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Chapter 33, Problem 1P Problem Bounds for Products of Spin Operators (a) From the fact that the eigenstates of a Hermitian matrix form a complete orthononnal set, deduce that the largest (smallest) diagonal matrix element a Hermitian operator can have is equal to its largest (smallest) eigenvalue. (b) Prove that the largest diagonal matrix element S(R) S(R') can have when R # R' is S2. (Hint: Write the operator in terms of the square of S(R) + S(R').) (c) Prove that the smallest diagonal matrix element S(R) S(R') can have is -S(S + 1). Step-by-step solution There is no solution to this problem yet. Get help from a Chegg subject expert. Ask an expert

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