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Step of 7 6.030P Refer to Figure P6.30 in the text book. In Figure P6.30, the base terminal and the collector terminal are connected by a short circuit. Thus, the base- emitter voltage is equals to the collector emitter voltage. =0.7 V V Apply voltage law straight down the line of the resistance and the transistor in Figure P6.30. Substitute 0.7 V for mA for and 9V for in the equation. 9-0.7 8.3 V = Thus, the value of resistor, Rc is Step of 7 Determine the value of base current with full scale reading of the meter. Determine the value of collector current with full scale reading of the meter. The emitter current is the summation of the base current and the collector current. Substitute 50 for and mA for in the equation. Step of 7 Determine the value of common-emitter current gain with full scale reading of the meter. Substitute 50 for I, and 950 for in the equation. 950x10 =19 Thus, the value of common-emitter current gain for a full scale meter reading, is 9 Step 7 Determine the value of base current with 1/5th of full scale meter reading. Substitute 50 uA for in the equation. Determine the value of collector current with 1/5th of full scale meter reading Substitute 10 for I, and mA for in the equation. 990 Step Determine the value of common-emitter current gain with 1/5th of full scale meter reading. Substitute 10 for I, and 990 for in the equation. 990x10 =99 Thus, the value of common-emitter current gain for 1/5th of the full scale meter reading, is 99 Step 7 Determine the value of base current with of full scale meter reading. Substitute 50 for in the equation. Determine the value of collector current with 1/10th of full scale meter reading. Substitute 5 for I, and mA for in the equation. 995 Step of Determine the value of common-emitter current gain with 1/10th of full scale meter reading. Substitute 5 for and 995 for in the equation. 995x10 =199 Thus, the value of common-emitter current gain for 1/10th of the full scale meter reading, is 199