Resolva a equação diferencial y ′′ − 2 y ′ = s e n ( 4 x ) com y ( 0 ) = 1 40 e y ′ ( 0 ) = 9 5 . y = 1 + e 2 x + 1 20 c o s 4 x − 1 20 s e...
Resolva a equação diferencial y ′′ − 2 y ′ = s e n ( 4 x ) com y ( 0 ) = 1 40 e y ′ ( 0 ) = 9 5 . y = 1 + e 2 x + 1 20 c o s 4 x − 1 20 s e n ( 4 x ) y = e 2 x − 1 + 1 40 c o s 4 x − 1 20 s e n ( 4 x ) y = 1 − e 2 x − 1 40 c o s 4 x − 1 20 s e n ( 4 x ) y = e 2 x − 1 + 1 20 c o s 4 x − 1 40 s e n ( 4 x ) y = 1 + e 2 x − 1 40 c o s 4 x + 1 20 s e n ( 4 x )
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