MATLAB ATIVIDADE de álgebra linear FEI

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Atividade: Álgebra linear no Matlab
Nome: RA: Turma: Data: Professores: Aristóteles e Samir
Parte 1:
>> A=[1 2 1; 1 4 7; 3 6 7];
>> B = [1; 1; 0];
>> C = [1 2 1 1; 1 4 7 1; 3 6 7 0]
C =
 1 2 1 1
 1 4 7 1
 3 6 7 0
>> X=rref(C)
X =
 1.0000 0 0 -2.7500
 0 1.0000 0 2.2500
 0 0 1.0000 -0.7500
>>% S={(-2.7500 2.2500 -0.7500)}
>> D=[1 2 1 1; 1 4 7 1; 3 6 7 0];
X=rref(D)
[L,C]=size(X);
n=L;
m=C;
if X(n,m-1)==0 & X(n,m)==0
 disp('o sistema e indeterminado')
else if X(n,m-1)==0 & X(n,m)~=0
 disp('o sistema e impossivel')
 else
 disp(' a solucao e:')
 for j=1:n
 X(j,m)
 end
 end
end
X =
 1.0000 0 0 -2.7500
 0 1.0000 0 2.2500
 0 0 1.0000 -0.7500
 a solucao e:
ans =
 -2.7500
ans =
 2.2500
ans =
 -0.7500
Parte 2:
>> E=[2 7 3 2 1 ; 1 3 2 4 -1 ; 2 7 6 6 2; 8 9 0 4 -3; -1 2 1 1 1];
>> F= [ 9;-4; -4 ; 17 ;-1];
>> G=[2 7 3 2 1 9 ; 1 3 2 4 -1 -4 ; 2 7 6 6 2 -4 ; 8 9 0 4 -3 17 ; -1 2 1 1 1 -1]
G =
 2 7 3 2 1 9
 1 3 2 4 -1 -4
 2 7 6 6 2 -4
 8 9 0 4 -3 17
 -1 2 1 1 1 -1
>> X=rref(C)
X =
 1
>> X=rref(C)
X =
 1
>> Z=rref(G)
Z =
 1 0 0 0 0 1
 0 1 0 0 0 2
 0 0 1 0 0 0
 0 0 0 1 0 -3
 0 0 0 0 1 -1
% s{( 1,2,0,-3,-1)}
>> X=rref(G)
[L,C]=size(X);
n=L;
m=C;
if X(n,m-1)==0 & X(n,m)==0
 disp('o sistema e indeterminado')
else if X(n,m-1)==0 & X(n,m)~=0
 disp('o sistema e impossivel')
 else
 disp(' a solucao e:')
 for j=1:n
 X(j,m)
 end
 end
end
X =
 1 0 0 0 0 1
 0 1 0 0 0 2
 0 0 1 0 0 0
 0 0 0 1 0 -3
 0 0 0 0 1 -1
 a solucao e:
ans =
 1
ans =
 2
ans =
 0
ans =
 -3
ans =
 -1