Vamos calcular a derivada de cada função: 1) f(x) = (x + 1)/(x - 1) f'(x) = [(x - 1)(1) - (x + 1)(1)]/(x - 1)^2 f'(x) = -2/(x - 1)^2 2) f(x) = (2x^3 + 1)^(3/2)/(x + 2) f'(x) = [(3/2)(2x^3 + 1)^(1/2)(6x^2)](x + 2) - (2x^3 + 1)^(3/2)(1)/(x + 2)^2 f'(x) = 12x^2(2x^3 + 1)^(1/2)/(x + 2)^3 - (2x^3 + 1)^(3/2)/(x + 2)^2 3) f(x) = 4x - x^4/(x^3 + 2)^100 f'(x) = 4 - [(3x^2)(x^4) - 4x^3]/(x^3 + 2)^101 f'(x) = (12x^2 - 4x^4)/(x^3 + 2)^101 4) f(x) = x sen(√(x^5 - x^2)) f'(x) = sen(√(x^5 - x^2)) + xcos(√(x^5 - x^2))(1/2)(5x^4 - 2x)/(2√(x^5 - x^2)) f'(x) = sen(√(x^5 - x^2)) + xcos(√(x^5 - x^2))(5x^4 - 2x)/(2(x^5 - x^2)^(1/2)) 5) f(x) = 3^(1/2)x^2cos(x)/(x^4 + tg^2(x) + 1)^2 f'(x) = [(2x)(3^(1/2)x^4 + 2x^2cos(x)(x^4 + tg^2(x) + 1)^2) - (3^(1/2)x^2cos(x))(4x^3 + 2xtg(x)(x^4 + tg^2(x) + 1))]/(x^4 + tg^2(x) + 1)^4/2 f'(x) = (6x^5cos(x) + 6x^3cos(x)tg^2(x) - 2x^3cos(x) + 6x^3tg(x) + 6x^2cos(x)tg(x)tg^2(x) - 2x^2cos(x)tg(x))/(x^4 + tg^2(x) + 1)^3/2 6) f(x) = 6^(1/2)x tg^2(x)/(√(x)) f'(x) = [(6^(1/2)tg^2(x))/(2√(x))] + [(6^(1/2)x)(2tg(x)(1/√(x)))]/(tg^4(x)) f'(x) = (3/(√(x)tg^2(x))) + (3√(x))/(tg^3(x)) 7) f(x) = √(x^2 + x^4) f'(x) = (2x^3 + 2x)/(2√(x^2 + x^4)) f'(x) = x(1 + x^2)^(1/2)/(x^2 + 1) Portanto, as alternativas corretas são: a) a, b, c, d, e, f, g, h, i, k.
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