atividade calculo omputacional 3

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questões 03 e 04
	 QUESTÃO 3 ETAPA 02 METODO DA BISEEÇÃO Função F(X) = X²-10 sem a função SE
	Itera	A	B	xi	f(a)	f(b)	f(xi)
	0	3	4	3.50000	-1	6	2.25
	1	3.00000	3.50000	3.25000	-1	2.25	0.5625
	2	3	3.25	3.12500	-1	0.5625	-0.234375	-0.03125
	3	3.125	3.25	3.18750	-0.234375	0.5625	0.16015625
	4	3.125	3.1875	3.15625	-0.234375	0.16015625	-0.0380859375
	QUESTÃO 04	Função F(x) = X²-10 com a função SE
	Itera	A	B	xi	f(a)	f(b)	f(xi)
	0	3.000000000	4.000000000	3.500000000	-1.000000000	6.000000000	2.250000000
	1	3.000000000	3.500000000	3.250000000	-1.000000000	2.250000000	0.562500000
	2	3.000000000	3.250000000	3.125000000	-1.000000000	0.562500000	-0.234375000
	3	3.125000000	3.250000000	3.187500000	-0.234375000	0.562500000	0.160156250
	4	3.125000000	3.187500000	3.156250000	-0.234375000	0.160156250	-0.038085938
	5	3.156250000	3.187500000	3.171875000	-0.038085938	0.160156250	0.060791016
	6	3.156250000	3.171875000	3.164062500	-0.038085938	0.060791016	0.011291504
	7	3.156250000	3.164062500	3.160156250	-0.038085938	0.011291504	-0.013412476
	8	3.160156250	3.164062500	3.162109375	-0.013412476	0.011291504	-0.001064301
	9	3.162109375	3.164062500	3.163085938	-0.001064301	0.011291504	0.005112648
	10	3.162109375	3.163085938	3.162597656	-0.001064301	0.005112648	0.002023935
	11	3.162109375	3.162597656	3.162353516	-0.001064301	0.002023935	0.000479758
	12	3.162109375	3.162353516	3.162231445	-0.001064301	0.000479758	-0.000292286
	13	3.162231445	3.162353516	3.162292480	-0.000292286	0.000479758	0.000093732
	14	3.162231445	3.162292480	3.162261963	-0.000292286	0.000093732	-0.000099278
	15	3.162261963	3.162292480	3.162277222	-0.000099278	0.000093732	-0.000002773
	16	3.162277222	3.162292480	3.162284851	-0.000002773	0.000093732	0.000045479
	17	3.162277222	3.162284851	3.162281036	-0.000002773	0.000045479	0.000021353
	18	3.162277222	3.162281036	3.162279129	-0.000002773	0.000021353	0.000009290
	19	3.162277222	3.162279129	3.162278175	-0.000002773	0.000009290	0.000003258
	20	3.162277222	3.162278175	3.162277699	-0.000002773	0.000003258	0.000000243
	21	3.162277222	3.162277699	3.162277460	-0.000002773	0.000000243	-0.000001265	0.000000006
	22	3.162277460	3.162277699	3.162277579	-0.000001265	0.000000243	-0.000000511
	23	3.162277579	3.162277699	3.162277639	-0.000000511	0.000000243	-0.000000134
	24	3.162277639	3.162277699	3.162277669	-0.000000134	0.000000243	0.000000054
	25	3.162277639	3.162277669	3.162277654	-0.000000134	0.000000054	-0.000000040
	26	3.162277654	3.162277669	3.162277661	-0.000000040	0.000000054	0.000000007
	27	3.162277654	3.162277661	3.162277658	-0.000000040	0.000000007	-0.000000017
	28	3.162277658	3.162277661	3.162277659	-0.000000017	0.000000007	-0.000000005
	29	3.162277659	3.162277661	3.162277660	-0.000000005	0.000000007	0.000000001
questão 06
	 QUESTÃO 06 METODO DE NEWTON FUNÇÃO = 2X-SEn(X)+4				INETERVALO (-2;-3)
	Itera	xi	f(xi)	f'(X)
	0	-2.00000	0.9092974268	2.41615
	1	-2.3763419562	-0.0599660868	2.72121	E<=0,1
	2	-2.3543053934	-0.0001694748	2.70577	E<=0,0001
	3	-2.3542427587	-0.00000000139	2.70573	E<= 0,000000001
	4
	METODO DE BOLSANO DESCOBRIR PRIMEIRO CHUTE
	2	7.0907025732
	3	9.8588799919
	4	12.7568024953
	5	14.9589242747
	-2	0.9092974268
	-3	-1.8588799919
	-4	-4.7568024953
	-5	-6.9589242747
questão 09
	 QUESTÃO 09 METODO DA ITERAÇÃO: FUNÇÃO= X³-COS(X)				Erro
	Itera	X	interação = x=Raiz³cos(x)	f(x)= X³-COS(X)
	x0	0.5		-0.752582561890373
	1	0.9574056696		0.301939254681247
	2	0.8318617459		-0.097857443386883
	3	0.8765553835		0.033698491775533
	4	0.8616851126		-0.011357233557980
	5	0.8667538751		0.003855239662898	0.0152124732
	6	0.8650399272		-0.001305474054270
	7	0.8656210701		0.000442429676979
	8	0.8654242062		-0.000149898914837
	9	0.8654909154		0.000050791843619
	10	0.8654683128		-0.000017209786682
	11	0.8654759713		0.000005831250972
	12	0.8654733764		-0.000001975815440
	13	0.8654742556		0.000000669470678
	14	0.8654739577		-0.000000226838393
	15	0.8654740586		0.000000076860220	0.000000303698613
	16	0.8654740244		-0.000000026042739
	17	0.865474036		0.000000008824126
	18	0.8654740321		-0.000000002989900	0.00000001181
	19	0.8654740334		0.000000001013075
	20	0.865474033		-0.000000000343263
	21	0.8654740331		0.000000000116309
	22	0.8654740331		-0.000000000039409
	23	0.8654740331		0.000000000013353
	24	0.8654740331		-0.000000000004524
	25	0.8654740331		0.000000000001533
	26	0.8654740331		-0.000000000000519
	27	0.8654740331		0.000000000000176
	28	0.8654740331		-0.000000000000060
	29	0.8654740331		0.000000000000020
	30	0.8654740331		-0.000000000000007
	31	0.8654740331		0.000000000000002
	32	0.8654740331		0.00	-0.000000000000002