<div id="pf1" class="pf w0 h0" data-page-no="1"><div class="pc pc1 w0 h0"><img class="bi x0 y0 w0 h0" alt="" src="https://files.passeidireto.com/e0666d76-9627-4100-8331-f224be3cacda/bg1.png"><div class="t m0 x1 h1 y1 ff1 fs0 fc0 sc0 ls3 ws2">ESTEQUIOMETRIA </div><div class="t m0 x2 h2 y2 ff1 fs1 fc0 sc0 ls3 ws2">- Conceito<span class="ff2">: <span class="_0 blank"></span>calcula <span class="_0 blank"></span>as quantidades <span class="_0 blank"></span>das substâncias envolvidas <span class="_0 blank"></span>num<span class="_0 blank"></span>a </span></div><div class="t m0 x2 h3 y3 ff2 fs0 fc0 sc0 ls3 ws2"> reação <span class="_0 blank"></span>química. </div><div class="t m0 x2 h3 y4 ff2 fs0 fc0 sc0 ls3 ws2"> </div><div class="t m0 x2 h1 y5 ff2 fs0 fc0 sc0 ls3 ws2">- <span class="ff1">Fórmula <span class="_0 blank"></span>per<span class="_0 blank"></span>centual ou composição centesimal; <span class="ff2">indica <span class="_0 blank"></span>a </span></span></div><div class="t m0 x2 h4 y6 ff2 fs1 fc0 sc0 ls3 ws2">porcentagem <span class="_0 blank"></span>em<span class="_0 blank"></span> massa de cada <span class="_0 blank"></span>elemento <span class="_0 blank"></span>que constitui <span class="_0 blank"></span>a substância </div><div class="t m0 x2 h3 y7 ff2 fs0 fc0 sc0 ls3 ws2"> </div><div class="t m0 x2 h3 y8 ff2 fs0 fc0 sc0 ls4 ws0">Ex<span class="fs2 ls0 v1">1</span><span class="ls3 ws2">: verifica-se <span class="_0 blank"></span>experimentalm<span class="_0 blank"></span>ente <span class="_0 blank"></span>que na queima <span class="_0 blank"></span>de 2,4g de </span></div><div class="t m0 x2 h3 y9 ff2 fs0 fc0 sc0 ls3 ws2"> m<span class="_0 blank"></span>agnésio, formam<span class="_0 blank"></span>-se <span class="_1 blank"></span>4g de um certo com<span class="_0 blank"></span>posto de magnésio. </div><div class="t m0 x2 h4 ya ff2 fs1 fc0 sc0 ls3 ws2">Qual a <span class="_0 blank"></span>fórmula percentual <span class="_0 blank"></span>desse com<span class="_0 blank"></span>posto? </div><div class="t m0 x2 h3 yb ff2 fs0 fc0 sc0 ls3 ws2"> Mg + 1/2 O<span class="fs2 ls1 v1">2</span> <span class="ff3 ws1">\u2192</span> MgO </div><div class="t m0 x2 h3 yc ff2 fs0 fc0 sc0 ls3 ws2"> 40u<span class="ls2">---</span>100% </div><div class="t m0 x2 h3 yd ff2 fs0 fc0 sc0 ls3 ws2"> 24u<span class="ls2">----</span>Y </div><div class="t m0 x2 h3 ye ff2 fs0 fc0 sc0 ls3 ws2"> <span class="_2 blank"></span>Y=60% </div><div class="t m0 x2 h3 yf ff2 fs0 fc0 sc0 ls3 ws2">Mg 60% e O 40% Mg 60% O 40% </div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div> <div id="pf2" class="pf w0 h0" data-page-no="2"><div class="pc pc2 w0 h0"><img class="bi x0 y0 w0 h0" alt="" src="https://files.passeidireto.com/e0666d76-9627-4100-8331-f224be3cacda/bg2.png"><div class="t m0 x3 h3 y10 ff2 fs0 fc0 sc0 ls3 ws1">.Ex<span class="fs2 ls1 v1">2</span><span class="ws2">: Qual a com<span class="_0 blank"></span>posição centesim<span class="_0 blank"></span>al do CaS? (Ca= 40 S= 32)<span class="ff4 ws3">\ue003<span class="_3 blank"></span><span class="ff2 ws2"> </span></span></span></div><div class="t m0 x3 h3 y11 ff2 fs0 fc0 sc0 ls3 ws2"> Ca S </div><div class="t m0 x3 h1 y12 ff2 fs0 fc0 sc0 ls5 ws2"> <span class="ff1 ls3">Cálcio </span></div><div class="t m0 x3 h3 y13 ff2 fs0 fc0 sc0 ls3 ws2"> <span class="_4 blank"> </span>Em 72g de CaS <span class="ff5 ws4">\uf0ae</span> 100%g </div><div class="t m0 x3 h4 y14 ff2 fs1 fc0 sc0 ls3 ws2"> Em<span class="_0 blank"></span> <span class="ls6 ws5">40</span>g de CaS <span class="ff5 ws6">\uf0ae</span> x de <span class="_0 blank"></span>Ca <span class="_0 blank"></span> </div><div class="t m0 x4 h3 y15 ff2 fs0 fc0 sc0 ls3 ws2">x = 55,55g </div><div class="t m0 x3 h3 y16 ff2 fs0 fc0 sc0 ls3 ws2"> </div><div class="t m0 x3 h1 y17 ff1 fs0 fc0 sc0 ls3 ws2">Enxofre </div><div class="t m0 x3 h3 y18 ff2 fs0 fc0 sc0 ls3 ws2">Em 72 g de CaS <span class="ff3 ws1">\u2013</span> 100 g de S </div><div class="t m0 x3 h4 y19 ff2 fs1 fc0 sc0 ls3 ws2">Em <span class="_0 blank"></span><span class="ls6">32 <span class="ls3">g de CaS -<span class="ls7"> </span>y g de S </span></span></div><div class="t m0 x3 h3 y1a ff2 fs0 fc0 sc0 ls3 ws2">y = = 44,44 g </div><div class="t m0 x3 h3 y1b ff2 fs0 fc0 sc0 ls3 ws2">No composto CaS tem<span class="_0 blank"></span>os, 55,55% de Ca e 44,44% de S </div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div> <div id="pf3" class="pf w0 h0" data-page-no="3"><div class="pc pc3 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x0 y0 w0 h0" alt="" src="https://files.passeidireto.com/e0666d76-9627-4100-8331-f224be3cacda/bg3.png"><div class="t m0 x5 h5 y1c ff3 fs3 fc0 sc0 ls8">\u2022<span class="ff2 ls3 ws2">Indique <span class="_0 blank"></span>a composição <span class="_0 blank"></span>centesimal <span class="_0 blank"></span>da água </span></div><div class="t m0 x2 h6 y1d ff2 fs4 fc0 sc0 ls3 ws2">oxigenada H<span class="fs5 ws7 v2">2</span><span class="ls9">O</span><span class="fs5 ws7 v2">2</span>? ( H= <span class="_0 blank"></span>1, O=<span class="ls1 ws8">16<span class="_0 blank"></span><span class="ls3 ws9">)<span class="ff4 wsa">\ue003<span class="_5 blank"></span><span class="ff2 ws2"> </span></span></span></span></div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div> <div id="pf4" class="pf w0 h0" data-page-no="4"><div class="pc pc4 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x0 y0 w0 h0" alt="" src="https://files.passeidireto.com/e0666d76-9627-4100-8331-f224be3cacda/bg4.png"><div class="t m0 x6 h6 y1e ff3 fs4 fc0 sc0 lsa">\u2022<span class="ff2 ls3 ws2">H2O2= <span class="_0 blank"></span>2+ 32= <span class="_0 blank"></span>34 g/mol </span></div><div class="t m0 x6 h5 y1f ff3 fs3 fc0 sc0 ls8">\u2022<span class="ff2 ls3 ws2">Cálculo <span class="_0 blank"></span>da porcentagem <span class="_0 blank"></span>de H </span></div><div class="t m0 x6 h6 y20 ff3 fs4 fc0 sc0 lsa">\u2022<span class="ff2 ls3 ws2">34 g ________100% </span></div><div class="t m0 x6 h6 y21 ff3 fs4 fc0 sc0 lsa">\u2022<span class="ff2 ls3 ws2">2g _______ <span class="_0 blank"></span> X X= <span class="_0 blank"></span>100.2/34= 5,88% </span></div><div class="t m0 x6 h5 y22 ff3 fs3 fc0 sc0 ls8">\u2022<span class="ff2 ls3 ws2">Cálculo <span class="_0 blank"></span>da porcentagem <span class="_0 blank"></span>de O </span></div><div class="t m0 x6 h6 y23 ff3 fs4 fc0 sc0 lsa">\u2022<span class="ff2 ls3 ws2">34g _________100% </span></div><div class="t m0 x6 h6 y24 ff3 fs4 fc0 sc0 lsa">\u2022<span class="ff2 ls3 ws2">32g _________ <span class="_0 blank"></span> X X= <span class="_0 blank"></span>94,12%<span class="_1 blank"></span> </span></div><div class="t m0 x6 h5 y25 ff2 fs3 fc0 sc0 ls3 ws2"> </div><div class="t m0 x6 h6 y26 ff2 fs4 fc0 sc0 ls3 ws2"> </div><div class="t m0 x6 h6 y27 ff2 fs4 fc0 sc0 ls3 ws2"> </div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div> <div id="pf5" class="pf w0 h0" data-page-no="5"><div class="pc pc5 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x0 y0 w0 h0" alt="" src="https://files.passeidireto.com/e0666d76-9627-4100-8331-f224be3cacda/bg5.png"><div class="t m0 x6 h1 y28 ff2 fs0 fc0 sc0 ls2">-<span class="ff1 ls3 ws2">Fórmula <span class="_0 blank"></span>mínima<span class="ff2">- indica a m<span class="_0 blank"></span>enor proporção, em núm<span class="_0 blank"></span>eros </span></span></div><div class="t m0 x6 h3 y29 ff2 fs0 fc0 sc0 ls3 ws2">inteiros </div><div class="t m0 x6 h3 y2a ff2 fs0 fc0 sc0 ls3 ws2">de m<span class="_0 blank"></span>ol, dos átomos que constituem <span class="_0 blank"></span>uma substância.<span class="_1 blank"> </span> </div><div class="t m0 x6 h3 y2b ff2 fs0 fc0 sc0 ls3 ws2">Ex: <span class="_2 blank"></span>V<span class="_6 blank"></span>erifica-se experimentalmente <span class="_7 blank"></span>que uma substância <span class="_8 blank"></span>Y<span class="_2 blank"></span> contém<span class="_1 blank"></span> </div><div class="t m0 x6 h3 y2c ff2 fs0 fc0 sc0 ls3 ws2">30,1 % de C, 3,13% de H e 66,7% de <span class="_7 blank"></span>Cl. Qual a sua fórmula <span class="_1 blank"></span> </div><div class="t m0 x6 h3 y2d ff2 fs0 fc0 sc0 ls3 ws2">mínim<span class="_7 blank"></span>a?<span class="_1 blank"> </span> </div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div> <div id="pf6" class="pf w0 h0" data-page-no="6"><div class="pc pc6 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x0 y0 w0 h0" alt="" src="https://files.passeidireto.com/e0666d76-9627-4100-8331-f224be3cacda/bg6.png"><div class="t m0 x7 h3 y2e ff3 fs0 fc0 sc0 lsb">\u2022<span class="ff2 ls3 ws2">30,1 % de C, 3,13% de H e 66,7% de <span class="_7 blank"></span>Cl<span class="_1 blank"> </span> </span></div><div class="t m0 x7 h3 y2f ff3 fs0 fc0 sc0 lsb">\u2022<span class="ff2 ls3 ws2">1o) Supondo 100g da substância: <span class="_7 blank"></span>C = 30,1g H=3,13g Cl=66,7g<span class="_1 blank"></span> </span></div><div class="t m0 x7 h4 y30 ff2 fs1 fc0 sc0 ls3 ws2"> </div><div class="t m0 x7 h3 y31 ff3 fs0 fc0 sc0 lsb">\u2022<span class="ff2 ls3 ws2">2o) Quantidades: <span class="_0 blank"></span>C Nc= 30,1 / 12 = 2,51 m<span class="_0 blank"></span>ol </span></div><div class="t m0 x7 h3 y32 ff3 fs0 fc0 sc0 lsb">\u2022<span class="ff2 ls3 ws2"> H NH= 3,13 / 1 = 3,13 m<span class="_0 blank"></span>ol </span></div><div class="t m0 x7 h3 y33 ff3 fs0 fc0 sc0 lsb">\u2022<span class="ff2 ls3 ws2"> Cl NCl = <span class="_0 blank"></span>66,7 / 35,5 = 1,88 mol </span></div><div class="t m0 x7 h4 y34 ff3 fs1 fc0 sc0 lsc">\u2022<span class="ff2 ls3 ws2">3o) Dividir <span class="_7 blank"></span>todos pelo menor: 2,51 / 1,88 = <span class="_7 blank"></span>1,33 </span></div><div class="t m0 x7 h3 y35 ff3 fs0 fc0 sc0 lsb">\u2022<span class="ff2 ls3 ws2"> 3,13 / 1,88 = 1,66 </span></div><div class="t m0 x7 h3 y36 ff3 fs0 fc0 sc0 lsb">\u2022<span class="ff2 ls3 ws2"> 1,88 / 1,88 = 1 </span></div><div class="t m0 x7 h1 y37 ff3 fs0 fc0 sc0 lsb">\u2022<span class="ff2 ls3 ws2">4o) Transformação <span class="_7 blank"></span>em números inteiros: <span class="ff1">x 3 </span></span></div><div class="t m0 x7 h4 y38 ff3 fs1 fc0 sc0 lsc">\u2022<span class="ff2 ls3 ws2">1,33 x 3 = <span class="_7 blank"></span>4 <span class="_1 blank"></span> 1,66 x 3 = 5 1 x <span class="_0 blank"></span>3 = 3 </span></div><div class="t m0 x7 h1 y39 ff3 fs0 fc0 sc0 lsb">\u2022<span class="ff1 ls3 ws2"> Fórmula mínima: <span class="_0 blank"></span>C4H5Cl3 </span></div><div class="t m0 x7 h1 y3a ff1 fs0 fc0 sc0 ls3 ws2"> </div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div> <div id="pf7" class="pf w0 h0" data-page-no="7"><div class="pc pc7 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x0 y0 w0 h0" alt="" src="https://files.passeidireto.com/e0666d76-9627-4100-8331-f224be3cacda/bg7.png"><div class="t m0 x8 h7 y3b ff2 fs6 fc0 sc0 ls3 ws2">CÁLCUL<span class="_7 blank"></span>O <span class="_1 blank"> </span>DA <span class="_1 blank"></span>FÓRMULA MÍNIMA<span class="_1 blank"></span><span class="ff1"> </span></div><div class="t m0 x9 h8 y3c ff1 fs7 fc0 sc0 ls3 ws2"> </div><div class="t m0 x6 h9 y3d ff2 fs2 fc0 sc0 ls3 ws2">Seja: C=75% H=2<span class="_1 blank"> </span>5%. Qual a fórmula <span class="_1 blank"> </span>mínima? <span class="_9 blank"> </span> </div><div class="t m0 x6 ha y3e ff1 fs2 fc0 sc0 ls3 ws2"> </div><div class="t m0 x6 ha y3f ff1 fs2 fc0 sc0 ls3 ws2">1º PASSO<span class="ff2">: Transformar <span class="_1 blank"> </span>as p<span class="_1 blank"> </span>orcentagens <span class="_1 blank"> </span>em massa. <span class="_9 blank"> </span> </span></div><div class="t m0 x6 hb y40 ff2 fs8 fc0 sc0 ls3 ws2">C = 75% em<span class="_7 blank"></span> <span class="_1 blank"> </span>massa <span class="_1 blank"> </span>d<span class="_1 blank"> </span>e Carbono = 75 g de Carbono.<span class="_1 blank"> </span> </div><div class="t m0 x6 h9 y41 ff2 fs2 fc0 sc0 ls3 ws2">H = 25% em<span class="_0 blank"></span> <span class="_1 blank"> </span>massa <span class="_1 blank"> </span>de hidrog<span class="_1 blank"> </span>ênio = 25<span class="_1 blank"> </span> g de hidrogênio<span class="_1 blank"> </span>. <span class="_1 blank"> </span> </div><div class="t m0 x6 ha y42 ff1 fs2 fc0 sc0 ls3 ws2"> </div><div class="t m0 x6 ha y43 ff1 fs2 fc0 sc0 ls3 ws2">2º PASSO<span class="ff2">: Determinar <span class="_1 blank"> </span>o número <span class="_1 blank"> </span>de mols. <span class="_9 blank"> </span> </span></div><div class="t m0 x6 h9 y44 ff2 fs2 fc0 sc0 lsd ws2"> <span class="ls3 v3"> <span class="_a blank"> </span> <span class="_b blank"> </span>n = </span></div><div class="t m0 x6 h9 y45 ff2 fs2 fc0 sc0 ls3 ws2"> </div><div class="t m0 x6 hb y46 ff2 fs8 fc0 sc0 ls3 ws2">C = <span class="_0 blank"></span> m<span class="_0 blank"></span>ols<span class="_1 blank"> </span> </div><div class="t m0 x6 h9 y47 ff2 fs2 fc0 sc0 ls3 ws2"> </div><div class="t m0 x6 h9 y48 ff2 fs2 fc0 sc0 ls3 ws2">H = m<span class="_7 blank"></span>ols<span class="_1 blank"> </span> </div><div class="t m0 x6 h9 y49 ff2 fs2 fc0 sc0 ls3 ws2"> </div><div class="t m0 x6 ha y4a ff1 fs2 fc0 sc0 ls3 ws2">3º PASSO<span class="ff2">: Após determinar <span class="_1 blank"> </span>a <span class="_1 blank"> </span>proporção <span class="_1 blank"> </span>entre o<span class="_1 blank"> </span> número de <span class="_1 blank"> </span>m<span class="_7 blank"></span>o<span class="_1 blank"> </span>ls <span class="_1 blank"> </span>de <span class="_1 blank"> </span>átom<span class="_0 blank"></span>os, <span class="_c blank"> </span>deve<span class="_c blank"> </span>-se </span></div><div class="t m0 xa h9 y4b ff2 fs2 fc0 sc0 ls3 ws2">transformá-la <span class="_c blank"> </span>na menor <span class="_1 blank"> </span>proporção <span class="_1 blank"> </span>possível de <span class="_1 blank"> </span>números <span class="_1 blank"> </span>inteiros <span class="_1 blank"> </span>e isso po<span class="_1 blank"> </span>de ser <span class="_1 blank"> </span>feito </div><div class="t m0 xa h9 y4c ff2 fs2 fc0 sc0 ls3 ws2">dividindo<span class="_1 blank"> </span>-se os valores <span class="_1 blank"> </span>em <span class="_1 blank"> </span>números <span class="_1 blank"> </span>de mols <span class="_1 blank"> </span>pelo menor <span class="_1 blank"> </span>deles. <span class="_1 blank"> </span> <span class="_1 blank"> </span> </div><div class="t m0 x6 hb y4d ff2 fs8 fc0 sc0 ls3 ws2">C = m<span class="_7 blank"></span>ols <span class="_1 blank"> </span>= 1 <span class="_1 blank"> </span> </div><div class="t m0 x6 h9 y4e ff2 fs2 fc0 sc0 ls3 ws2"> </div><div class="t m0 x6 h9 y4f ff2 fs2 fc0 sc0 ls3 ws2">H = m<span class="_7 blank"></span>ols <span class="_c blank"> </span>= 4 <span class="_1 blank"> </span> </div><div class="t m0 x6 ha y50 ff1 fs2 fc0 sc0 ls3 ws2"> </div><div class="t m0 x6 ha y51 ff1 fs2 fc0 sc0 ls3 ws2">CH4 <span class="ff5 sc1 lse">\uf0ae</span><span class="ff2"> Essa é a menor <span class="_1 blank"> </span>proporção d<span class="_1 blank"> </span>e números in<span class="_1 blank"> </span>teiros, <span class="_1 blank"> </span>entre <span class="_1 blank"> </span>o número <span class="_1 blank"> </span>de mols <span class="_1 blank"> </span>de átomos <span class="_1 blank"> </span>de </span></div><div class="t m0 xa h9 y52 ff2 fs2 fc0 sc0 ls3 ws2">cada com<span class="_0 blank"></span>ponente. <span class="_c blank"> </span> </div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div> <div id="pf8" class="pf w0 h0" data-page-no="8"><div class="pc pc8 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x0 y0 w0 h0" alt="" src="https://files.passeidireto.com/e0666d76-9627-4100-8331-f224be3cacda/bg8.png"><div class="t m0 xb h6 y53 ff2 fs4 fc0 sc0 ls3 ws2">Exercícios </div><div class="t m0 xb h6 y54 ff2 fs4 fc0 sc0 ls3 ws2">1-Uma <span class="_0 blank"></span>amostra contém <span class="ls1">40</span>% <span class="_0 blank"></span>em massa de S e </div><div class="t m0 xc h6 y55 ff2 fs4 fc0 sc0 ls1 ws8">60<span class="ls3 ws2">% de Oxi<span class="_0 blank"></span>gênio.( S=<span class="lsf wsb">32</span>; O=<span class="lsf wsb">16</span><span class="ws9">)<span class="_7 blank"></span><span class="ff4 wsa">\ue003<span class="_d blank"></span><span class="ff2 ws2"> </span></span></span></span></div><div class="t m0 xb h5 y56 ff2 fs3 fc0 sc0 ls3 ws2">Determine <span class="_7 blank"></span>a fórmula mínima? </div><div class="t m0 xb h6 y57 ff2 fs4 fc0 sc0 ls3 ws2"> </div><div class="t m0 xb h6 y58 ff2 fs4 fc0 sc0 ls3 ws2">2-Numa amostra <span class="_7 blank"></span>de<span class="_1 blank"></span> um dado composto <span class="_7 blank"></span>fora<span class="_1 blank"></span>m </div><div class="t m0 xc h6 y59 ff2 fs4 fc0 sc0 ls3 ws2">encontra<span class="_1 blank"></span>dos <span class="_7 blank"></span><span class="ls1">8 <span class="ls3">g de Ca, 6,</span>2 <span class="ls3">g de P e <span class="_0 blank"></span><span class="ls1">11<span class="ls3">,2g de </span></span></span></span></div><div class="t m0 xc h6 y5a ff2 fs4 fc0 sc0 ls3 ws2">O. Determine <span class="_7 blank"></span>a fórmu<span class="_1 blank"></span>la mínima.( <span class="_7 blank"></span>Ca=<span class="_1 blank"></span><span class="ls1">40<span class="ls10">; </span></span></div><div class="t m0 xc h6 y5b ff2 fs4 fc0 sc0 ls11 wsc">P=<span class="ls1">31<span class="ls3 ws2">; O=<span class="_0 blank"></span><span class="ls1 ws8">16<span class="ls3 ws9">)<span class="_7 blank"></span><span class="ff4 wsa">\ue003<span class="_d blank"></span><span class="ff2 ws2"> </span></span></span></span></span></span></div><div class="t m0 xb h5 y5c ff2 fs3 fc0 sc0 ls3 ws2"> </div><div class="t m0 xb h6 y5d ff2 fs4 fc0 sc0 ls3 ws2"> </div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div> <div id="pf9" class="pf w0 h0" data-page-no="9"><div class="pc pc9 w0 h0"><img fetchpriority="low" loading="lazy" class="bi x0 y0 w0 h0" alt="" src="https://files.passeidireto.com/e0666d76-9627-4100-8331-f224be3cacda/bg9.png"><div class="t m0 xd h6 y5e ff3 fs4 fc0 sc0 lsa">\u2022<span class="ff2 ls3 ws2">Resolução<span class="_1 blank"></span> </span></div><div class="t m0 xd h6 y5f ff3 fs4 fc0 sc0 lsa">\u2022<span class="ff2 ls3 ws2">1- 100g <span class="_0 blank"></span>de amostra{40 g de <span class="_0 blank"></span>S </span></div><div class="t m0 xd h6 y60 ff2 fs4 fc0 sc0 ls3 ws2"> <span class="_0 blank"></span> {60 g de O </div><div class="t m0 xd h6 y61 ff2 fs4 fc0 sc0 ls3 ws2">S= 40/32 <span class="_7 blank"></span>=1<span class="_1 blank"></span>,25mols </div><div class="t m0 xd h6 y62 ff2 fs4 fc0 sc0 ls3 ws2">O=60/16 <span class="_7 blank"></span>= 3,75<span class="_1 blank"></span> </div><div class="t m0 xd h5 y63 ff2 fs3 fc0 sc0 ls2">n<span class="ff6 ls3 wsd">°</span><span class="ls3 ws2"> de mols <span class="_7 blank"></span>de S= 1,25/1,25= <span class="_7 blank"></span>1 </span></div><div class="t m0 xd h6 y64 ff2 fs4 fc0 sc0 ls1">n<span class="ff6 ls12">°</span><span class="ls3 ws2"> de mols <span class="_7 blank"></span>de<span class="_1 blank"></span> O= 3,75/1,25= <span class="_7 blank"></span>3 </span></div><div class="t m0 xd h6 y65 ff2 fs4 fc0 sc0 ls3 ws2">F Mínima=SO<span class="fs5 v2">3 </span></div><div class="t m0 xd hc y66 ff2 fs9 fc0 sc0 ls3 ws2"> </div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div> <div id="pfa" class="pf w0 h0" data-page-no="a"><div class="pc pca w0 h0"><img fetchpriority="low" loading="lazy" class="bi x0 y0 w0 h0" alt="" src="https://files.passeidireto.com/e0666d76-9627-4100-8331-f224be3cacda/bga.png"><div class="t m0 x5 h5 y67 ff2 fs3 fc0 sc0 ls3 ws2">2- Ca= <span class="_7 blank"></span>8/40<span class="_1 blank"></span>= 0,2/0,2= <span class="_7 blank"></span>1x 2 </div><div class="t m0 x5 h6 y68 ff2 fs4 fc0 sc0 ls3 ws2"> P= 6,2/31= <span class="_7 blank"></span>0,2/0,2<span class="_1 blank"></span>= <span class="_7 blank"></span>1x2= 2 </div><div class="t m0 x5 h6 y69 ff2 fs4 fc0 sc0 ls3 ws2"> 11,2/16= <span class="_7 blank"></span> 0,7=0,2= <span class="_7 blank"></span>3,5<span class="_1 blank"></span>x2 = 7 </div><div class="t m0 x5 h5 y6a ff2 fs3 fc0 sc0 ls14 wse">Ca<span class="fs9 ls3 wsf v2">2</span><span class="ls3 ws10">P<span class="fs9 wsf v2">2</span><span class="ls13">O</span><span class="fs9 ws2 v2">7 </span></span></div><div class="t m0 x5 h6 y6b ff2 fs4 fc0 sc0 ls3 ws2"> </div><div class="t m0 x5 h6 y6c ff2 fs4 fc0 sc0 ls3 ws2"> </div></div><div class="pi" data-data='{"ctm":[1.000000,0.000000,0.000000,1.000000,0.000000,0.000000]}'></div></div>
Compartilhar