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Semiconductor Physics and Devices: Basic Principles, 4 th edition Chapter 9 By D. A. Neamen Problem Solutions ______________________________________________________________________________________ 60.0230.012.1 e 1419 1085.87.11106.12 1 itD 2/116 164.060.0105 60.001.475.4 1020 1085.8 8 14 itD We then find 111097.4 itD cm 2 eV 1 _______________________________________ 9.14 (a) 224.0 105 108.2 ln0259.0 15 19 n V (b) 666.0224.089.0 nBnbiV V (c) kT e TAJ Bn sT exp2 0259.0 89.0 exp300120 2 81029.1 sTJ A/cm 2 (d) 81029.1 5 ln0259.0ln sT ta J J VV 512.0aV V _______________________________________ 9.15 (a) 63.00 B V 0259.0 63.0 exp300120 2 sTJ 410948.2 A/cm 2 844 10948.210948.210 sTI A (i) sT ta I I VV ln 8 6 10948.2 1010 ln0259.0 151.0 V (ii) 8 6 10948.2 10100 ln0259.0aV 211.0 V (iii) 8 3 10948.2 10 ln0259.0aV 270.0 V (b) 030217.0 300 350 0259.0 kT eV 030217.0 63.0 exp35012010 24 sTI 610296.1 A (i) 1exp t a sT V V II 1 10296.1 1010 ln030217.0 6 6 aV 0654.0 V (ii) 1 10296.1 10100 ln030217.0 6 6 aV 1317.0 V (iii) 6 3 10296.1 10 ln030217.0aV 201.0 V _______________________________________ 9.16 (a) 88.0Bn V (b) 0259.0 88.0 exp30012.1 2 sTJ 1010768.1 A/cm 2 (c) 1010768.1 10 ln0259.0aV 641.0 V (d) 2ln0259.02ln ta VV 0180.0 V _______________________________________ 9.17 Plot _______________________________________ 9.18 From the figure, 68.0Bn V tt Bn ST VV TAJ expexp2* tV exp 0259.0 68.0 exp300120 2 or t ST V J exp10277.4 5