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Step of 8.041P Refer to Figure 8. 15 (a) from the text Calculate the value of the voltage Substitute -0.5 V for and -0.25 V for Vor =-0.5-0.25 V Therefore, the value of the voltage IS -0.75 V V Step of Calculate the value of the voltage VG Substitute -0.75 V for and 1.8 V for VDD =1.05 V Therefore, the value of the voltage VG is 1.05 V .05 Step of 7 Calculate the value of the transconductance 8ml Substitute 100 for and 0.25 V for 8ml 0.25 Therefore, the value of the transconductance 8ml is 0.8 mA/V Step of 7 Consider the expression for the voltage gain A, Here, Substitute 0.8 mA/V for 8ml and -40 V/V for A, 40 0.4 m Therefore, the value of the resistance is Step of 7 Consider the expression for the resistance Substitute 100 for for and 5 V/µm for 100 100 L L 10 L=2 µm Therefore, the value of the length L is 2 Step of 7 Consider the expression for the current through the transistor Substitute 400 for for and 5 for 100 W 2 W 2 4(0.0625) W 2 0.25 =8 W Therefore, the value of the ratio 8 Step of Consider the expression for the current through the transistor Substitute 100 for for and 5 V/µm for 100 2 W 2 (0.25) 2 0.0625 W =32 W Therefore, the value of the ratio is 32 L

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