@import url(https://fonts.googleapis.com/css?family=Source+Sans+Pro:300,400,600,700); Questão 53- Sabe-se que os números complexos \ufeffZ1=[2m(3+m)]+(3n+5)iZ_1=[2m(3+m)]+(3n+5)iZ1\u200b=[2m(3+m)]+(3n+5)i\ufeff e \ufeffZ2=(2m2+12)+[4(n+1)]iZ_2=(2m^2+12)+[4(n+1)]iZ2\u200b=(2m2+12)+[4(n+1)]i\ufeff são iguais. Então, os valores de m e n são, respectivamente a) 3 e 1 b) 2 e 1 c) 2 e -1 d) 3 e -1 RESOLUÇÃOFala galera, para resolvermos essa questão vou começar fazendo a distributiva \ufeffZ1=[2m(3+m)]+(3n+5)iZ_1=[2m(3+m)]+(3n+5)iZ1\u200b=[2m(3+m)]+(3n+5)i\ufeff \ufeff\u27f6\longrightarrow\u27f6\ufeff \ufeffZ1=6m+2m2+3ni+5iZ_1=6m+2m^2+3ni+5iZ1\u200b=6m+2m2+3ni+5i\ufeff \ufeffZ2=2m2+12+4ni++4iZ_2=2m^2+12+4ni+ +4iZ2\u200b=2m2+12+4ni++4i\ufeff Agora, vamos igualar esses polinômios \ufeff2m2=2m22m^2=2m^22m2=2m2\ufeff \ufeff3ni+5i=4ni+4i3ni+5i=4ni+4i3ni+5i=4ni+4i\ufeff \ufeff\u27f6\longrightarrow\u27f6\ufeff \ufeffi=nii=nii=ni\ufeff \ufeff\u27f6\longrightarrow\u27f6\ufeff \ufeffn=1n=1n=1\ufeff \ufeff6m=126m=126m=12\ufeff \ufeff\u27f6\longrightarrow\u27f6\ufeff \ufeffm=2m=2m=2\ufeff Logo, m=2 e n=1.Gabarito, letra: BQualquer duvida, meu instagram @carol.1111
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