Resolver em R as seguintes equações logarítmicas: 1) log -x2(6 5) = 2 2) log 2)12( xx 3) log log 4 log 2 (3x-6) = 0 4) (log x) 2 - log x – 2 = 0...

1) log -x²(6^5) = 2 -x²(6^5) = 10^2 -x² = 10^2/(6^5) x² = -10^2/(6^5) x = ±√(-10^2/(6^5)) 2) log2(12/(x+2)) = x 12/(x+2) = 2^x 12 = 2^x(x+2) 12 = 2^x * x + 2^(x+1) x ≈ 1,357 ou x ≈ -2,409 3) log(log4(log2(3x-6))) = 0 log4(log2(3x-6)) = 1 log2(3x-6) = 4^1 3x-6 = 2^4 3x-6 = 16 x = 22/3 4) (log x)² - log x - 2 = 0 Substituindo log x por y: y² - y - 2 = 0 (y-2)(y+1) = 0 y = 2 ou y = -1 log x = 2 ou log x = -1 x = 100 ou x = 0,1 5) log(3,5-x) + log(5+x)/log2 = 1 log[(3,5-x)(5+x)]/log2 = 1 (3,5-x)(5+x) = 2^1 17,5 - x² = 2 x² = 15,5 x = ±√15,5 6) 3^(2-x) = 16 2-x = log3(16) 2-x = log3(2^4) 2-x = 4log3(2) 2-x = 4(0,301) 2-x = 1,204 x = 0,796