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Josimery 5 problema

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PROBLEMA 5 
Modelo 
MIN 30X1 + 28X2 + 43X3 
ST 
Gasolina) 20X1 + 17X2 25X3 >= 200 
Óleo) 40X1 + 43X2 + 35X3 >= 280 
END 
 LP OPTIMUM FOUND AT STEP 2 
 OBJECTIVE FUNCTION VALUE 
 1) 300.0 000 
 VARIABLE VALUE REDUCED COST 
 X1 10.000000 0.000000 
 X2 0.000000 2.500000 
 X3 0.000000 5.500000 
 ROW SLACK OR SURPLUS DUAL PRICES 
 GASOLINA) 0.000000 -1.500000 
 ÓLEO) 120.000000 0.000000 
 NO. ITERATIONS= 2

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