Chegg Solutions for Microelectronic Circuits (Adel S Sedra, Kenneth C Smith) (Z-Library)_parte_1353

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Step 1 of 2 11.104P The fourth pole is must be kept at lower than the lowest amplifier pole that is Hz Since, pole will become the dominant pole which is near to imaginary axis. Determine the value of The new pole frequency is, Substitute 10⁵ for 10⁶ Hz for in equation. = 10 Hz Therefore, the frequency of dominant pole is 10 Hz . Step 2 of 2 Consider the resistance of 1 MQ in the RC low-pass network. Determine the value of capacitance. Substitute 1 for 100 Hz for in equation. = 15.9 nF Therefore, the required capacitance of capacitor C is 15.9 nF