Confiablidade 1 - motores - ok

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Planilha1
	Tempo decorrido(h)	nº motores s/ falha	nº motores s/ falha	falhas no intervalo	falhas acumuladas	f(t) =	h(t) =	F(t) =	R(t) =		Legenda
		no inicio do intervalo	no fim do intervalo			nf/n0.Dt	nf/ns.Dt	Snf/n0	Sns/n0		n0	Número inicial
		n0	ns	nf							nf	Número falhas intervalo
	0 - 100	1000	990	10	10	0.000100	0.000101	0.010	0.990		ns	Número sobrev. Intervalo
	100 - 200	990	981	9	19	0.000091	0.000092	0.019	9.810		Dt	Intervalo = 100
	200 - 300	981	974	7	26	0.000071	0.000072	0.026	9.740
	300 - 400	974	969	5	31	0.000051	0.000052	0.031	9.690
	400 - 500	969	964	5	36	0.000052	0.000052	0.036	9.640
	500 - 600	964	959	5	41	0.000052	0.000052	0.041	9.590
	600 - 700	959	954	5	46	0.000052	0.000052	0.046	9.540
	700 - 800	954	949	5	51	0.000052	0.000053	0.051	9.490
	800 - 900	949	944	5	56	0.000053	0.000053	0.056	9.440
	900 - 1000	944	939	5	61	0.000053	0.000053	0.061	9.390
f(t)
1E-4	9.0000000000000006E-5	6.9999999999999994E-5	5.0000000000000002E-5	5.0000000000000002E-5	5.0000000000000002E-5	5.0000000000000002E-5	5.0000000000000002E-5	5.0000000000000002E-5	5.0000000000000002E-5	y = 9E-05e-0,073x
R² = 0,6478
1E-4	9.0000000000000006E-5	6.9999999999999994E-5	5.0000000000000002E-5	5.00000000000	00002E-5	5.0000000000000002E-5	5.0000000000000002E-5	5.0000000000000002E-5	5.0000000000000002E-5	5.0000000000000002E-5	
h(t)
y = 9E-05e-0,067x
R² = 0,6133
1.0101010101010101E-4	9.1743119266055046E-5	7.1868583162217663E-5	5.1599587203302372E-5	5.1867219917012447E-5	5.213764337851929E-5	5.2410901467505238E-5	5.2687038988408854E-5	5.2966101694915253E-5	5.3248136315228964E-5	
R(t) 
y = 0,9924e-0,006x
R² = 0,9931
0.99	0.98099999999999998	0.97399999999999998	0.96899999999999997	0.96399999999999997	0.95899999999999996	0.95399999999999996	0.94899999999999995	0.94399999999999995	0.93899999999999995