Resolva as equações em R.1) 2 x + 6 = x + 18 2) 5 x – 3 = 2 x + 9 3) 3 (2x-3) + 2 (x + 1) = 3x + 184) 2x + 3 (x – 5) = 4x + 95) 2 (x + 1) – 3 (2x –5)

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1 -

\[2x + 6 = x + 18\]

\[2x - x = 18 - 6\]

\[\boxed{x = 12}\]

2 -

\[5x - 3 = 2x + 9\]

\[5x - 2x = 9 + 3\]

\[3x = 12\]

\[x = \dfrac{{12}}{3} \to \boxed{x = 4}\]

3 -

\[3(2x - 3) + 2(x + 1) = 3x + 18\]

\[6x - 9 + 2x + 2 = 3x + 18\]

\[6x + 2x - 3x = 18 + 9 - 2\]

\[5x = 25\]

\[x = \dfrac{{25}}{5} \to x = 5\]

4 -

\[2x + 3(x - 5) = 4x + 9\]

\[2x + 3x - 15 = 4x + 9\]

\[5x - 4x = 9 + 15\]

\[x = 24\]

5 -

\[2(x + 1) - 3(2x - 5) = 6x - 3\]

\[2x + 2 - 6x + 15 = 6x - 3\]

\[- 4x + 17 = 6x - 3\]

\[- 6x - 4x = - 3 - 17\]

\[- 10x = - 20\]

\[x = 2\]

6 -

\[3x - 5 = x - 2\]

\[3x - x = - 2 + 5\]

\[2x = 3\]

\[x = \dfrac{3}{2}\]

7 -

\[3x - 5 = 13\]

\[3x = 13 + 5\]

\[x = \dfrac{{18}}{3} \to x = 6\]

8 -

\[3x + 5 = 2\]

\[3x = 2 - 5\]

\[x = \dfrac{{ - 3}}{3} \to x = - 1\]

9 -

\[x - (2x - 1) = 23\]

\[x - 2x + 1 = 23\]

\[- x = 23 - 1\]

\[x = - 22\]

10 -

\[2x - (x - 1) = 5 - (x - 3)\]

\[2x - x + 1 = 5 - x + 3\]

\[x + 1 = - x + 8\]

\[x + x = 8 - 1\]

\[2x = 7\]

\[x = \dfrac{7}{2}\]

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Portanto temos acima as resoluções das equações apresentadas no enunciado.

rsrs