1 (247)

Prévia do material em texto

Step 2.006E Refer Figure E2.6 in the textbook ideal op-amp, the inverting and non-inverting terminal currents are zero Re-draw the circuit 0A M > 0A Figure Step Form Figure the non-inverting node voltage That is =0V (Since connected ground) Using virtual ground concept the inverting node voltage becomes Therefore the inverting node Step Use Ohm's law to Figure the 4 1x10 Substitute for equation 1-0 1x10 1x10 Therefore the input Step 13 Use current law to at inverting node, determine the feedback current Therefore the feedback Step 13 Apply Kirchhoffs voltage law to Figure determine the output voltage Substitute 0V for and 1mA for the equation Therefore the output voltage -10V Step Use Ohm's law Figure the load Substitute -10V for equation -10 Therefore -10mA Step Using Kirchhoff current law the above circuit the output current(i) Substitute -10mA for and for equation Therefore -11mA Step The voltage (4) Substitute -10V for and IV for in the equation =-10 Therefore the voltage gain (4) -10V/V Step The voltage gain Therefore the voltage decibels 20dB Step The current (4) is Substitute -10mA for and for the equation =-10 Therefore the current gain -10A/A Step The current =20 Therefore the current gain decibels 20dB Step The power gain Substitute -10 V/V for and for the equation P, =100 Therefore the power gain P, Step 13 of 13 The power Since, =20 Therefore the power gain in decibels is 20dB