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The hydrogen gas can be obtained by the following reaction: CH4 (g) + H2O (l)  CO (g) + 3 H2 (g). According to the following formation enthalpies,...

The hydrogen gas can be obtained by the following reaction: CH4 (g) + H2O (l)  CO (g) + 3 H2 (g). According to the following formation enthalpies, ΔfH(CH4) = - 75 KJ/mol, ΔfH(H2O) = - 287 KJ/mol and ΔfH(CO) = - 108 KJ/mol, the enthalpy of the reaction above at 25°C and 1 atm is equal to:


A. + 254 kJ
B. - 127 kJ
C. - 470 kJ
D. + 508 kJ
E. - 254 kJ

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Valige Joao Landeza

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Valige Joao Landeza

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Para calcular a entalpia da reação, é necessário somar as entalpias de formação dos produtos e subtrair as entalpias de formação dos reagentes. ΔH = ΣΔHf (produtos) - ΣΔHf (reagentes) Substituindo os valores dados na equação acima, temos: ΔH = [3 x ΔfH(H2)] + ΔfH(CO) - [ΔfH(CH4) + ΔfH(H2O)] ΔH = [3 x 0] + (-108) - [(-75) + (-287)] ΔH = -108 + 75 + 287 ΔH = +254 kJ Portanto, a alternativa correta é A) +254 kJ.

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