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Step 2.002E Consider the following open loop op-amp circuit + The output voltage in the open-loop is, (1) The differential-mode input is, The common mode input is, (3) Step (a) Calculate the voltage by substituting 10' for A 0V for and 2V for V3 in equation (1) Therefore, the voltage at the third terminal, V1 is -0.002V Calculate the differential-mode input voltage. =0-(-0.002) =0.002 mV Therefore, the differential-mode input voltage, VM is Step Calculate the common-mode input voltage by substituting -0.002 for V1 and 0 for V2 in equation (3) = =-0.001 =-1mV Therefore, the common mode input voltage, IS -1mV Step (b) Calculate the voltage by substituting 10' for A for and -10V for in equation (1) =5+0.01 =5.01V Therefore, the voltage at the third terminal, V1 is 5.01 V Calculate the differential- mode input voltage. =5-5.01 =-0.01 Therefore, the differential-mode input voltage, VId is Calculate the common-mode input voltage by substituting 5.01 V for V1 and 5V for V2 in equation (3) =5.005 V Therefore, the common-mode input voltage, is 5.005 Step (c) Calculate the voltage V3 by substituting for A 0.998 V for V2 and 1.002 V for V1 in equation (1). Therefore, the voltage at the third terminal, V3 is V Calculate the differential-mode input voltage. =0.998-1.002 =-0.004 Therefore, the differential-mode input voltage, is -4 mV Calculate the common-mode input voltage by substituting 1.002 V for V1 and 0.998 V for V2 in equation (3). =1V Therefore, the common-mode input voltage, is V Step (d) Calculate the voltage by substituting for A V for V3 and -3.6 V for V1 in equation (1) Therefore, the voltage at the third terminal, is -3.6036 V Calculate the mode input voltage. =-3.6036-(-3.6) =-0.0036 =-3.6 mV Therefore, the differential mode input voltage, -3.6mV Calculate the common-mode input voltage by substituting -3.6 V for V1 and -3.6036 V for in equation (3). Therefore, the common-mode input voltage, is