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Calcule a derivada de [sen(ln(tan(ex+2)))] x 2 . Soluc¸a˜o: y = [sen(ln(tan(ex+2)))] x 2 ln y = ln[sen(ln(tan(ex+2)))] x 2 ln y = x 2 · ln[sen(ln(tan(ex+2)))] derivando em relac¸a˜o a x dos dois lados 1 y dy dx = 1 2 ·ln[sen(ln(tan(ex+2)))]+x 2 · 1 sen(ln(tan(ex+2))) ·cos(ln(tan(ex+2)))· 1 (tan(ex+2)) ·sec2(ex+2)·ex+2 1 y dy dx = 1 2 · ln[sen(ln(tan(ex+2)))] + x 2 · cos(ln(tan(e x+2))) · sec2(ex+2) · ex+2 sen(ln(tan(ex+2))) · (tan(ex+2)) dy dx = y · { 1 2 · ln[sen(ln(tan(ex+2)))] + x 2 · cos(ln(tan(e x+2))) · sec2(ex+2) · ex+2 sen(ln(tan(ex+2))) · (tan(ex+2)) } dy dx = [sen(ln(tan(ex+2)))] x 2 · { 1 2 · ln[sen(ln(tan(ex+2)))] + x 2 · cos(ln(tan(e x+2))) · sec2(ex+2) · ex+2 sen(ln(tan(ex+2))) · (tan(ex+2)) } dy dx = 1 2 [sen(ln(tan(ex+2)))] x 2 · ln[sen(ln(tan(ex+2)))]+ + x 2 · [sen(ln(tan(e x+2)))] x 2 −1 cos(ln(tan(ex+2))) · sec2(ex+2) · ex+2 (tan(ex+2)) 1
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