Indicate the alternative that shows the average reaction rate as a function of H2, given that for reaction 2 it was verified that in the interval o...
Indicate the alternative that shows the average reaction rate as a function of H2, given that for reaction 2 it was verified that in the interval of 100 s, the concentration of HI decreased from 4 x 10^-6 (mol/L) to 3.5 x 10^-6 (mol/L) and the concentration of H2 increased from 0 to 4.5 x 10^-6 (mol/L).
a. 2.5 x 10^-7 (mol/L.s)
b. 5.0 x 10^-7 (mol/L.s)
c. 7.5 x 10^-7 (mol/L.s)
d. 1.0 x 10^-6 (mol/L.s)
e. 2.0 x 10^-6 (mol/L.s)
a. 2.5 x 10^-7 (mol/L.s)
b. 5.0 x 10^-7 (mol/L.s)
c. 7.5 x 10^-7 (mol/L.s)
d. 1.0 x 10^-6 (mol/L.s)
e. 2.0 x 10^-6 (mol/L.s)
💡 1 Resposta
Ed 
Para calcular a taxa média de reação, é necessário utilizar a fórmula: Taxa média = variação da concentração / tempo Para a reação 2, temos: HI: 4,0 x 10^-6 mol/L -> 3,5 x 10^-6 mol/L Δ[HI] = 4,0 x 10^-6 mol/L - 3,5 x 10^-6 mol/L = 0,5 x 10^-6 mol/L H2: 0 mol/L -> 4,5 x 10^-6 mol/L Δ[H2] = 4,5 x 10^-6 mol/L - 0 mol/L = 4,5 x 10^-6 mol/L Tempo: 100 s Substituindo os valores na fórmula, temos: Taxa média = (0,5 x 10^-6 mol/L) / (100 s) = 5,0 x 10^-9 mol/(L.s) Portanto, a alternativa correta é a letra A) 2,5 x 10^-7 (mol/L.s).
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