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714. What is the maximum allowable weight that may be carried on a pallet which has the dimensions of 33.5 x 48.5 inches? Floor load limit - 76 lb/sq ft Pallet weight - 44 lb Tiedown devices - 27 lb A. 857.4 pounds. B. 830.4 pounds. C. 786.5 pounds. 1. Determine the area. 33.5 x 48.5 ÷ 144 = 11.28 square feet. 2. Determine the floor load limit. 11.28 x 76 = 857.51 pounds. 3. Subtract the weight of the pallet and tiedown devices. 857.51 - 71 = 786.51 pounds. 715. What is the maximum allowable weight that may be carried on a pallet which has the dimensions of 36 x 48 inches? Floor load limit: 169 lbs/sq ft Pallet weight: 47 lbs Tiedown devices: 33 lbs A. 1,948.0 pounds. B. 1,995.0 pounds. C. 1,981.0 pounds. Pallet area = (36 x 48)/144 = 12 sq ft Floor load limit = 12 sq ft x 169 lbs/sq ft = 2,028 lbs Allowable weight = 2,028 lbs - 80 lbs = 1,948 lbs 716. (Refer to Figure 44.) What is the new CG if the weight is added to the forward compartment under Loading Conditions WS 3? A. 11.4 percent MAC. B. 14.3 percent MAC. C. 14.5 percent MAC. 1. Calculate original CG in inches aft of datum: CG (inches aft of LEMAC) = (19.8% ÷ 100%) x 141.5" = 28.02" CG (inches aft of Datum) = 549.13" + 28.02" = 577.15" 2. Use the original weight and the CG to calculate the original Moment/1,000. Next use the weight change and station to determine the Moment/1,000 change: Weight Moment/1,000 Original Weight 84,500 48,768.92 Weight Change + 3,000 + 1,056.30 New Weight 87,500 49,825.22 3. Determine the new CG: CG = (49,825.22 ÷ 87,500) x 1,000 = 569.43 4. Convert CG to percent of MAC: CG (inches aft of LEMAC) = 569.43" - 549.13" = 20.3" CG (% of MAC) = (20.3" ÷ 141.5") x 100% = 14.3%