<span class="blank _19"> </span><span class="ls2f">, qual</span></span></div><div class="t m0 x6 h2 yd1 ff2 fs1 fc3 sc0 ls2f ws42">o pH dessa solução<span class="ff8 ls2b wsa">?<span class="blank _6"></span><span class="ff2 ls2f ws42"> A<span class="blank _0"></span>dote: log 2 = 0<span class="blank _10"></span>,3<span class="blank _10"></span>.</span></span></div><div class="t m0 x10 h2 yd2 ff2 fs1 fc3 sc0 ls22 ws42"> 6<span class="blank _6"></span>,<span class="blank _6"></span>7<span class="blank _15"></span>.</div><div class="t m0 x10 h2 yd3 ff2 fs1 fc3 sc0 ls22 ws42"> 3<span class="blank _6"></span>,<span class="blank _6"></span>8<span class="blank _6"></span>.</div><div class="t m0 x10 h2 yd4 ff2 fs1 fc3 sc0 ls22 ws42"> 7<span class="blank _15"></span>,<span class="blank _6"></span>7<span class="blank _14"></span>.</div><div class="t m0 x10 h2 yd5 ff2 fs1 fc3 sc0 ls22 ws42"> 11<span class="blank _6"></span>.</div><div class="t m0 x10 h2 yd6 ff2 fs1 fc3 sc0 ls22 ws42"> 2,<span class="blank _10"></span>4<span class="blank _6"></span>.</div><div class="t m0 x31 hc yd7 ff2 fs8 fc3 sc0 ls2b ws2d">+<span class="blank"> </span>+</div><div class="t m0 x20 hc yd8 ff2 fs8 fc3 sc0 lsf">+<span class="ls10 v2">3</span><span class="ls2b">+</span></div><div class="t m0 x32 hc yd9 ff2 fs8 fc3 sc0 ls11">+<span class="ls3c">-8</span></div><div class="t m0 x6 h2 yda ff4 fs1 fc4 sc0 ls20 ws42">(IT<span class="blank _11"></span>A SP<span class="blank _6"></span>/2020)<span class="ffb ls2b wsa">!<span class="blank _6"></span><span class="ff4 ws42"> <span class="ffb ls2f">!!</span></span></span></div><div class="t m0 x6 h2 ydb ff2 fs1 fc3 sc0 ls2f ws42">Considere que o ar seco ao nív<span class="blank _6"></span>el do mar é composto</div><div class="t m0 x6 h2 ydc ff2 fs1 fc3 sc0 ls22 ws42">de 410<span class="blank _1a"> </span> % (em v<span class="blank _6"></span>olume) de CO<span class="blank _a"> </span><span class="ls2f">. Sejam dadas a</span></div><div class="t m0 x6 h2 ydd ff2 fs1 fc3 sc0 ls1e ws42">constante da lei de Henry para o CO<span class="blank _a"> </span><span class="ls22"> e a constant<span class="blank _0"></span>e da</span></div><div class="t m0 x6 h2 yde ff2 fs1 fc3 sc0 ls1f ws42">primeira dissocia<span class="blank _0"></span>ção do ácido carbônico<span class="blank _6"></span>,</div><div class="t m0 x6 h2 ydf ff2 fs1 fc3 sc0 ls45 ws42">res<span class="blank _2"> </span>pe<span class="blank _2"> </span>c<span class="blank _2"> </span>ti<span class="blank _2"> </span>vam<span class="blank _2"> </span>en<span class="blank _2"> </span>te,<span class="blank _2"> </span> K<span class="blank _1b"> </span><span class="ls22"> = 2,<span class="blank _10"></span>510<span class="blank _1c"> </span> mol L<span class="blank _b"> </span> atm<span class="blank _b"> </span> e K<span class="blank _1d"> </span> =</span></div><div class="t m0 x6 h2 ye0 ff2 fs1 fc3 sc0 ls2f ws42">110<span class="blank _1e"> </span>. As<span class="blank _0"></span>sinale a opção que apresenta a</div><div class="t m0 x6 h2 ye1 ff2 fs1 fc3 sc0 ls1e ws42">concentração em mol L<span class="blank _b"> </span><span class="ls22"> de CO<span class="blank _a"> </span> dis<span class="blank _0"></span>solvido e o pH de</span></div><div class="t m0 x6 h2 ye2 ff2 fs1 fc3 sc0 ls2c ws42">uma amostra de água desioniz<span class="blank _0"></span>ada, após a mesma</div><div class="t m0 x6 h2 ye3 ff2 fs1 fc3 sc0 ls1f ws42">entrar em equilíbrio com o ar atmosf<span class="blank _6"></span>érico.</div><div class="t m0 x10 h2 ye4 ff2 fs1 fc3 sc0 ls22 ws42"> 10<span class="blank _1a"> </span> e 5<span class="blank _10"></span>,<span class="blank _6"></span>7</div><div class="t m0 x10 h2 ye5 ff2 fs1 fc3 sc0 ls22 ws42"> 10<span class="blank _1a"> </span> e 6<span class="blank _10"></span>,<span class="blank _6"></span>4</div><div class="t m0 x10 h2 ye6 ff2 fs1 fc3 sc0 ls22 ws42"> 10<span class="blank _1c"> </span> e 5<span class="blank _6"></span>,<span class="blank _6"></span>7</div><div class="t m0 x10 h2 ye7 ff2 fs1 fc3 sc0 ls22 ws42"> 10<span class="blank _1a"> </span> e 6<span class="blank _6"></span>,<span class="blank _6"></span>4</div><div class="t m0 x10 h2 ye8 ff2 fs1 fc3 sc0 ls22 ws42"> 10<span class="blank _1c"> </span> e 6<span class="blank _6"></span>,<span class="blank _6"></span>4</div><div class="t m0 x13 hc ye9 ff2 fs8 fc3 sc0 lsc ws2e">\u20132<span class="blank"> </span><span class="ls2b v2">2</span></div><div class="t m0 x33 hc yea ff2 fs8 fc3 sc0 ls2b">2</div><div class="t m0 x34 hf yeb ff2 fs8 fc3 sc0 ls12">H<span class="lsc ws2f v3">\u20132<span class="blank _1f"> </span>\u20131<span class="blank _20"> </span>\u20131<span class="blank"> </span></span><span class="ls2b">a</span></div><div class="t m0 x35 hc yec ff2 fs8 fc3 sc0 lsc ws29">\u20136<span class="blank _6"></span>,4</div><div class="t m0 x36 hc yed ff2 fs8 fc3 sc0 lsc ws30">\u20131<span class="blank"> </span><span class="ls2b v2">2</span></div><div class="t m0 x1b hc yee ff2 fs8 fc3 sc0 lsc">\u20137</div><div class="t m0 x1b hc yef ff2 fs8 fc3 sc0 lsc">\u20137</div><div class="t m0 x1b hc yf0 ff2 fs8 fc3 sc0 lsc">\u20135</div><div class="t m0 x1b hc yf1 ff2 fs8 fc3 sc0 lsc">\u20132</div><div class="t m0 x1b hc yf2 ff2 fs8 fc3 sc0 lsc">\u20135</div><div class="t m0 x6 h2 yf3 ff4 fs1 fc4 sc0 ls20 ws42">(IT<span class="blank _11"></span>A SP<span class="blank _6"></span>/2018)<span class="ffb ls2b wsa">!<span class="blank _6"></span><span class="ff4 ws42"> <span class="ffb ls2f">!!</span></span></span></div><div class="t m0 x6 h2 yf4 ff2 fs1 fc3 sc0 ls2f ws42">Considere dadas as constant<span class="blank _0"></span>es de dissociação ácida</div><div class="t m0 x6 h2 yf5 ff2 fs1 fc3 sc0 ls2f ws42">(K<span class="blank _1d"> </span>) ou básica (K<span class="blank _a"> </span>) das seguintes substâncias, a 25<span class="ff8 ls2b wsa">º<span class="blank _6"></span><span class="ff2 ls2f">C:</span></span></div><div class="t m0 x6 h2 yf6 ff2 fs1 fc3 sc0 ls30 ws42">fe<span class="blank _2"> </span>n<span class="blank _2"> </span>ol<span class="blank _2"> </span> <span class="blank _2"> </span>(C<span class="blank _21"> </span><span class="ls13">H<span class="ls2c">OH), K<span class="blank _1d"> </span><span class="ls22"> = 110<span class="blank _22"> </span> e anilina (C<span class="blank _a"> </span><span class="ls14">H</span><span class="ws31">NH<span class="blank"> </span></span><span class="ls2f">), K<span class="blank _a"> </span></span> =</span></span></span></div><div class="t m0 x6 h2 yf7 ff2 fs1 fc3 sc0 ls1f ws32">710<span class="blank"> </span><span class="ls2b">.</span></div><div class="t m0 x6 h2 yf8 ff2 fs1 fc3 sc0 ls22 ws42">Sobre o pH de soluç<span class="blank _0"></span>ões aquosas dessas subs<span class="blank _0"></span>tâncias</div><div class="t m0 x6 h2 yf9 ff2 fs1 fc3 sc0 ls2d ws42">são f<span class="blank _6"></span>eitas as seguintes afirmações:</div><div class="t m0 x6 h2 yfa ff2 fs1 fc3 sc0 ls1e ws42">I. A solução aquosa de fenol a 110<span class="blank _18"> </span><span class="ls22"> mol L<span class="blank _b"> </span> t<span class="blank _0"></span>em pH <</span></div><div class="t m0 x6 h2 yfb ff2 fs1 fc3 sc0 ls46">5.</div><div class="t m0 x6 h2 yfc ff2 fs1 fc3 sc0 ls1e ws42">II. A solução aquosa de anilin<span class="blank _2"> </span>a a 110<span class="blank _1c"> </span><span class="ls22"> mol L<span class="blank _b"> </span> tem pH</span></div><div class="t m0 x6 h2 yfd ff2 fs1 fc3 sc0 ls34 ws42">> 9<span class="blank _6"></span>.</div><div class="t m0 x6 h2 yfe ff2 fs1 fc3 sc0 ls1e ws42">III. Ambas as soluções aquosas<span class="blank _2"> </span> a 1100<span class="blank _1c"> </span><span class="ls22"> mol L<span class="blank _b"> </span> têm</span></div><div class="t m0 x6 h2 yff ff2 fs1 fc3 sc0 ls1f ws42">pH apr<span class="blank _0"></span>o<span class="blank _6"></span>ximadamente iguais.</div><div class="t m0 x6 h2 y100 ff2 fs1 fc3 sc0 ls1e ws42">Das afirmações<span class="blank _2"> </span> acima está(ão) CORRET<span class="blank _14"></span>A(S)</div><div class="t m0 x10 h2 y101 ff2 fs1 fc3 sc0 ls22 ws42"> apenas III.</div><div class="t m0 x10 h2 y102 ff2 fs1 fc3 sc0 ls22 ws42"> apenas II.</div><div class="t m0 x10 h2 y103 ff2 fs1 fc3 sc0 ls22 ws42"> apenas II e III.</div><div class="t m0 x10 h2 y104 ff2 fs1 fc3 sc0 ls22 ws42"> apenas I.</div><div class="t m0 x10 h2 y105 ff2 fs1 fc3 sc0 ls22 ws42"> apenas I e II.</div><div class="t m0 x37 hc y106 ff2 fs8 fc3 sc0 ls2b ws33">a<span class="blank"> </span>b</div><div class="t m0 x38 hf y107 ff2 fs8 fc3 sc0 ls2b ws34">6<span class="blank"> </span>5<span class="blank _23"> </span>a<span class="blank _24"> </span><span class="lsc ws35 v3">\u201310<span class="blank"> </span></span><span class="ws36">6<span class="blank"> </span>5<span class="blank _25"> </span>2<span class="blank _26"> </span>b</span></div><div class="t m0 x10 hc y108 ff2 fs8 fc3 sc0 lsc ws29">\u201310</div><div class="t m0 x2d hc y109 ff2 fs8 fc3 sc0 lsc ws37">\u20134<span class="blank"> </span>\u20131</div><div class="t m0 x39 hc y10a ff2 fs8 fc3 sc0 lsc ws38">\u20134<span class="blank"> </span>\u20131</div><div class="t m0 x1e hc y10b ff2 fs8 fc3 sc0 lsc ws38">\u20134<span class="blank"> </span>\u20131</div><div class="t m0 x6 h2 y10c ff4 fs1 fc4 sc0 ls20 ws42">(A<span class="blank _6"></span>C<span class="blank _0"></span>AFE SC/2019)<span class="ffb ls2b wsa">!<span class="blank _0"></span><span class="ff4 ws42"> <span class="blank _0"></span><span class="ffb ls2f">!!</span></span></span></div><div class="t m0 x6 h2 y10d ff2 fs1 fc3 sc0 ls2f ws42">Considere o tr<span class="blank _6"></span>echo retirado de um artigo da revis<span class="blank _0"></span>ta</div><div class="t m0 x6 h2 y10e ff2 fs1 fc3 sc0 ls47 ws42">Ve<span class="blank _4"> </span>j<span class="blank _4"> </span>a<span class="blank _2"> </span> <span class="blank _4"> </span>p<span class="blank _4"> </span>u<span class="blank _4"> </span>b<span class="blank _4"> </span>l<span class="blank _4"> </span>i<span class="blank _4"> </span>c<span class="blank _4"> </span>a<span class="blank _2"> </span>d<span class="blank _4"> </span>a<span class="blank _4"> </span> <span class="blank _4"> </span>n<span class="blank _4"> </span>o<span class="blank _4"> </span> <span class="blank _4"> </span>d<span class="blank _4"> </span>i<span class="blank _4"> </span>a<span class="blank _2"> </span> <span class="blank _4"> </span>1<span class="blank _4"> </span>3<span class="blank _4"> </span>/<span class="blank _4"> </span>0<span class="blank _4"> </span>5<span class="blank _4"> </span>/<span class="blank _4"> </span>2<span class="blank _2"> </span>0<span class="blank _4"> </span>1<span class="blank _4"> </span>6<span class="blank _4"> </span> <span class="blank _4"> </span>r<span class="blank _2"> </span>e<span class="blank _4"> </span>l<span class="blank _4"> </span>a<span class="blank _4"> </span>t<span class="blank _4"> </span>a<span class="blank _2"> </span>n<span class="blank _4"> </span>d<span class="blank _4"> </span>o<span class="blank _4"> </span> <span class="blank _4"> </span>q<span class="blank _4"> </span>u<span class="blank _4"> </span>e<span class="blank _4"> </span> <span class="blank _4"> </span>o</div><div class="t m0 x6 h2 y10f ff2 fs1 fc3 sc0 ls36 ws42">exce<span class="blank _2"> </span>ss<span class="blank _2"> </span>o<span class="blank _2"> </span> d<span class="blank _2"> </span>e<span class="blank _2"> </span> á<span class="blank _2"> </span>c<span class="blank _2"> </span>id<span class="blank _2"> </span>o <span class="blank _2"> </span>fó<span class="blank _2"> </span>li<span class="blank _2"> </span>c<span class="blank _2"> </span>o <span class="blank _2"> </span>na<span class="blank _2"> </span> <span class="blank _2"> </span>gr<span class="blank _2"> </span>av<span class="blank _2"> </span>id<span class="blank _2"> </span>e<span class="blank _2"> </span>z <span class="blank _2"> </span>p<span class="blank _2"> </span>od<span class="blank _2"> </span>e <span class="blank _2"> </span>d<span class="blank _2"> </span>ob<span class="blank _2"> </span>r<span class="blank _2"> </span>ar<span class="blank _2"> </span> <span class="blank _2"> </span>o</div><div class="t m0 x6 h2 y110 ff2 fs1 fc3 sc0 ls2f ws42">risco de autismo na criança \u201c[\u2026] Ex<span class="blank _0"></span>cesso de ácido</div><div class="t m0 x6 h2 y111 ff2 fs1 fc3 sc0 ls30 ws42">fó<span class="blank _2"> </span>li<span class="blank _2"> </span>c<span class="blank _2"> </span>o<span class="blank _2"> </span> n<span class="blank _2"> </span>a<span class="blank _2"> </span> <span class="blank _2"> </span>ge<span class="blank _2"> </span>s<span class="blank _2"> </span>ta<span class="blank _2"> </span>ç<span class="blank _2"> </span>ã<span class="blank _2"> </span>o <span class="blank _2"> </span>p<span class="blank _2"> </span>o<span class="blank _2"> </span>de<span class="blank _2"> </span> <span class="blank _2"> </span>a<span class="blank _2"> </span>um<span class="blank _2"> </span>e<span class="blank _2"> </span>n<span class="blank _2"> </span>ta<span class="blank _2"> </span>r<span class="blank _2"> </span> <span class="blank _2"> </span>em<span class="blank _2"> </span> <span class="blank _2"> </span>a<span class="blank _2"> </span>té<span class="blank _2"> </span> <span class="blank _2"> </span>du<span class="blank _2"> </span>a<span class="blank _2"> </span>s<span class="blank _2"> </span> ve<span class="blank _2"> </span>ze<span class="blank _2"> </span>s</div><div class="t m0 x6 h2 y112 ff2 fs1 fc3 sc0 ls2f ws42">o risco de autismo na criança. A conclusão é de um</div><div class="t m0 x6 h2 y113 ff2 fs1 fc3 sc0 ls1f ws42">estudo r<span class="blank _6"></span>ealizado por pesquisadores da Univ<span class="blank _6"></span>ersidade</div><div class="t m0 x6 h2 y114 ff2 fs1 fc3 sc0 ls35 ws42">Johns Hopkins, nos Estados Unidos, apr<span class="blank _6"></span>esentado</div><div class="t m0 x6 h2 y115 ff2 fs1 fc3 sc0 ls2c ws42">nesta se<span class="blank _6"></span>xta-f<span class="blank _6"></span>eira durante o Enc<span class="blank _0"></span>ontro I<span class="blank _0"></span>nternacional</div><div class="t m0 x6 h2 y116 ff2 fs1 fc3 sc0 ls1f ws42">para P<span class="blank _0"></span>esquisa sobr<span class="blank _0"></span>e A<span class="blank _6"></span>utismo de 2016<span class="blank _6"></span>, em Baltimore.</div><div class="t m0 x6 h2 y117 ff2 fs1 fc3 sc0 ls2f ws39">[\u2026]\u201d<span class="blank _27"></span>.</div><div class="t m0 x6 h2 y118 ff2 fs1 fc3 sc0 ls22 ws42">Sob condições apr<span class="blank _0"></span>opriadas, uma solução aquosa de</div><div class="t m0 x6 h2 y119 ff2 fs1 fc3 sc0 ls20 ws42">ácido f<span class="blank _6"></span>ólico <span class="blank _2"> </span>apr<span class="blank _6"></span>esenta [H<span class="blank _a"> </span><span class="ls2f">] = 4<span class="blank _6"></span>,<span class="blank _0"></span>510<span class="blank _1c"> </span><span class="ls22"> mol/L (sob</span></span></div><div class="t m0 x6 h2 y11a ff2 fs1 fc3 sc0 ls39 ws42">temp<span class="blank _2"> </span>erat<span class="blank _2"> </span>ura <span class="blank _2"> </span>de 2<span class="blank _2"> </span>5 <span class="ff8 ls2b wsa">º<span class="blank _6"></span><span class="ff2 ls34">C).</span></span></div><div class="t m0 x6 h2 y11b ff2 fs1 fc3 sc0 ls42 ws42">Assi<span class="blank _2"> </span>nal<span class="blank _2"> </span>e a<span class="blank _2"> </span> al<span class="blank _2"> </span>ter<span class="blank _2"> </span>na<span class="blank _2"> </span>tiva <span class="blank _2"> </span>cor<span class="blank _2"> </span>reta<span class="blank _2"> </span> qu<span class="blank _2"> </span>e c<span class="blank _2"> </span>ont<span class="blank _2"> </span>ém <span class="blank _2"> </span>o val<span class="blank _2"> </span>or <span class="blank _2"> </span>do</div><div class="t m0 x6 h2 y11c ff2 fs1 fc3 sc0 ls1f ws42">pH dessa solução<span class="blank _6"></span>.</div><div class="t m0 x6 h2 y11d ff4 fs1 fc4 sc0 ls44 ws2c">Dado<span class="blank _2"> </span>s<span class="ff2 fc3 ls2f ws42">: log 2 = 0<span class="blank _10"></span>,<span class="blank _0"></span>30; log 3 = 0<span class="blank _6"></span>,<span class="blank _6"></span>48<span class="blank _6"></span>.</span></div><div class="t m0 x10 h2 y11e ff2 fs1 fc3 sc0 ls22 ws42"> 4<span class="blank _6"></span>,<span class="blank _6"></span>34</div><div class="t m0 x10 h2 y11f ff2 fs1 fc3 sc0 ls22 ws42"> 4<span class="blank _6"></span>,<span class="blank _6"></span>64</div><div class="t m0 x10 h2 y120 ff2 fs1 fc3 sc0 ls22 ws42"> 4<span class="blank _6"></span>,<span class="blank _6"></span>50</div><div class="t m0 x10 h2 y121 ff2 fs1 fc3 sc0 ls22 ws42"> 5<span class="blank _6"></span>,<span class="blank _6"></span>66</div><div class="t m0 x31 hc y122 ff2 fs8 fc3 sc0 ls15">+<span class="lsc">\u20135</span></div><div class="c x3a y123 w5 h10"><div class="t m0 x0 h11 y124 ff10 fsa fc0 sc0 ls16 ws3a"><span class="fc9 sc0">Cop</span><span class="blank _6"></span><span class="fc9 sc0">y</span></div><div class="t m0 x0 h11 y125 ff10 fsa fc0 sc0 ls17 ws3b"><span class="fc9 sc0">Lin</span><span class="fc9 sc0">k</span></div></div><div class="c x3b y123 w5 h10"><div class="t m0 x0 h11 y124 ff10 fsa fc0 sc0 ls17 ws3b"><span class="fc9 sc0">T</span><span class="blank _27"></span><span class="fc9 sc0">witt</span><span class="blank _6"></span><span class="fc9 sc0">er</span><span class="blank _27"></span></div></div><div class="c x12 y123 w5 h10"><div class="t m0 x0 h11 y124 ff10 fsa fc0 sc0 ls18 ws3c"><span class="fc9 sc0">F</span><span class="blank _11"></span><span class="fc9 sc0">ace</span><span class="fc9 sc0">book</span><span class="blank _10"></span></div></div><div class="c xb y123 w5 h10"><div class="t m0 x0 h11 y124 ff10 fsa fc0 sc0 ls19 ws3d"><span class="fc9 sc0">What</span><span class="fc9 sc0">s</span><span class="fc9 sc0">Ap</span><span class="fc9 sc0">p</span></div></div><div class="c x3c y123 w5 h10"><div class="t m0 x0 h11 y124 ff10 fsa fc0 sc0 ls17 ws3b"><span class="fc9 sc0">Lin</span><span class="fc9 sc0">k</span><span class="blank _10"></span><span class="fc9 sc0">ed</span><span class="fc9 sc0">I</span><span class="fc9 sc0">n</span></div></div><div class="c x2e y123 w5 h10"><div class="t m0 x0 h11 y124 ff10 fsa fc0 sc0 ls48"><span class="fc9 sc0">Email</span></div></div><div class="t m0 x3d h2 y126 ff2 fs1 fc6 sc0 ls2b">1</div><div class="t m0 x3e h2 y127 ff2 fs1 fc6 sc0 ls2b">2</div><div class="t m0 x3e h2 y128 ff2 fs1 fc6 sc0 ls2b">3</div><div class="t m0 x3e h2 y129 ff2 fs1 fc6 sc0 ls2b">4</div><div class="t m0 x3e h2 y12a ff2 fs1 fc6 sc0 ls2b">5</div><div class="t m0 x3f h12 y12b ff11 fsb fc2 sc0 ls49 ws42">Do<span class="blank _6"></span>wnload g<span class="blank _2"> </span>r<span class="blank _0"></span>atuito</div><div class="t m0 x40 h13 y12c ff12 fs9 fc7 sc0 ls4a ws42">Curso de r<span class="blank _6"></span>edação + E-book</div><div class="t m0 x3f h12 y12d ff11 fsb fc2 sc0 ls4b ws42">Ve<span class="blank _4"> </span>j<span class="blank _5"> </span>a<span class="blank _5"> </span> <span class="blank _4"> </span>o<span class="blank _5"> </span> <span class="blank _5"> </span>q<span class="blank _4"> </span>u<span class="blank _5"> </span>e<span class="blank _5"> </span> <span class="blank _4"> </span>m<span class="blank _5"> </span>a<span class="blank _5"> </span>i<span class="blank _4"> </span>s<span class="blank _5"> </span> <span class="blank _5"> </span>c<span class="blank _4"> </span>a<span class="blank _5"> </span>i<span class="blank _5"> </span> <span class="blank _4"> </span>n<span class="blank _5"> </span>o<span class="blank _5"> </span> <span class="blank _4"> </span>E<span class="blank _5"> </span>n<span class="blank _5"> </span>e<span class="blank _4"> </span>m</div><div class="t m0 xc h2 y12e ff13 fs1 fc0 sc0 ls2d ws42">Equilíbrio Químico</div><div class="t m0 xc h2 y12f ff13 fs1 fc0 sc0 ls4c ws42">As <span class="blank _2"> </span>L<span class="blank _6"></span>e<span class="blank _2"> </span>is<span class="blank _2"> </span> de<span class="blank _2"> </span> N<span class="blank _2"> </span>ewto<span class="blank _2"> </span>n</div><div class="t m0 xc h2 y130 ff13 fs1 fc0 sc0 ls2d ws42">Ética e Justiça na Filosofia</div><div class="t m0 xc h2 y131 ff13 fs1 fc0 sc0 ls2d ws42">O Espaço Rural Brasileir<span class="blank _6"></span>o</div><div class="t m0 xc h2 y132 ff13 fs1 fc0 sc0 ls1f ws42">A Era V<span class="blank _10"></span>argas</div><div class="t m0 x41 h2 y133 ff1 fs1 fc1 sc0 ls2d ws3e">DISCIPLINAS</div><div class="t m0 x23 h2 y134 ff1 fs1 fc1 sc0 ls4d ws3f">SIMULADOS</div><div class="t m0 x12 h2 y135 ff1 fs1 fc1 sc0 ls2f ws42">PLANO DE ESTUDOS</div><div class="t m0 x42 h2 y136 ff1 fs1 fc1 sc0 ls2f ws42">POLÍTIC<span class="blank _0"></span>A DE PRIV<span class="blank _11"></span>A<span class="blank _0"></span>CID<span class="blank _6"></span>ADE</div><div class="t m0 x43 h2 y137 ff2 fs1 fc1 sc0 ls23 ws40">Rea<span class="blank"> </span>l<span class="blank"> </span>i<span class="blank"> </span>z<span class="blank"> </span>a<span class="blank"> </span>ç<span class="blank"> </span>ã<span class="blank"> </span>o</div><div class="t m0 x23 h2 y138 ff2 fs1 fc1 sc0 ls2b ws42"> <span class="blank _28"> </span> </div><div class="t m0 x15 h1 y139 ff2 fs0 fc1 sc0 ls4e ws42">O <span class="ls4f">Curso Enem Gratuito é um canal independente de difusão de</span></div><div class="t m0 x3f h1 y13a ff2 fs0 fc1 sc0 ls50 ws42">conteúdos de apoio à aprendizagem e de informações sobre</div><div class="t m0 x3d h1 y13b ff2 fs0 fc1 sc0 ls51 ws42">programas e o<span class="blank _0"></span>portunidades de acesso ao Ensino Superior<span class="blank _10"></span>. </div><div class="t m0 x44 h1 y13c ff2 fs0 fc1 sc0 ls52 ws42">É parte da Rede Enem, iniciativa R<span class="blank _6"></span>ede <span class="blank _2"> </span>Enem Serviços de</div><div class="t m0 x45 h1 y13d ff2 fs0 fc1 sc0 ls50 ws42">Internet L<span class="blank _11"></span>TD<span class="blank _6"></span>A <span class="blank _2"> </span>- Consult<span class="blank _0"></span>e nossa Política de Priv<span class="blank _6"></span>acidad<span class="blank _2"> </span>e</div><div class="t m0 x46 h2 y13e ff13 fs1 fc4 sc0 ls53 ws41">Pa<span class="blank"> </span>rc<span class="blank"> </span>e<span class="blank"> </span>i<span class="blank"> </span>ro<span class="blank"> </span>s</div><div class="c x47 y13f w6 h14"><div class="t m0 x48 h15 y140 ff3 fs0 fc2 sc0 ls2b"><span class="fc9 sc0">"</span></div></div><div class="t m0 x49 h16 y141 ff14 fsc fc8 sc0 ls1a ws42"><span class="fc9 sc0">09/09/2022 19</span><span class="ff15 ls1b"><span class="fc9 sc0">:</span></span><span class="ls54"><span class="fc9 sc0">54</span></span></div><div class="t m0 x4a h16 y142 ff14 fsc fc8 sc0 ls1c ws42"><span class="fc9 sc0">P</span><span class="fc9 sc0">á</span><span class="fc9 sc0">gi</span><span class="fc9 sc0">na</span><span class="fc9 sc0"> 1</span><span class="fc9 sc0"> de 1</span><span class="blank _0"></span></div></div><div class="pi" data-data="{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}"></div></div>
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