alguém sabe resolver? sen 0 + sen π/2 - sen 3π/2 y=____________________________ 2.sen π/6

Sen 0 = 0
sen (pi/2) = 1
sen (3pi/2) = - 1

sen(pi/6) = 1/2

y = (0 + 1 - 1)/[2(1/2)] = 0
y = 0