Tutoria Mec flu

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2m NAC Q = Dados H2O 2m = 0,01 P P = H 90) =0,90 120) = 0,80 2m dt = 2" 1m acp comercial Eq. de Bernoulli modificada = 330 + + -ht = P2 + + Zz ht = hd -> hs localizada pg 29 pg zg distribuida HF = + + ht hd = f L D 2g hs = HF = 2g + + f D 2g + K 2g 2g OBS.i f = f Q = A = 2 4 Re = M = 4Q Re = = 4 1 in 1 3600s (2in) Re = » 2000 Q Q(cm3/s) Regime turbulento D² Re ≤ 2100 laminar = 278,48 2100 (he 4000 turbulento diagrama E =0,009 = Retirado do D de Moody f 0,009) = =0,039 E/D.02 01 008 .035 RIVETED 006 STEEL 005 .03 004 CONCRE 003 WOOD STAVE 002 001 0008 Relative Roughness 0006 0005 0004 016 0003 For Complete Turbulence, Rough Pipes 0002 014 0001 012 00008 00006 00005 00004 01 00002 000 00001 008 000008 000006 000005 25 30 40 50 60 80 100 200 300 400 500 600 1000 2000 4000 6000 8000 Pipe Diameter, in millimetres - d Moody Diagram 0.1 0.09 0.08 Transition Region 0.07 0.05 0.04 0.06 0.03 0.05 0.02 0.015 0.04 0.01 Friction Factor 0.03 0.005 Laminar Flow 0.002 64 0.02 Re 0.001 Material (mm) 5x10 0.015 coarse 0.25 2x10 Relative Pipe Roughness new smooth 0.025 Drawn tubing 0.0025 Complete turbulence 10⁻⁴ 0.0025 Iron. cast 0.15 5x10 0.01 Sewers.old 3.0 mortar lined 0.1 rusted 0.5 10⁻⁵ structural or forged 0.025 Water old 1.0 Friction Factor = 2d P 5x10⁻⁶ Smooth Pipe 10⁻⁶ 10³ 10⁴ 10⁵ 10⁶ 10⁷ 10⁸ Reynolds Number, Re = pVdHF = + + L D 2g + K 2g AF = ( It D + f HF = + 2,70) + (30 5) m = 31,08m Pot= = Considerando J Pot = 9,8 = 346,27 0,50 = A F = Kgm = kg m Pot = = W = P.V m3 = kgm2 53 = ≡ 0,46HP Como a bomba tem de ela suficiente para bombear fluido nesse sistema