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Disciplina: Eletrônica Digital
Professora: Priscila Doria
Nome do aluno:
Lista de Exercícios Nº 3
1. Simplifique as expressões abaixo, utilizando a Álgebra de Boole.
a. CBABCAABCCBACABS ++++=
Resposta: BCAS +=
b. ABCDDCBADABCDBCADCABDCBADCABS ++++++=
Resposta: DCABS +=
c. )(]))([( CABCBACCBADCBS ++++++++=
Resposta: BACS +=
d. ABCBADCCBADCBAS ++++++= ])()([
Resposta: ACADABDCS +++=
e. DABADCBDDCBBAS +++++⊕= ])()[(
Resposta: ABDCBADAS ++=
f. )]()())(([ BAACBCACBCBAACDDCBS +++++++++=
Resposta: ACBS +=
g. }])([){( ACBACBADCBADDCBAS ++++⊕++=
Resposta: DCAS =
h. }])()[(){( ABDDBCBDABCBACBBBAS +++++⊕++=
Resposta: DBBAS +=
i. ABCCBABCACBACBAS ++++=
Resposta: BAACBAS ++=
2
j. DCBAABCDDCBABCDADCABDCBACDBADCBAS +++++++=
Resposta: CBABCDDCADCBS +++=
k. CACDBADCBAADBS ++++=
Resposta: BAS +=
l. DCBADCBCDBDBCDAABABCS ++++++=
Resposta: CBBDACCBS +++=
2. Simplifique a expressão e desenhe o circuito que executa a expressão simplificada.
})]([){( DCBACBCBADCBDBS +++++⊗++=
3. Demonstre que:
)()( CBACBAS ⊗⊕=⊕⊗=
4. Prove que:
DCBADCBA ⊗⊗⊗=⊕⊕⊕
A B C D DCBA ⊕⊕⊕ DCBA ⊗⊗⊗
0 0 0 0 1 1
0 0 0 1 0 0
0 0 1 0 0 0
0 0 1 1 1 1
0 1 0 0 0 0
0 1 0 1 1 1
0 1 1 0 1 1
0 1 1 1 0 0
1 0 0 0 0 0
1 0 0 1 1 1
1 0 1 0 1 1
1 0 1 1 0 0
1 1 0 0 1 1
1 1 0 1 0 0
1 1 1 0 0 0
1 1 1 1 1 1
5. Simplifique as expressões da questão 1, utilizando o diagrama de Veitch-Karnaugh.
3
6. Através dos diagramas de Veitch-Karnaugh, determine a expressão simplificada de S1 e S2.
a. A B S1 S2
0 0 1 1
0 1 0 1
1 0 1 0
1 1 1 0
Respostas: BAS +=1 e AS =2
b. A B C S1 S2
0 0 0 X 1
0 0 1 0 X
0 1 0 1 0
0 1 1 X 0
1 0 0 1 0
1 0 1 X 1
1 1 0 X X
1 1 1 1 X
Respostas: BAS +=1 e ACBAS +=2
c. A B C D E S1 S2
0 0 0 0 0 1 1
0 0 0 0 1 1 0
0 0 0 1 0 1 1
0 0 0 1 1 1 0
0 0 1 0 0 0 1
0 0 1 0 1 1 1
0 0 1 1 0 0 1
0 0 1 1 1 1 1
0 1 0 0 0 0 1
0 1 0 0 1 0 0
0 1 0 1 0 1 1
0 1 0 1 1 0 0
0 1 1 0 0 1 1
0 1 1 0 1 1 1
0 1 1 1 0 0 1
0 1 1 1 1 1 1
1 0 0 0 0 1 1
1 0 0 0 1 1 0
1 0 0 1 0 0 1
1 0 0 1 1 0 1
1 0 1 0 0 0 1
1 0 1 0 1 1 1
1 0 1 1 0 0 1
1 0 1 1 1 1 1
1 1 0 0 0 0 1
1 1 0 0 1 0 0
1 1 0 1 0 1 1
1 1 0 1 1 0 0
1 1 1 0 0 0 1
1 1 1 0 1 1 1
1 1 1 1 0 0 1
1 1 1 1 1 1 1
Respostas:
DBAECS
EDCBDBCADCBCBACES
++=
++++=
2
1
d. A B C D E S1 S2
0 0 0 0 0 0 1
0 0 0 0 1 0 X
0 0 0 1 0 1 1
0 0 0 1 1 0 X
0 0 1 0 0 1 X
0 0 1 0 1 1 1
0 0 1 1 0 0 X
0 0 1 1 1 1 1
0 1 0 0 0 0 1
0 1 0 0 1 1 0
0 1 0 1 0 1 1
0 1 0 1 1 0 0
0 1 1 0 0 1 X
0 1 1 0 1 1 1
0 1 1 1 0 0 0
0 1 1 1 1 1 1
1 0 0 0 0 0 1
1 0 0 0 1 0 X
1 0 0 1 0 1 1
1 0 0 1 1 0 0
1 0 1 0 0 1 X
1 0 1 0 1 1 1
1 0 1 1 0 0 0
1 0 1 1 1 1 1
1 1 0 0 0 0 X
1 1 0 0 1 0 1
1 1 0 1 0 1 1
1 1 0 1 1 0 1
1 1 1 0 0 1 1
1 1 1 0 1 1 X
1 1 1 1 0 0 1
1 1 1 1 1 1 X
Respostas:
ECABS
EDCDCCES
⊗+=
++=
2
1
4
7. Simplifique as expressões de S1, S2, S3, S4, utilizando os mapas de Veitch-Karnaugh.
a. A B C D S1 S2 S3 S4
0 0 0 0 1 1 0 0
0 0 0 1 1 0 0 0
0 0 1 0 1 1 1 0
0 0 1 1 1 0 0 1
0 1 0 0 1 1 1 1
0 1 0 1 0 1 1 1
0 1 1 0 0 1 1 0
0 1 1 1 1 1 0 1
1 0 0 0 1 1 0 0
1 0 0 1 1 1 0 1
1 0 1 0 1 0 1 0
1 0 1 1 1 0 0 0
1 1 0 0 1 0 0 0
1 1 0 1 0 1 1 1
1 1 1 0 0 0 0 1
1 1 1 1 1 1 0 1
Respostas:
CDDCBS ++=1
CBABDDAS ++=2
DCBDCBDBAS ++=3
DCAABCCDACBAS +++=4
b.
Respostas:
DBS +=1
DBACBDS ++=2
CDBAABCCBADBS +++=3
ABCDADCBS +++=4
A B C D S1 S2 S3 S4
0 0 0 0 1 X 0 X
0 0 0 1 X X 0 0
0 0 1 0 X 1 0 X
0 0 1 1 X 0 1 1
0 1 0 0 1 X X 1
0 1 0 1 0 1 X X
0 1 1 0 X 0 1 0
0 1 1 1 X 1 0 1
1 0 0 0 X 1 X 0
1 0 0 1 1 0 1 1
1 0 1 0 X X 0 0
1 0 1 1 1 1 0 X
1 1 0 0 X 0 1 1
1 1 0 1 X 1 0 1
1 1 1 0 1 1 X 1
1 1 1 1 0 X 1 X
c. A B C S1 S2 S3 S4
0 0 0 1 1 0 0
0 0 1 0 1 1 1
0 1 0 1 1 0 1
0 1 1 1 0 0 0
1 0 0 1 1 1 1
1 0 1 1 1 1 0
1 1 0 0 1 1 1
1 1 1 1 0 0 1
Respostas:
BAACCBS ++=1
CBS +=2
CACBS +=3
CBABCACBAS +++=4