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10 Gases Solutions to Exercises Pco₂ = 0.12497 mol 297 0.08206 mol L K atm = 0.30458 = 0.305 atm = = 0.928 atm 760 Pₜ = Pco₂ + Pair = 0.30458 + 0.92763 = 1.23221 = 1.232 atm (Result has 3 decimal places and 4 sig figs.) 10.70 V mass C₂H₅OC₂H₅ mol C₂H₅OC₂H₅ Pₜ = + ; T = 273.15 + 35.0°C = 308.15 = 308.2 K (a) 5.00 mL 1 mol C₂H₅OC₂H₅ = 0.048125 = 0.0481 mol C₂H₅OC₂H₅ P = nRT V = 0.048125 mol 308.15 0.08206 atm = 0.20282 = 0.203 atm (b) Pₜ = + + PC₂H₅OC₂H₅ = 0.751 atm + 0.208 atm + 0.203 atm = 1.162 atm 10.71 Analyze/Plan. The partial pressure of each component is equal to the mole fraction of that gas times the total pressure of the mixture. Find the mole fraction of each component and then its partial pressure. Solve. = 0.75 mol N₂ + 0.30 mol O₂ + 0.15 mol CO₂ = 1.20 mol = 1.20 0.75 = = = 0.625 2.15 atm = 1.344 = 1.3 atm = 0.30 1.20 = = 0.25; = 0.250 2.15 atm = 0.5375 = 0.54 atm = 1.20 0.15 = 0.125 = 0.13; = 0.125 2.15 atm = 0.2688 = 0.27 atm Check. = 1.344 + 0.5375 + 0.2688 = 2.1503 = 2.15 atm. The sum of the partial pressures agrees with the stated total pressure. 10.72 = 10.25 N₂ = 0.3658 mol; = 1.83 H₂ 2.016g 1 mol = 0.9077 = 0.908 mol = 17.03 1 mol = 0.4668 mol = 0.467 mol nt = 0.3658 + 0.9077 + 0.4668 = 1.7403 = 1.740 mol 1.7403 1.85 atm = 0.389 atm = 0.9077 1.7403 1.85 atm = 0.965 atm; = 0.4668 1.7403 1.85 atm = 0.496 atm 10.73 Analyze/Plan. Mole fraction = pressure fraction. Find the desired mole fraction of O₂ and change to mole percent. Solve. = = 8.38 0.21 atm atm = 0.025; mole % = 0.025 100 = 2.5% 291